A ball is initially at rest and travels 7.8 m. The ball travels at an acceleration of 6.4 m/s². What is the final velocity of the ball? Give your answer to 1 decimal place.​

A chemical process known as hydrogen displacement occurs when hydrogen gas is replaced or displaced by another element or molecule.

It results from a number of reactions, most of which involve a reactive metal or substance. A metal reacting with an acid can displace hydrogen atoms of the acid, resulting in the formation of a salt and the release of hydrogen gas as an example.

Another example is the interaction of a metal with water molecules, which displaces hydrogen atoms and results in the formation of metal hydroxide and hydrogen gas. Chemistry studies hydrogen displacement reactions in great detail because they are important for understanding the reactivity of various compounds. They shed light on the behavior of elements, how well they can replace hydrogen, and how new compounds are formed.

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The pressure exerted on the fluid by the force applied on the small piston can be calculated using the formula:

P = F/A

where P is the pressure, F is the force, and A is the area on which the force is applied. Since the force is applied on the smaller piston, we need to use its area:

A_small = πr_small^2

where r_small is the radius of the smaller piston. Thus,

A_small = π(0.02 m)^2 = 1.2566 x 10^-3 m^2

The force applied on the small piston is 250 N. Thus,

P = F/A_small = 250 N / 1.2566 x 10^-3 m^2 = 1.989 x 10^5 Pa

Therefore, the increase in pressure caused by the 250 N force on the small piston is 1.989 x 10^5 Pa, which is approximately equal to 2 x 10^5 Pa (to two significant figures).

b) We can use the principle of conservation of volume to determine how far the smaller piston moves when the larger piston moves 5 cm. The volume of the fluid in the hydraulic lift remains constant, so we have:

A_small × h_small = A_large × h_large

where h_small and h_large are the heights of the fluid columns above the smaller and larger pistons, respectively. Since the lift is filled with an incompressible fluid, the pressure is the same throughout the fluid. Thus,

P = F/A_small = F/A_large

Multiplying both sides of this equation by the areas of the pistons, we get:

F × A_small = F × A_large

Substituting the given values, we get:

250 N × (π(0.02 m)^2) = F × (π(0.20 m)^2)

Solving for F, we get:

F = 250 N × (0.02 m/0.20 m)^2 = 25 N

Now, we can use the force applied on the larger piston and the area of the smaller piston to calculate the force on the smaller piston:

F_small = F × (A_small/A_large) = 25 N × (1.2566 x 10^-3 m^2 / (π(0.20 m)^2)) = 0.1989 N

Using the formula for pressure, we can calculate the height of the fluid column above the smaller piston:

P = F_small/A_small = h_small × ρ × g

where ρ is the density of the fluid and g is the acceleration due to gravity. Since the density of the fluid and the acceleration due to gravity are constants, we can simplify this equation to:

h_small = F_small/(A_small × ρ × g)

Substituting the given values, we get:

h_small = 0.1989 N / (1.2566 x 10^-3 m^2 × 1000 kg/m^3 × 9.81 m/s^2) = 0.0159 m

Therefore, the smaller piston moves 0.0159 m (or approximately 1.6 cm) when the larger piston moves 5 cm.

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The steps assume that the mirrors and boxes are arranged in a simple, two-dimensional configuration.

The steps to be followed are;

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The magnitude of the acceleration of the ball  applied at the bottom of the circle can be expressed in the form  of FTension-FGravity/M.

Option D is correct.

Along the string's circular and vertical paths, the tension changes. As long as the total quantity of kinetic and potential energy is constant throughout, the ball's speed can change.

Centripetal force varies as a result of motion variations.

We can determine how tight a string that is traveling in a vertical circle is using the expression below:

FC = mv2 /r.

A moving item attached to a string experiences centripetal force, which is determined by the product of the object's mass (mg) and the string tension. (T).

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Complete question:  

A student swings ball of mass M on the end of a string in vertical circle of radius R,as shown in the figure below. Also shown is diagram representing all the forces exerted on the ball at the bottom of the circle where its speed is What is the magnitude of the acceleration of the ball at the bottom of the circle? FTension FGravity

A)Fi /M

B)Fc /M

C)Fr+Fg/M

D) Ft- Fg/M

The proportionality constant of the moving object experiencing a drag force is 0.01875 Ns²/m².

The work-energy principle states that the work done on an object is equal to its change in kinetic energy. So, the work done by the drag force can be found as follows:

W = (1/8)mv² - (1/2)mv₀²

where m = mass of the object, v = final speed, and v₀ = initial speed.

The work done by the drag force is also given by the formula:

W = ∫F(x)dx

where F(x) = force function and x = position of the object.

In this case, the force function is F(x) = -Cv², since the drag force is in the opposite direction of motion. So:

W = ∫-Cv²dx

Since the force is proportional to v², rewrite this as:

W = -C∫v²dx

Integrating both sides with respect to x:

W = -(1/3)Cv³

So, equating the two expressions for W:

(1/8)mv² - (1/2)mv₀² = -(1/3)Cv³

Substituting m = 0.01 kg, v₀ = 10 m/s, and solving for C:

C = -(3/8) × (m/v₀³) × (v² - v₀²) = -(3/8) × (0.01/10³) × (1/8 × 10² - 10²) = 0.01875 Ns²/m²

Therefore, the proportionality constant is C = 0.01875 Ns²/m².

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Answer :

Step-by-step explanation:

We are given with 4 resistors which are connected in parallel.

Let

R_1 =10Ω

R_2 = 12Ω

R_3 = 15Ω

R_4 = 20 Ω

First let's calculate the total resistance.

Since the resistors are connected in parallel, Total resistance will be,

[tex]{\boxed{ \implies {\sf {\dfrac{1}{R_{(total)} }= \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + \dfrac{1}{R_4}}}}} \\ [/tex]

Plugging in the required values,

[tex]\implies \sf \dfrac{1}{R_{(total)}} = \dfrac{1}{10} + \dfrac{1}{12} + \dfrac{1}{15} + \dfrac{1}{20} \\ \\\implies \sf \dfrac{1}{R_{(total)}} = \dfrac{6 + 5 + 4 + 3}{60} \\ \\ \implies \sf \dfrac{1}{R_{(total)}} = \frac{18}{60} \\ \\ \implies \sf R_{(total)} = \frac{60}{18} \\ \\ \implies \sf R_{(total)} = 3.33 [/tex]

Hence, The total resistance is 3.33 Ω

Now,

[tex] \implies \sf I = \dfrac{V}{R}[/tex]

Where,

Plugging the required values

[tex] \implies[/tex] I = 25/3.33

[tex] \implies[/tex] I = 7.5 A

Therefore, The total current in the circuit is 7.5 A

Answer:10.2

Explanation:

Answer:

W = 6000 Joule

Explanation:

Work is defined as force times distance

W = F * d

We know that F = 15N, we just need the distance (d)

Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.

The width of the mower is only 50 cm = 0.5 m.

This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,

d = 10 (meter) * 40 (times) = 400 meter

Therefore:

W = (15) * (400) = 6000 J

The use of the wheel barrow in this case makes it a simple machine

A wheelbarrow is an illustration of a straightforward device that can simplify labour by lowering the force needed to move a large load. The wheel and axle and the lever are two basic machines that are used.

The wheelbarrow's wheel is made of an axle and wheel. The friction between the wheel and the ground is decreased by the wheel's rotation around the axle. It can also be seen as one of the classes of the lever.

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Answer:

Car

Explanation:

Based on Newton 2nd law, energy are conserves. Meaning that if the Force is equal, the car with lower mass must be travelling in a much greater acceleration.

F = m.a

where,

a = Δv/Δt

When talking about energy, there are 2 factor: mass and velocity.

The change of Kinetic energy experience by the car is

ΔEk = 1/2.m.Δv²

Eventhough the car has smaller mass, notice that the velocity will be squared. In this case the velocity is the a more dominant factor. It means that energy absorbed by the car is much larger.

Here's the circuit diagram:

```

   +---R₁---R₂---+

   |             |

   -             -

  (6V)          ( )

                 |

                 |

                 |

                 |

                 |

                 |

                 |

                ( )

                -

```

Calculations:

1. The total resistance of the two resistors:

  R_total = R₁ + R₂

          = 12 ohm + 24 ohm

          = 36 ohm

  Answer: 36 ohm

2. The total current flowing in the circuit:

  I = V / R_total

    = 6.0 V / 36 ohm

    = 0.167 A

  Answer: 0.167 A

3. The current flowing in R₁:

  I₁ = V / R₁

     = 6.0 V / 12 ohm

     = 0.5 A

  Answer: 0.5 A

4. The current flowing in R₂:

  I₂ = V / R₂

     = 6.0 V / 24 ohm

     = 0.25 A

  Answer: 0.25 A

5. The total power consumed by R₁ and R₂:

  P = I² * R_total

    = (I₁ + I₂)² * R_total

    = (0.5 A + 0.25 A)² * 36 ohm

    = 0.1875 * 36 ohm

    = 6.75 W

  Answer: 6.75 W

In Experiment 6.1, two entangled atoms are delivered to several Stern-Gerlach analyzers where the spins are detected in various orientations. Each atom's measurement result is probabilistic and arbitrary. Because there is no way to influence how the measurement on the distant atom turns out, it is impossible to use this process to convey a message instantly.

A fundamental area of physics called quantum mechanics examines how matter and energy behave at the atomic and subatomic scales. The behavior of particles like electrons, protons, and photons as well as their interactions are understood and described mathematically.

The idea of entanglement, which describes how two or more particles can come to be connected in such a way that their states are correlated even though they are separated by a considerable distance, is also introduced by quantum mechanics.

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Answer: 3 meters from the ground

Explanation:

gravitational potential energy= mass*height*acceleration of free fall(g)

150=5*h*10

h=150/50

h= 3 m

Answer:

.04 kg

Explanation:

The equation for simple harmonic motion is x = A*cos(ωt), where A is the amplitude, ω is the angular frequency, and t is the time.

Comparing the given equation x = 2.0cos(50t) with the equation for simple harmonic motion, we see that A = 2.0 meters and ω = 50 radians/second.

The angular frequency is related to the spring constant and mass by the equation ω = sqrt(k/m), where sqrt denotes the square root.

Substituting the values given, we get:

50 = sqrt(100/m)

Squaring both sides and solving for m, we get:

m = 100/2500 = 0.04 kg

The mass to be hung at a point 40cm to the right of the pivot point such that the stick hangs level is 15 g.

To solve this problem, use the principle of moments which states that the sum of the clockwise moments about a pivot point is equal to the sum of the counterclockwise moments about the same pivot point. In this case, take the pivot point to be the suspension point of the meter stick.

Let x be the mass that needs to hang at a point 40cm to the right of the pivot point. Then, set up the following equation:

(clockwise moment) = (counterclockwise moment)

(0.2 kg) × (0.3 m) × (9.81 m/s²) = (x kg) × (0.4 m) × (9.81 m/s²) + (0.1 kg) × (0.1 m) × (9.81 m/s²)

Simplifying this equation:

0.05886 = 3.924x

x = 0.015 kg or 15 g

Therefore, we need to hang a 15 g mass at a point 40 cm to the right of the pivot point such that the stick hangs level.

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Answer:

The velocity of the center of mass (Vcm) of a system of particles can be calculated using the formula:

Vcm = (m1v1 + m2v2 + m3v3 + ... + mnvn) / (m1 + m2 + m3 + ... + mn)

where m1, m2, m3, ... mn are the masses of the particles and v1, v2, v3, ... vn are their velocities.

In this problem, we have three particles with masses of 20g, 30g, and 50g and velocities of 2i, 10j, and 10k respectively. We can convert the masses to kg to make the calculations easier:

m1 = 20g = 0.02kg

m2 = 30g = 0.03kg

m3 = 50g = 0.05kg

Using the formula above, we can calculate the velocity of the center of mass:

Vcm = (m1v1 + m2v2 + m3v3) / (m1 + m2 + m3)

Vcm = (0.02kg * 2i + 0.03kg * 10j + 0.05kg * 10k) / (0.02kg + 0.03kg + 0.05kg)

Vcm = (0.04i + 0.3j + 0.5k) / 0.1kg

Vcm = 0.4i + 3j + 5k m/s

Therefore, the velocity of the center of mass of the three particles is 0.4i + 3j + 5k m/s.

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Answer:

C. 110 kgm/s

Explanation:

Law of Conservation of Momentum states that total momentum before the collision must equal total momentum after the collision.

Momentum = p = mv

x = final velocity of the blue train

(50 kg)(4 m/s) + (30 kg)(0 m/s) = (50 kg)(x) + (30 kg)( 3 m/s)

200 kg·m/s + 0 = (50 kg)(x) + 90 kg·m/s

50 kg(x) = 110 kg·m/s

x = (110 kg·m/s)/(50 kg) = 2.2 m/s

p-final (blue train) = (50 kg)(2.2 m/s) = 110 kg·m/s

Answer:

According to the law of conservation of momentum, the total momentum of the system before and after the interaction must be equal.

The total initial momentum of the system is:

P_initial = 50 * 4 + 30* 0 = 200kgm/s

The total final momentum of the system

let the velocity of the blue train is=v

P_final = 30* 3 + 50* v = 200

after solving v=2.2m/sec

the momentum of blue train will be= 50* 2.2=110kgm/s

The Kinetic energy of the car with a mass of 80 grams is 0.40 joules

From the graph given, we can see that the as the mass increase, the kinetic energy also increase. Thus, we can say that the kinetic energy and mass of the car are in direct proportionality.

Now, we shall obtain the velocity of the car. Details below:

KE = ½mv²

0.1 = ½ × 0.02 × v²

0.1 = 0.01 × v²

Divide both side by 0.01

v² = 0.1 / 0.01

Take the square root of both side

v = √(0.1 / 0.01)

v = 3.16 m/s

Finally, we shall determine the kinetic energy of the car of mass 80 grams. Details below:

KE = ½mv²

KE = ½ × 0.08 × 3.16²

Kinetic energy = 0.40 joules

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