A 60 kg cyclist approaches the bottom of a gradual hill at a speed of 11 m/s. The hill is 5.0 m high, and the cyclist estimates that she is going fast enough to coast up and over it without peddling. Using conservation of energy, find the speed of the cyclist when she reaches the top of the hill (ignoring air resistance and friction). g

Answers

Answer 1

Answer:

9.91m/s

Explanation:

According to conservation of energy, the potential energy at the top of the hill is equal to the kinetic energy along the hill.

PE = KE

mgh = 1/2mv²

m is the mass of the cyclist

g is the acceleration due to gravity

h is the height of the hill

v is the speed of the cyclist

From the formula:

gh = v²/2

Given

g = 9.81m/s²

h = 5.0m

Substitute into the formula:

9.81(5.0) =  v²/2

9.81*5*2 =  v²

98.1 =  v²

v = √98.1

v = 9.91m/s

Hence the speed of the cyclist when she reaches the top of the hill is 9.91m/s


Related Questions

Two sailors, Popped-Eye and Mack Sparrow, are using identical pulleys to lift sunken treasure to their ship. Popped-Eye's treasure is three times heavier than Mack Sparrow's. Each sailor lifts his treasure an identical distance. Popped-Eye lifts his treasure the entire distance in 30s. Mack Sparrow requires twice as much time.
Which statement below is true regarding Popped-Eye's and Mack Sparrow's relative power?
A) Their power is equal.
B) Popped-Eye is 3 times more powerful than Mack Sparrow.
C) Popped-Eye is 6 times more powerful than Mack Sparrow.
D) Popped-Eye is 1.5 times more powerful than Mack Sparrow.

Answers

Answer:

Popped-Eye is 3 times more powerful than Mack Sparrow.

Explanation:

Popped-Eye is 6 times more powerful than Mack Sparrow.

What is power?

In science and engineering, power is the rate at which work is completed or energy is delivered. It can be expressed as the product of the work completed (W) or the energy transferred (E) divided by the time interval (t), or W/t.

Given parameters:

Popped-Eye's treasure is three times heavier than Mack Sparrow's.

Mack Sparrow requires twice as much time.

So, Popped-Eye can lift  times heavier treasure  in half of time compere to Mack Sparrow .

Hence, Popped-Eye's power is 3÷(1/2) = 3×2 = 6 times more than Mack Sparrow's.

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A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.34 x 104 rad/s to an angular speed of 4.37 x 104 rad/s. In the process, the bit turns through 3.10 x 104 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 7.43 x 104 rad/s, starting from rest?

Answers

Answer:

2.66 s

Explanation:

Given The initial angular speed ([tex]\omega_o[/tex]) =  1.34 x 10⁴ rad/s, the final angular speed (ω) = 4.37 x 10⁴ rad/s, the angular acceleration (α), distance (θ) = 3.10 x 10⁴ rad.

Using the formula:

[tex]\omega^2=\omega_o^2+2\alpha \theta\\\\Substituting:\\(4.37*10^4)^2=(1.34*10^4)^2+2(3.1*10^4)\alpha\\\\(4.37*10^4)^2-(1.34*10^4)^2=2(3.1*10^4)\alpha\\\\2(3.1*10^4)\alpha=1.73*10^9\\\\\alpha=2.79*10^4\ rad/s^2[/tex]

The constant acceleration = 2.79 * 10⁴ rad/s.

Since there is constant acceleration, to reach a final speed of  7.43 x 10⁴ rad/s, we use the formula:

[tex]\omega =\omega_o +\alpha t\\\\\omega_o=0,\omega=7.43*10^4\ rad/s,\alpha=2.79*10^4\ rad/s^2\\\\Substituting:\\\\7.43*10^4=0+2.79*10^4t\\\\7.43*10^4=2.79*10^4t\\\\t=2.66\ s[/tex]

How fast would a 4.75 cm copper bar have to move at right angles to a 0.700 T magnetic field to generate 1.50 V (the same as a AA battery) across its ends

Answers

Answer:

ω = 1899.5 radian / s

Explanation:

EMF induced by a rotating rod = 1 /2 B ω L² where ω is angular velocity of rod and L is its length . B is magnetic field

1 /2 B ω L² = 1.5

1/2 x .7 x ω x .0475² = 1.5

ω = 1899.5 radian / s

You throw a ball downward from a window at a speed of 1.7 m/s. How fast will it be moving when it hits the sidewalk 2.5 m below?

Answers

Answer:

7.43m/s

Explanation:

Given parameters:

Initial velocity = 1.7m/s

Height  = 2.5m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply one of the motion equation. The most fitting one given the parameters is;

           V²  = U² + 2gh

where V is the final velocity

           U is the initial velocity

          g is the acceleration due to gravity = 9.8m/s

           h is the height

Input the parameters and solve;

    V² = 2.5² + 2(9.8)(2.5)

    V = 7.43m/s

A person in a grocery store is standing carrying a big sack of rice (that has a mass of 10 kg) on the top of his head. Where is his CG located relative to his original CG (i.e when he is standing without the sack of rice on his head)
a) Higher than his original CG
b) Lower than his original CG
c) At the same point as his original CG
d) Insufficient information

Answers

Answer:

The CG is located higher than his original CG.

Explanation:

Centre of gravity (CG), in physics, an imaginary point in a body of matter where, for convenience in certain calculations, the total weight of the body may be thought to be concentrated. In a uniform gravitational field the centre of gravity is identical to the centre of mass, a term preferred by physicists.

 His CG is located higher than his original CG when he is standing without the sack of rice on his head.

A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. A system is in unstable equilibrium if, when displaced, it experiences a net force or torque in the same direction as the displacement from equilibrium. A system is in neutral equilibrium if its equilibrium is independent of displacements from its original position. A marble on a flat horizontal surface is an example.

A nearby highway is being designed for traffic whose speed limit is 90km/h. If most people become uncomfortable on banked curve larger than 45 degrees, what is the minimum radius you could design the curve

Answers

Answer:

The minimum radius of the curve is 6125 m

Explanation:

Given;

speed limit of the highway, V = 90 km/h = 25 m/s

banking angle, θ = 45°

The minimum radius of the curve will be calculated by applying banking angle formula;

[tex]mg tan \theta = F_{centripetal \ force}\\\\mg tan \theta = \frac{mv^2}{r}\\\\ g tan \theta = \frac{v^2}{r}\\\\r = \frac{v^2}{ g tan \theta}\\\\r = \frac{(25)^2}{(9.8)(1)} \\\\r = 6125 \ m[/tex]

Therefore, the minimum radius of the curve is 6125 m

An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of the spring is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at 1.4 m/s2, what is the mass of the object?

Answers

Answer:

Approximately [tex]28.3\; \rm kg[/tex], assuming that the spring was pulled horizontally.

Explanation:

Let [tex]k[/tex] denote the spring constant of this spring. Calculate the size of tension in this spring that corresponds to the [tex]\Delta x = 0.88\; \rm m[/tex] stretch:

[tex]F(\text{tension}) = k\cdot \Delta x = 45\; \rm N \cdot m^{-1} \times 0.88\; \rm m = 39.6\; \rm N[/tex].

(The negative sign is ignored.)

If the spring is pulled horizontally, then the tension that the spring exerts would be the only unbalanced force on this object. The net force n this object would be equal to the tension that the spring had exerted: [tex]39.6\; \rm N[/tex].

Newton's Second Law of motion suggests the following relation between the net force [tex]\sum F[/tex] on the object, the mass [tex]m[/tex] of the object, and the acceleration [tex]a[/tex] of the object:

[tex]\sum F = m \cdot a[/tex].

For this object, [tex]a = 1.4\; \rm m \cdot s^{-2}[/tex]. It has been found that the net force on this object is [tex]\sum F = 39.6\; \rm N[/tex]. Rearrange the original equation [tex]\sum F = m \cdot a[/tex] and solve for [tex]m[/tex], the mass of this object:

[tex]\displaystyle m = \frac{\sum F}{a} = \frac{39.6\; \rm N}{1.4\; \rm m \cdot s^{-2}} \approx 28.3\; \rm kg[/tex].

In other words (based on all these assumptions,) the mass of this object should be approximately [tex]28.3\; \rm kg[/tex].

A current of 6.67 A in a solenoid of length 13.6 cm creates a 0.373 T magnetic field at the center of the solenoid. How many turns does this solenoid contain?

Answers

Answer:

The value is  [tex]N = 6051 \ turns[/tex]

Explanation:

From the question we are told that

   The current is  [tex]I = 6.67 \ A[/tex]

  The length is  [tex]l = 13.6 \ cm = 0.136 \ m[/tex]

  The magnetic field is  [tex]B = 0.373 \ T[/tex]

Gnerally the number of turn per unit length is mathematically represented as

      [tex]n = \frac{B}{\mu_o * I}[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4*\pi*10^{-7}[/tex]

So

=>    [tex]n = \frac{0.373}{ 4\pi * 10^{-7} * 6.67 }[/tex]

=>    [tex]n = 44496 \ turns /m[/tex]

Generally the number of turn is mathematically represented as

       [tex]N = n * l[/tex]

=>  [tex]N = 44496 * 0.136[/tex]

=>  [tex]N = 6051 \ turns[/tex]

The no of turns dos this solenoid contains will be 6051 turns.

What is a solenoid?

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .

The given data in the problem is;

B is the current =6.67 A

L is the length =13.6 cm=0.136 m

B is the magnetic field =0.373 T  

The number of turns per unit length is found as;

[tex]\rm n= \frac{B}{\mu_0I} \\\\ \rm n= \frac{0.373}{4 \times 3.14 \times 10^{-7}\times 6.67} \\\\ \rm n = 44496 \ turn /m[/tex]

The number of turns is found as;

[tex]\rm N=n\times l \\\\ \rm N=44496\times 0.136 \\\\ \rm N=6051 \ turns[/tex]

Hence the no of turns dos this solenoid contains will be 6051 turns.

To learn more about the solenoid refer to the link ;

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gas is escaping from a sperical ballom 4 cm3 per minute .how fast is the surface area shrinking when radius is 24cm

Answers

Answer:

dS/dt = 0.33 cm²/min

Explanation:

Volume of sphere is given by;

V = (4/3)πr³

We are told that gas is escaping from a spherical balloon 4 cm³ per minute. Thus; dV/dt = 4 cm³/min

Now, let's find the rate at which the radius is changing.

dr/dt = (dV/dt) ÷ (dV/dr)

Now, dV/dr = 4πr²

Thus;

dr/dt = 4/(4πr²)

dr/dt = 1/(πr²)

Now, surface area of sphere is given by;

S = 4πr²

Thus, dS/dr = 8πr

Now, let's find the rate at t which area is shrinking.

dS/dt = (dS/dr) × (dr/dt)

Plugging relevant terms, we have;

dS/dt = 8πr × 1/(πr²)

dS/dt = 8/r

At r = 24 cm, we have;

dS/dt = 8/24

dS/dt = 1/3

dS/dt = 0.33 cm²/min

A force of 1.46 N pushes against an object with a mass of 0.10 kg for 3.00 min. The object does not move. What is the work done on the object by the force

Answers

Answer:

0 J

Explanation:

Given data

force F=1.46N

mass m=0.1kg

time t= 3min

distance= 0 meters----"the object did not move"

We know that work-done is given as

work= Force * distance moved

Work= 1.46*0

work =0joules

We understand that when this is no distance move, then there is no work done, for work to be done, the object must move through a distance

Which of the following statements is true?

Anemia can be avoided by eating a diet rich in calcium.
CAT scans use powerful magnets and radio signals to view the inside of the body.
X-rays are only useful for viewing broken bones.
Exercise can reduce pain, relieve stress, and increase energy.

Answers

Answer:

c

Explanation:

Answer:

Exercise can reduce pain, relieve stress, and increase energy.Explanation:

What is the answer to this question?

Answers

Answer:

C I just did it. so yeah....

Strictly based upon physical characteristics I think

Carmen is helping load furniture and boxes onto a moving truck. She picks up boxes of her things, places them on a cart, and pushes the cart to the moving van. Which term best describes the type of force Carmen uses?
A. contact
B. friction
C. gravity (this one is wrong)
D. noncontact(this one is wrong)

Answers

A. Contact
Their you go!

What is the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope

Answers

Answer:

Explanation:

We have that the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

From the question we are told

Mountain goats can easily scale slopes angled at 60∘ from horizontal.  What is the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope?

Generally the equation for the normal force acting on a mountain goat   is mathematically given as

N=mgcos

N=550*cos60

N=275N

Therefore

The normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is

N=275N

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The gravitational potential energy of a 88 kg person in a building that is 385 m tall is 332,024 J. The person then jogs up the stairs, an additional distance of 100 meters.

How would the potential energy of the person be affected?
A) There would be no change.
B) The potential energy would double.
C) The potential energy would increase almost 25%
D) The potential energy would decrease more than 50%.

Answers

Answer:

Part C

Explanation:

The potential energy would increase almost 25%

Which of the following equipment is related to fencing?
A.
Sabre
B.
Bib
C.
Épée
D.
All of the above

Answers

This answer is
D. All if the above

why is the unit of power called derived unit​

Answers

Answer:The ampere is unique in that it uses the base unit of time (t) in its definition (second). All other electrical and magnetic units (such as voltage, power, and magnetic flux) use various combinations of base units in their definitions and are called derived units.

Explanation:

The maximum energy a bone can absorb without breaking is surprisingly small. For a healthy human of mass 59 kg , experimental data show that the leg bones can absorb about 200 J . Part A From what maximum height could a person jump and land rigidly upright on both feet without breaking his legs

Answers

Answer:

0.35m

Explanation:

In this problem we want to solve for the height given the potential energy

the potential energy is the energy possessed  by a body by virtual of it position.

given data

mass m=59kg

PE(potential energy)= 200J

Height h=?

assuming g=9.81,/s^2

we know that the expression for potential energy is

PE=mgh

substituting we have

200=59*9.81*h

200=578.79h

divide both sides by 578.79

h=200/578.79

h=0.35m

Therefore the height is 0.35m

You are originally 1.0 m beneath the surface of a pool. If you dive to 2.0 m beneath the surface, what happens to the absolute pressure on you

Answers

Answer:

The absolute pressure on me increases to 130,900 Pa.

Explanation:

Since I dive to a depth of 2.0 m, there is a depth change of 2.0 m which will cause a corresponding pressure change. The pressure change is thus ΔP = ρgΔh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8m/s² and Δh = depth change = 2.0 m

ΔP = ρgΔh  =  1000 kg/m³ × 9.8m/s² × 2.0 m = 19,600 Pa.

Since the absolute pressure P at 1.0 m is the pressure due to atmosphere plus the pressure of 1.0 m of water, we have

P = P₀ + ρgΔh' where P₀ = atmospheric pressure = 101,500 Pa and Δh' = 1.0 m

P = 101,500 Pa + 1000 kg/m³ × 9.8m/s² × 1.0 m = 101,500 Pa + 9800 Pa = 111,300 Pa

So, the absolute pressure at 2.0 m is P' = P + ΔP = 111,300 Pa + 19,600 Pa = 130,900 Pa.

So the absolute pressure on me increases to 130,900 Pa.

"The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

Answers

Answer:

2 : 1

Explanation:

Given that The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

Since the magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. And

Weight W = mg

Mass is always constant

2g : g

The ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B will be:

2 : 1

Which would increase the speed of a sound wave?
O A wave passes from a solid to a liquid while remaining the same temperature.
O The medium increases in temperature while remaining in the same phase.
O The medium decreases in temperature while remaining in the same phase.
O A wave passes from a liquid to a gas while remaining the same temperature.
(First correct answer with explanation gets Brainliest)​

Answers

Answer:

B. The medium increases in temperature while remaining in the same phase.

Explanation: The most important factor influencing the speed of sound in air is temperature. The speed is proportional to the square root of the absolute temperature, giving an increase. Due to this information, B is the best answer.

What is the answer to this question?

Answers

Answer:

c

Explanation:

Answer:

b

Explanation:

What happens when the forces applied to an object at rest produce a net force of zero?

1.The object will not move at all.

2.The object will have positive acceleration.


3.The object will change its direction of motion.

Answers

Answer:

1. The object will not move at all.

Explanation:

The question above is related to "Newton's First Law of Motion." According to this law, an object that is at rest will remain in its position (at rest) unless acted upon by "unbalanced forces." If the forces applied to an object are balanced, the net force is zero. This means that the object will not move nor accelerate.

The law also mentioned that if the object is in motion, it will remain in same velocity (speed with direction) if there's no net force.

The first stage of a Saturn V space vehicle consumed fuel and oxidizer at the rate of 1.50 3 104 kg/s with an exhaust speed of 2.60 3 103 m/s. (a) Calculate the thrust produced by this engine. (b) Find the acceleration the vehicle had just as it lifted off the launch

Answers

Answer:

Explanation:

Thrust produced = v dm / dt

v is speed of exhaust and dm / dt is rate at which mass of gas is being thrown out .

= 2.603 x 10³ x 1.503 x 10⁴

= 3.91 x 10⁷ N  ,

which of the following statements about mass and weight is correct?
A. "Mass" is the scientific term for "weight''
B. Weight directly measures force while mass directly measures amount of matter.
C. Weight has unit of kilograms or grams. Mass has unit of newtons.
D. The mass of an object depends on the size of the object. The weight of an object dosent depend on the size of the object.

Answers

The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.

Explanation:

Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.

A space vehicle is traveling at 4140 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The relative speed between the motor and the command module is then 99 km/h. The mass of the motor is four times the mass of the module. What is the speed of the command module relative to Earth just after the separation

Answers

Answer:

V_ce = 1128 m/s

Explanation:

We are given;

Speed of space vehicle relative to the earth; V_i = 4140 km/h = 1150 m/s

relative speed between the motor and the command module; V_mc = 99 km/h = 27.5 m/s

mass of the motor is four times the mass of the module.

If the mass of the module is m

Mass of motor = 4m

From conservation of momentum, since the system is isolated, then;

Initial momentum = final momentum.

Thus;

MV_i = 4m(V_me) + m(V_ce) - - - (eq 1)

Where;

M is mass of space vehicle

V_me is speed of motor relative to the earth

V_ce is speed of command module relative to the earth

Now, relative speed between the motor and the command module is given by the formula;

V_mc = V_me - V_ce

Thus, V_me = V_mc + V_ce

Putting (V_mc + V_ce) for V_me in eq 1, we have;

MV_i = 4m(V_mc + V_ce) + m(V_ce)

Now, the mass of the space vehicle will be the sum of the mass of the module and mass of the motor.

Thus;

M = m + 4m

M = 5m

Thus;

5mV_i = 4m(V_mc + V_ce) + m(V_ce)

Divide through by m to get;

5V_i = 4(V_mc + V_ce) + (V_ce)

5V_i = 4V_mc + 4V_ce + V_ce

5V_i = 4V_mc + 5V_ce

We want to find the speed of the command module relative to Earth just after the separation. Thus, let's make V_ce the subject;

V_ce = (5V_i - 4V_mc)/5

V_ce = ((5 × 1150) - (4 × 27.5))/5

V_ce = 1128 m/s

two forces act on a 6 kg object. one of the forces is 10 N. if the object accelerates at 2 m/s^2, what is the greatest possible magnitude of the other force

Answers

Answer:

22N

Explanation:

Let the two forces be acting in the horizontal direction on the object.

Given

Mass m = 6kg

One of the force = 10N

acceleration = 2m/s²

Taking the sum of forces along the x component, we will have:

[tex]\sum F_x = ma_x\\Ff - 10 = 6(2)\\Ff - 10 = 12\\Ff = 12+10\\Ff = 22N[/tex]

Note that Ff is the greatest possible magnitude of the other force.

Hence the greatest possible magnitude of the other force is 22N

Which picture shows an example of no work being done?

Answers

B, Its the one with the kid trying to lift a weight.

Explanation:

Got it right Edge 2020.

Answer:

it's the weights kid!!! the other user got it thank them, i got it right bc of them :)

Explanation:

Photons with the lowest energy have the lowest
A. wavelength
B. self-esteem
C. frequency
D. speed

Answers

Answer:

c frequency

hope it helps:))

Explanation:

To solve this we must be knowing each and every concept related to photon. Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

What is photon?

A photon, also known as a light quantum, is a small energy packet containing electromagnetic radiation. The idea came from Albert Einstein's explanation of something like the photoelectric phenomenon (1905), in which he hypothesized the possibility of energy levels packets during light transmission.

Photons all move just at speed of light. Photons are bosons that have no electric charge and rest mass one and unit of spin; they were field particle that are assumed to be the bearers of electromagnetic field. Photons with the lowest energy have the lowest frequency.

Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.

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In which of the following situations shows no acceleration of the car?
O A car shortly after a stoplight turns green.
A car approaching a red light
O A car with the cruise control set at 80 km/h
O A car turning a curve at a constant speed
Other:

Answers

It’s D I took the test

Answer:

I think A, a car shortly after a stoplight turns green OR if it's wrong it's B☺️

Other Questions
What event led to congress meeting to revise the articles of confederation Why did European nations want to expand into China? to spread ideas like democracy to learn about the culture there to stop other countries trade deals to increase their influence in the world How has globalization affected workers in the United States? BRAINLIEST A store owner mixed 8 pounds of peanuts and 9 pounds of m&ms, the mixture sold for 55.27. a second mixture included 6 pounds of peanuts and 4 pounds of m&ms and sold for 42.70. find the cost per pound of the peanuts and m&ms Max Points! Will Mark Brainliest To Whoever Gets Both Of These Correct First! The colonists were different from their relatives in Europe because they were _________ inches taller, far ____________, more children who were ______ times as likely to survive to adulthood, ______ % richer, and paid of the _____________ of the English. what is 83 as the sum of three square numbers can someone please help me? Please be quick. thanks. Oh and please dont just use me for points. Thank you! :)How does having skill-related fitness help you perform successfully in your everyday activities, at school and at home?Describe one exercise you did that helps improve your striking and your reaction time skills (at least one of your exercises must qualify).Describe how balance and/or coordination is needed for at least three things that you do every day.Name an activity or sport. What activity or game could a player practice during the off season to improve his/her performance? What similar movement skills are used when practicing this offseason activity?Try the aquatics exercises you learned in lesson 02.07 Aquatics. What was the most difficult part of completing the leg action of treading water or bicycling in the air? Why?Describe an outdoor pursuit you currently participate in, or an outdoor pursuit you would like to pursue in the future, including equipment needed and safety procedures.Did you meet your goal throughout this activity log? Why or why not? Cell theory teaches us that cells are the ? 1. In what two "presences" is this document being signed? ____________________ ______________________184Na11Antimony511086112 Select the correct answer.Kylie places a cube of metal A and a cube of metal B in two separate beakers of water. Then she heats the beakers. She keeps the mass of metal, the amount of water, and the amount of heat the same. At the end of her experiment, she finds that metal A has a lower temperature than metal B. What can she conclude about the thermal properties of the two metals?Metal B is a better conductor than metal A.Metal A is a better conductor than metal B.Metal A has a higher heat capacity than metal B.Metal B has a higher heat capacity than metal A. What does juxtaposition mean A function F(x) is such that F(-x) = F(x). If F(2) = -5. which of the following points must also be on the graph of F(x)? A. (-2,5) B. (2.5) C. (-2,-5) D. (-5. 2) E. (-5, -2) Write a function password_check() that takes as input two strings newpassword and oldpassword, and accepts the new password (i.e., returns True) if newpassword is different from oldpassword and newpassword is at least 6 letters long. If the new password fails the check, your functions should return False why are you here, do you just like to answer questions? If c is a number with no exponent, what is the value of c in the equation below?StartFraction 4 Superscript 7 Baseline Over 4 cubed EndFraction = a Superscript b Baseline = c Randal's dad is installing a new pool in their backyard. The pool is a square and has anarea of 121ft? Randal's dad will then build a 4 ft wide deck to surround the pool.What is the outside perimeter of the deck? what is the horizontal intercept of 3x+5y=-5 Which of the following is likely the lowest paid of the jobs listed?A. Retail clerkB. Car salespersonC. Desktop publisherD. Retail managerI Need help ASAP How do you know whether two quantities x and y are proportional? A. Every ratio yx for related pairs of x and y is equivalent. B. Every sum x + y is the same for related pairs of x and y. C. Every x term is a multiple of the previous term. D. Every difference x y is the same for related pairs of x and y.