Answer
t = 367.77 s = 6.13 min
Explanation:
According to the law of conservation of energy:
[tex]Heat\ Supplied\ By \ Heater = Heat\ Absorbed\ by\ Glass + Heat\ Absorbed\ by\ Water\\Pt = m_gC_g\Delta T_g + m_wC_w\Delta T_w\\[/tex]
where,
P = Electric Power of Heater = 300 W
t = time required = ?
m_g = mass of glass = 300 g = 0.3 kg
m_w = mass of water = 250 g = 0.25 kg
C_g = speicific heat of glass = 840 J/kg.°C
C_w = specific heatof water = 4184 J/kg.°C
ΔT_g = ΔT_w = Change in Temperature of Glass and water = 100°C - 15°C
ΔT_g = ΔT_w = 85°C
Therefore,
[tex](300\ W)(t) = (0.3\ kg)(840\ J/kg.^oC)(85^oC)+(0.25\ kg)(4184\ J/kg.^oC)(85^oC)\\[/tex]
t = 367.77 s = 6.13 min
In which circuit does charge reverse direction many times per second?
A. A DC circuit
B. A combined circuit
C. A parallel circuit D. An AC circuit
Answer:
D. An AC circuit
Explanation:
AC= Alternating current
What has to happen for a star to join the main sequence ?
1) Nuclear Fusion
2) Shell Heating
3) Use up most of its available fuel
4) Hydrostatic Equilibrium
Answer:
Nuclear fusion
Explanation:
This is because main sequence of star is powered by fusion of hydrogen to helium atoms together and this process releases energy. The energy released when the gas collapse into a protostar make the center of the protostar to be extremely hot. When the core becomes very hot, nuclear fusion can start.
Your friend says an appliance uses energy. How would you correct his statement?
Answer:
Not all appliances run on energy. Some of them run on gas. Some both. It just depends on the age of the appliance, the make of the appliance, and the company who made it.
Since water is much denser than air, deep-sea divers experience a much higher ambient pressure underwater. Each 10 meters of depth underwater adds another 1 atm to the ambient pressure experienced by the diver. (Note: this is in addition to the 1 atm ambient pressure at the surface of the water!) What pressure, in psi, is experienced by a diver 50.0 meters below the surface of the water
Answer:
If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.
Explanation:
At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
What is pressure?Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.
Pressure is the physical amount of force exerted on a particular area.
Pressure can be expressed as
Pressure = Force / area
There are three types of pressure.
Absolute pressureGauge pressureDifferential pressureThus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
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What is the force holding you down?
Answer:
The force holding you down is gravity.
Explanation:
Gravity is a force between two objects with mass. It pulls things together. You have mass, and the Earth has mass, so gravity tries to pull you and the Earth together. The gravitational force is much bigger for more massive objects.
Answer:
Gravitational Force
Explanation:
Gravitational Force holding everything down
-TheUnknownScientist
What is a cyclic behavior
Answer:
Uzi
Explanation:
When somebody comes to me I don’t have any
Europa, a satellite of Jupiter, appears to have an ocean beneath its icy surface. Proposals have been made to send a robotic submarine to Europa to see if there might be life there. There is no atmosphere on Europa, and we shall assume that the surface ice is thin enough that we can ignore its weight and that the oceans are fresh water having the same density as on the earth. The mass and diameter of Europa have been measured to be 4.78×10^22 kg k g and 3130 km k m , respectively.
Required:
If the submarine intends to submerge to a depth of 150 m , what pressure must it be designed to withstand?
Answer:
[tex]193743.49\ \text{Pa}[/tex]
Explanation:
G = Gravitational constant = [tex]6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2[/tex]
M = Mass of Europa = [tex]4.74\times 10^{22}\ \text{kg}[/tex]
R = Radius of Europa = [tex]\dfrac{3130}{2}=1565\ \text{km}[/tex]
h = Depth = 150 m
[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]
Acceleration due to gravity is given by
[tex]g=\dfrac{GM}{R^2}[/tex]
Pressure is given by
[tex]P=\rho gh\\\Rightarrow P=\rho \dfrac{GM}{R^2}h\\\Rightarrow P=1000\times \dfrac{6.674\times 10^{-11}\times 4.74\times 10^{22}}{1565000^2}\times 150\\\Rightarrow P=193743.49\ \text{Pa}[/tex]
The submarine should be designed to withstand a pressure of [tex]193743.49\ \text{Pa}[/tex].
The pressure due to column of liquid increases with the gravitational
attraction, density of the liquid and height of the liquid column.
The submarine should be able to withstand a pressure of approximately 194863.65 Pa.Reasons:
Mass of Europa, M = 4.78 × 10²² kg
Diameter of Europa, r = 3,130 km
Required:
The pressure a submarine must be designed to withstand when submerged to a depth of 150 meters.
Solution:
Gravitational acceleration on Europa is given by the formula;
[tex]\displaystyle g = \mathbf{\frac{G \cdot M}{r^2}}[/tex]
G = Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
[tex]Radius \ of \ the \ satellite\ Europa = \dfrac{3,130 \ km}{2} = \mathbf{1,565 \ km}[/tex]
[tex]\displaystyle g = \frac{6.67408 \times 10^{-11} \times 4.78 \times ^{22}}{1565000^2} \approx 1.303[/tex]
The gravitational acceleration on Europa, g ≈ 1.303 m/s²
Therefore;
Pressure due to a liquid's weight, P = ρ·g·h
The pressure at 150 m, P₁₅₀ = 150 × 1.303 × 997 = 194863.65
The pressure the submarine must be designed to withstand is, P₁₅₀ ≈ 194863.65 Pa.
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Rough Surface with: Ms = 0.8 HK = 0.4
(a) Find the magnitude of the
force F needed to prevent the
book from sliding down the
rough wall.
F
M = 1.5 kg
600
(b) Find the minimum force F
needed to set the book in
motion up the rough wall with
constant velocity
Answer:
a) F = 18.375N, b) F = 24.5 N
Explanation:
This exercise can be solved using the translational equilibrium equations.
Let's start by fixing a reference system with the horizontal x axis and the vertical y axis, from the statement of the exercise I understand that the wall is vertical and the book is supported on it, therefore the applied force is in the direction towards the wall
a) In this part the force that does not allow the movement of the book is requested, therefore the static friction coefficient must be used (μ_s = 0.8)
X axis
F - N = 0
N = F
Y axis
fr - W = 0
W = fr
where W is the weight of the book.
The friction force has the formula
fr = μ_s N
we substitute
mg = μ_s F
F = [tex]\frac{mg}{\mu_s }[/tex]
let's calculate
F = 1.5 9.8 / 0.8
F = 18.375N
b) In this case the book is moving so the friction coefficient to use is kinetic ( μ_K = 0.6)
F = [tex]\frac{mg}{\mu_K }[/tex]
we calculate
F = 1.5 9.8 / 0.6
F = 24.5 N
Which of the following answers are true: Group of answer choices The larger the slit, the better the wavelength resolution of the spectrometer A slit can select wavelengths spatially. This is for example used in a monochromator, where focused light after refraction in a prism or diffracted from a grating can be selected through a narrow slit. A slit can be used to direct light alternatingly to the sample or the blank. A slit can be used as a photodetector. The narrower the slit, the better the wavelength resolution of t
Answer:
true b, e
Explanation:
The expression that describes the diffraction of a grating is
d sin θ = m λ
where d is the separation between the slits, m is the order of the spectrum
let's analyze the different answers
a) False. The size (height) of the slits does not influence the resolution, the number of them per unit of length influences, the greater the number, the smaller the distance (d) this they
b) True. The spectrum is resolved on a screen, in the form that each wavelength corresponds to a fixed distance from the central maximum, for a given order
c) False. The exit slit selects a given wavelength, but does not deflect the beam from its path
d) False. The slit lets in light, but does not measure its intensity
e) True. For a continuous spectrum, the wavelength variation that passes through a slit is proportional to its width. For a discrete spectrum the width of the slit does not affect the wavelength
180 N
40 kg
140 N
Net Force =
Also how do you find the net force?
Answer:
720N
Explanation:
180+(40×10)+140=720 remember we can only add with same units ;1kg=10N therefore 40 kg=(40×10)N=400N
The net force would be the summation of all the forces in addition to the weight force of the 40 kg weight, thus the net force of all the forces would come out to be 712.4 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
F = ma
As given in the problem we have to find the net force,
Let us assume the acceleration due to gravity would be 9.81 m/s².
The force generated by the 40-kilogram weight =40 ×9.81 Newtons.
The force generated by the 40-kilogram weight = 392.4 Newtons
Net force = 180 + 140 +392.4
=712.4 Newtons
Thus, the net force of all the forces would come out to be 712.4 Newtons.
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what energy does a spillway produce?
Answer: Energy dissipation
As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base).
HOPE THIS HELPS
Answer: Energy dissipation
Explanation: As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base). Hope this helps. Can u give me brainiliest
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.00 m. A person is standing 12.0 m away from the wall, equidistant from the loudspeakers. When the person moves 3.00 m parallel to the wall, she experiences destructive interference for the second time. What is the frequency of the sound
Answer: [tex]278\ Hz[/tex]
Explanation:
Given
Distance between two speakers is 8 m
Man is standing 12 away from the wall
When the person moves 3 parallel to the wall
the parallel distances from the speaker become 4+3, 4-3
Now, the difference of distances from the speaker is
[tex]\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m[/tex]
Condition for destructive interference is
[tex]\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}[/tex]
for second destructive interference; n=2
[tex]\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz[/tex]
What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)
Answer:
When we have a current I, we will have a magnetic field perpendicular to this current.
Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".
Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.
Of course, the intensity of the magnetic field is proportional to the current, given by:
B = (μ*I)/(2*π*r)
Where:
μ is a constant, I is the current and r is the distance between to the current.
Now remember that for a resistor:
R = ρ*L/A
R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.
If we increase the area of the wire (if we use a thicker wire).
And the relation between resistance and current is:
I = V/R
Where V is the voltaje.
Now, if we use a thicker wire, then the cross-section area of the wire increases.
Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.
And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.
If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.
what happens to the work done when a force is doubled and the distance moved remain the same?
Answer:
It is doubled
Explanation:
f2=2f1
x1=x2=x
W1=f1*x1=f1*x
W2=f2*x2=f2*x=2*(fi*x)=2*W1
Calculate the equivalent resistance for each of the following circuits.
Answer:
5. 60 Ω
6. 60 Ω
7. 10 Ω
8. 0.625 KΩ
Explanation:
5. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 20 Ω
Resistor 3 (R₃) = 30 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 20 + 30
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
6. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 35 Ω
Resistor 3 (R₃) = 15 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 35 + 15
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
7. Determination of the equivalent resistance.
Resistor 1 (R₁) = 6 Ω
Resistor 2 (R₂) = 4 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂
R = 6 + 4
R = 10 Ω
Thus, the equivalent resistance is 10 Ω
8. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 KΩ
Resistor 2 (R₂) = 2 KΩ
Resistor 3 (R₃) = 1 KΩ
Equivalent Resistance (R) =?
Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/2 + 1/1
Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:
1/R = (1 + 5 + 10) / 10
1/R = 16/10
Invert
R = 10/16
R = 0.625 KΩ
Thus, the equivalent resistance is 0.625 KΩ.
Stars fuse most of the hydrogen in the entire star before they die.
2 poir
True
False
A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.
Wonderful.
Look out below !
Was the FAA notified ?
The place you get your hair cut has two nearly parallel mirrors 7.50 m apart. As you sit in the chair, your head is 1.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be
Answer:
the far distance is 15 meters
Explanation:
The computation is shown below
The Light from the back of your head must be
= 7.50m - 1.00m
= 6.50m
It should be the back mirror.
Now 7 m to front mirror and 1.00 m from the front mirror to
Therefore you see the back of your head is
= 7.50m + 1.00m + 6.50m
= 15 meters away
Hence, the far distance is 15 meters
Why one won't save a document as a text file
Answer:
i dont know
Explanation:
do you mean to save the answer or to save your question
Learning Task 1: Analyze the figure and answer the questions that follow.
1. Which one is the charged object?
2. What made the hair of the girl to rise?
Answer:
1) Van der rcf generator
2) the charge is distributed among all the hairs, as they all have the same potential,
the charges are of the same sign repel each other
Explanation:
1.) The object is a Van der rcf generator, which is loaded by friction,
The girl has no load
2) when the girl touches the sphere of the generator part of the electrons of this is transferred to the girl, when this charge reaches the hair, the charge is distributed among all the hairs, as they all have the same potential,
the charges are of the same sign repel each other
pls help!! i don’t understand what i am supposed to do.
Well, my German isn't as sharp as it used to be, but it looks like you're supposed to use the symbols at the top and draw two circuits ... one where the switch is closed and the light is shining, the other where the switch is open and the light is out.
That should be pretty easy for you. Just hook up one battery, one switch, and one light, all in series. Then opening and closing the switch makes the light go on and off.
People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Which factor causes glacial movement downhill?
A. gravity
B. oceans
C. snow
D. wind
An astronaut on the Moon has a weight of 128 N and a mass of 80 Kg. What
is the gravitational field strength of the moon?
Answer:
1.6 g
Explanation:
Use the formula: W = m× g
∴ g = W / m
Here, W = 128N
m = 80 Kg
∴ g = 128 ÷ 80
= 1.6 N (Ans)
Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n = 1.56) at an angle of 60°. What is the angle of reflection from the surface?
Answer:
The angle of reflection is "60°".
Explanation:
The given values are:
Light from monochromatic source,
= 560 nm
Angle of incidence,
= 60°
Surface of fused quartz (n),
= 1.56
Whenever a light ray was indeed occurring at a flat surface, it should be the law or concept of reflection which contains this same rays of light, the reflected ray as well as the "normal" ray at either the mirror surface.
According to the above law,
⇒ [tex]Angle \ of \ incidence=Angle \ of \ reflection[/tex]
then,
⇒ [tex]Angle \ of \ reflection=60^{\circ}[/tex]
PLEASE HELP ME WITH THIS ONE QUESTION
A diverging lens has a focal length of –10 cm. Suppose an object is placed 15 cm in front of the lens. a) What is the image distance? b) Is the image real or virtual?
Answer:
b
Explanation:
For given diverging lens(Concave) ; a) The distance of the image is -6 Cm, b) The image is virtual.
What is diverging lens?The lens that diverge incident parallel beam of light after refraction from the lens, is called diverging or concave lens.
The images formed by it are always smaller, upright, towards object and between focus and optical center of the lens.Given data:
a)
u = -15 Cm, f = -10 Cm, v= ?by using lens formula,[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]
On putting the values,[tex]\frac{1}{-10} = \frac{1}{v} - \frac{1}{-15}\\\frac{1}{-10} = \frac{1}{v} + \frac{1}{15}[/tex]
[tex]\frac{1}{v} = \frac{1}{-10} -\frac{1}{15} \\\frac{1}{v} = \frac{-3-2}{30} \\[/tex]
[tex]v = -6 Cm[/tex]
b) Magnification ,
m= ([tex]\frac{v}{u}[/tex])
on putting values,
[tex]m =(\frac{-6}{-15} )=\frac{2}{5} =0.4[/tex]
since m is positive it means the image is virtual
Hence a) distance of image is -6 Cm and b) the image is virtual.
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What is the
mass
density
of an object of
equal to 100 grams and volume of 20 cubic
centimeter
Answer:
[tex]d=5\ g/cm^3[/tex]
Explanation:
Given that,
Mass of the object, m = 100 grams
Volume of the object, V = 20 cm³
We need to find the density of the object. We know that, density is equal to mass per unit volume. So,
[tex]d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3[/tex]
So, the density of the object is equal to [tex]5\ g/cm^3[/tex].
A 2.3 kg , 20-cm-diameter turntable rotates at 110 rpm on frictionless bearings. Two 460 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. Part A What is the turntable's angular velocity, in rpm, just after this event
Answer:
The correct solution is "64 RPM".
Explanation:
The given values are:
Mass,
M = 2.3 kg
Diameter,
D = 20 cm
i.e.,
= 0.2 m
Rotates at,
N = 110 rpm
Mass of block,
m = 460 g
i.e.,
= 0.46 kg
According to angular momentum's conservation,
⇒ [tex]I_1\omega_1=I_2\omega_2[/tex]
then,
⇒ [tex]I_1=\frac{1}{2}MR_2[/tex]
On substituting the values, we get
⇒ [tex]=\frac{1}{2}\times 2.3\times (0.1)^2[/tex]
⇒ [tex]=\frac{1}{2}\times 0.023[/tex]
⇒ [tex]=0.0115 \ kg \ m^2[/tex]
Now,
⇒ [tex]I_2=I_1+2mR^2[/tex]
[tex]=0.0115+2\times 0.46\times (0.1)^2[/tex]
[tex]=0.0115+0.0092[/tex]
[tex]=0.02 \ kg \ m^2[/tex]
then,
⇒ [tex]0.0115\times 110=0.02\omega_2[/tex]
⇒ [tex]1.265=0.02\omega_2[/tex]
⇒ [tex]\omega_2=\frac{1.265}{0.02}[/tex]
⇒ [tex]=63.25 \ or \ 64 \ RPM[/tex]
So the the greater the height, the
farther something can fall, the greater
the potential energy.
True
False
PLEASE HELPPPPPP <333
Answer:
its b 100 kg
they told m¹ and m²
160‐60
Answer:
c
Explanation:
A negatively charged rod briefly touches a neutral metal ball. The metal ball will now be ____________
Answer:
let say it will be positive