A 1.8 g mass of fructose is added to 0.100 kg of water and it is
found that the freezing point has decreased by 0.186 °C. Given
that the Kf value of water is 1.86 °C kg/mol, what is the molar
mass of fructose (van't Hoff factor, i = 1)?
g/mol
Round your answer to the nearest whole number. Do not include units in your answer​

Answer:

The correct answer will be " RbF > RbCl > RbBr > Rbl".

Explanation:

The size of the given ions will be:

RbCl:

⇒  689kJ/mol

RbBr:

⇒  660kJ/mol

Rbl:

⇒  630kJ/mol

RbF:

⇒  785kJ/mol

Now according to the size, the arrangement will be:

⇒  (785kJ/mol) > (689kJ/mol) > (660kJ/mol) >(630kJ/mol)

⇒  RbF > RbCl > RbBr > Rbl

The bond among all opposite charging ions seems to be strongest whenever the ions were indeed small.

Answer: The final temperature is [tex]38.0^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]heat_{released}=heat_{absorbed}[/tex]

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)][/tex]

[tex]-[m_1\times (T_{final}-T_1)]=[m_2\times (T_{final}-T_2)][/tex]   (as [tex]c_1=c_2[/tex])

Q = heat absorbed or released

[tex]m_1[/tex] = mass of water at [tex]85.0^0C[/tex] = [tex]volume\times density=41.0ml\times 1g/ml=41.0g[/tex]

[tex]m_2[/tex] = mass of water at [tex]26.0^0C[/tex] = [tex]volume\times density=161.0ml\times 1g/ml=161.0g[/tex]

[tex]T_{final}[/tex]  = final temperature = ?

[tex]T_1[/tex]   = temperature of 41.0 ml of water = [tex]85.0^0C[/tex]

[tex]T_2[/tex]   = temperature of 161.0 ml of water = [tex]26.0^0C[/tex]

Now put all the given values, we get

[tex]-[41.0\times (T_f-85.0)^0C]=161.0\times (T_f-26.0)^0C[/tex]

[tex]T_f=38.0^0C[/tex]

Thus the final temperature is [tex]38.0^0C[/tex]

Answer:

3, H⁺ acceptor

Explanation:

Let's consider Bronsted-Lowry acid-base theory.

According to this theory, an acid is a substance that donates H⁺ ions. For example, HCl is an acid.

HCl + H₂O = Cl⁻ + H₃O⁺

Cl⁻ is the conjugate base of HCl.

According to this theory, a base is a substance that accepts H⁺ ions. For example, NH₃ is a base.

NH₃ + H₂O = NH₄⁺ + OH⁻

NH₄⁺ is the conjugate acid of NH₃.

According to one acid-base theory, a base is an H+ acceptor.

The acid-base theory, also called the Brønsted-Lowry theory, is a theory developed by Johannes N. Brønsted and Thomas M. Lowry.

In conclusion, according to one acid-base theory, a base is an H+ acceptor.

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Answer:

At lower temperatures the solubility of the KCl decreased and recrystallization occurred

Explanation:

Solubility refers to the amount of solute that dissolves in one litre of water at a particular temperature. Solubility is a property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The resulting solution is called a saturated solution.

Solubility is dependent on temperature. This is the reason why we must state the particular temperature at which a given solubility data was collected. Above or below the quoted temperature, the solubility data may no longer be accurate.

Let's return to the question, at elevated temperatures, we can see that the KCl is very soluble in water as evidenced by the clear solution obtained at high temperature. However, as the temperature decreases, the solubility of KCl also decreases accordingly and recrystallization of the solute occurred hence the formation of a cloudy solution and the settling of some solid at the bottom of the flask.

Answer:

C. At lower temperatures the solubility of the KCl decreased and recrystallization occurred

Explanation:

Answer:2,4-dichlorohexane

Explanation:

Hope it helps

Answer:

59.8287

Explanation:

I put that answer in and it is correct.

Answer:

Mg ---> Mg^2+ + 2e^

Explanation:

hope it helps : )

Magnesium is a neutral atom that can lose two electrons two achieve stability and forms a cation. The magnesium ion is produced as, Mg ⇒ Mg²⁺ + 2e⁻.

Magnesium ion is a charged species that is produced as the result of the neutral magnesium donating its electron so as to achieve its stable and complete electronic configuration.

When an atom donates an electron to another atom then they themselves become positively charged whereas the other species that accepts the electron becomes negatively charged. The positive charge is called a cation.

The reaction of the neutral magnesium donating electrons to become ions is shown as,

Mg ⇒ Mg²⁺ + 2e⁻

Therefore, magnesium loses two electrons to become positively charged.

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#SPJ2

Answer:

If the cap is left off, some of the dissolved CO2 can escape as gas from the bottle, making the pop go flat faster (less dissolved CO2 in pop). If the cap is placed tightly, the gaseous CO2 cannot readily escape the bottle thus your pop won't go flat

Explanation:

If the cap is left off, some of the dissolved CO2 can escape as gas from the bottle, making the pop go flat faster. If the cap is placed tightly, the gaseous CO2 cannot readily escape the bottle thus your pop won't go flat.

Just some fun related concept:

A similar concept comes into play for the reason behind why pop tastes better in fridge then just keeping at normal temperature. This is because gases tend to have high solubility at cold temperatures thus CO2 is more readily dissolved in fridge than outside room temperature which is why it tastes great!

Answer:

The oxygen atoms of the carbonyl groups and the hydrogen atoms attached to the nitrogen atoms form α-helices or β-pleated sheets. The order of the amino acids provides the R groups that interact to determine the tertiary structure

Explanation:

Enjoy! plz mark me brainliest

Answer:

Ernest Rutherford is known in his work of pioneering studies of radioactivity and the specifics in the atom. He discovered that there are two types of radiation, which are alpha and beta particles, coming from uranium. He found that the atom consists mostly of empty space, with its mass concentrated in a central positively charged nucleus.

Explanation:

hope this helps

Answer:

A. CH2.

B. CH.

Explanation:

A. Determination of the empirical formula of polyethylene.

Data obtained from the question include:

Carbon (C) = 86%

Hydrogen (H) = 14%

The empirical formula of the polyethylene can be obtained as follow:

C = 86%

H = 14%

Divide by their molar mass

C = 86/12 = 7.17

H = 14/1 = 14

Divide by the smallest

C = 7.17/7.17 = 1

H = 14/7.17 = 2

Therefore, the empirical formula of the polyethylene is CH2.

B. Determination of the empirical formula of polystyrene

Data obtained from the question include:

Carbon (C) = 92.3%

Hydrogen (H) = 7.7%

The empirical formula of the polystyrene can be obtained as follow:

C = 92.3%

H = 7.7%

Divide by their molar mass

C = 92.3/12 = 7.69

H = 7.7/1 = 7.7

Divide by the smallest

C = 7.69/7.69 = 1

H = 7.7/7.69 =

Therefore, the empirical formula of the polystyrene is CH.

Answer:

b. 186 g

Explanation:

Step 1: Write the balanced equation.

4 NH₃(g) + 6 NO(g) → 5 N₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 145 g of N₂

The molar mass of nitrogen is 28.01 g/mol.

[tex]145g \times \frac{1mol}{28.01 g} =5.18 mol[/tex]

Step 3: Calculate the moles of NO required to produce 5.18 moles of N₂

The molar ratio of NO to N₂ is 6:5.

[tex]5.18molN_2 \times \frac{6molNO}{5molN_2} = 6.22molNO[/tex]

Step 4: Calculate the mass corresponding to 6.22 moles of NO

The molar mass of NO is 30.01 g/mol.

[tex]6.22mol \times \frac{30.01g}{mol} =186 g[/tex]

The mass of NO required to produce 145 g of N₂ is 186 g.

The correct answer to the question is Option B. 186 g

We'll begin by calculating the mass of NO that reacted and the mass of N₂ produced from the balanced equation.

4NH₃ + 6NO —> 5N₂ + 6H₂O

Molar mass of NO = 14 + 16 = 30 g/mol

Mass of NO from the balanced equation = 6 × 30 = 180 g

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 5 × 28 = 140 g

From the balanced equation above,

140 g of N₂ were produce by 180 g of NO

Finally, we shall determine the mass of NO required to produce 145 g of N₂

From the balanced equation above,

140 g of N₂ were produce by 180 g of NO

Therefore,

145 g of N₂ will be produce by = (145 × 180) / 140 = 186 g of NO

Thus, 186 g of NO is required for the reaction.

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Answer:

Percentage of yield = 1%

Explanation:

Given:

Amount of yield = 5g

Total amount of product = 500 gram

Find:

Percentage of yield = ?

Computation:

⇒ Percentage of yield = [Amount of yield / Total amount of product]100

⇒ Percentage of yield = [5g / 500g]100

⇒ Percentage of yield = [0.01]100

⇒ Percentage of yield = 1%

Answer:

  7.86 g/cm³

Explanation:

  11.0 kg = 11,000 g

The density in g/cm³ is ...

  (11,000 g)/(1,400 cm³) = 7.86 g/cm³

Answer: In a compound with molecular formula [tex]X_2Y_3[/tex] ,the valency of Y and X are 2 and 3 respectively.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The given compound is [tex]X_2Y_3[/tex] where X and Y combine and their oxidation states or valencies are exchanged and written in simplest whole number ratios. Thus the oxidation state or valency of X is 3 and that of Y is 2.

The valency of X is 3 and the valency of Y is 2.

The valency is more simply defined as the combining power of an element. We can see the valency of an element from the subscript of the other atom in the compound. This will now serve as our guide in decoding the valencies of X and Y.

Hence, the valency of X is 3 and the valency of Y is 2.

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Answer:

Compound A: Propylbenzene

Compound B: Cumene

Explanation:

On this case, we have two clues:

1) The mass spectrometry info

2) The formation of benzoic acid

If we have the formation of benzoic acid with a strong oxidant ([tex]H_2CrO_4[/tex]). It means that we have an alky group bonded to benzene. Therefore we have to add three carbons to a benzene ring in order to obtain the mass of the compound (120).

The next question is how these three additional carbons are bonded to the benzene. For this, we have to check the mass info. For compound A we have a fragmentation moeity on 91 therefore we have a loss of an ethyl group. Therefore compound A have a linear structure for the aditional three carbons.

For compound B we have a fragmentation moeity on 105 this means a loss of 15 units of mass therefore we loss a methyl group. This indicates that we have a non linear structure fo the three additional carbons.

See figures 1 and 2.

I hope it helps!

Answer:

Hi..? All three elements are in group 1 thus they have 1 valence electron which is easy to lose due to shielding.As Pottasium is larger than the rest,Pottasium's valence electron is at a greater distance from the attractive nucleus and is so removed more easily than Sodium's and Lithium's valence electrons.As it is removed more easily it requires less energy and can be said to be more reactive

Answer:

See answer below

Explanation:

In this case, you are missing the picture. Luckily I found one on another site, so I hope is the one you are asking for. If not, please post again with the picture.

According to the picture below, you need to write a chemical formula for each molecular model.

To do this, is just simple. Let's see each model per separate.

In the first model, we have a blue ball and three white balls. According to the nomenclature of the question a blue ball represents nitrogen atoms and white ball represents hydrogen, therefore, we have an atom of nitrogen bonded to three atoms of hydrogens, so, the chemical formula should be:

NH₃: This molecule corresponds to the Ammonia molecule.

The second picture, shows 4 black balls (representing an atom of carbon each) and each black ball holds a determinated number of white balls. The two of the middle have two white balls each, and the terminals have 3 white balls, therefore, the molecule should be the following:

CH₃ - CH₂ - CH₂ - CH₃: this corresponds to the butane

Finally, the last picture shows a yellow ball (which represents sulphur) and three red balls (representing oxygen each), so, the molecule that represents this would be:

SO₃: this is the sulfite ion.

moles ratio of NH3 to H2O is 4:6

if 4=6

1. ?

1 * 6 /4 = 1.5

1.5 moles of water

Answer:

H3C is the chemical name for the methyl group, and it can also be written as CH3

CH2 is a carbene

OH is hydroxide

Answer:

PCl₅: 0.1192M

PCl₃: 0.0734M

Cl₂: 0.0734M

Explanation:

Based on the reaction:

PCl₅ ⇄ PCl₃ + Cl₂

K of reaction is defined as:

K = [PCl₃] [Cl₂] / [PCl₅]

Replacing with concentrations of gases in equilibrium:

K = [0.119] [0.119] / [0.313]

K = 0.0452

Moles of each gas is:

PCl₅: 7.40L × (0.313mol / L) = 2.3162 moles

PCl₃: 7.40L × (0.119mol / L) = 0.8806 moles

Cl₂: 7.40L × (0.119mol / L) = 0.8806 moles

When the volume of the container is increased the system will produce more moles, (That is, produce more products) in order to keep constant the pressure of the container -Le Chatelier's principle-. In equilibrium, molarity of each gas is:

PCl₅: 2.3162 moles - x / 16.6L

PCl₃: 0.8806 moles + x / 16.6L

Cl₂: 0.8806 moles + x / 16.6L

Where X is reaction coordinate.

Replacing in K formula:

0.0452 = [0.05305 + X/16.6] [0.05305 + X/16.6] / [0.13953 - X/16.6]

6.3068x10⁻³ - 2.723x10⁻³ X = 0.0028143 + 0.00639157 X + 0.00362897 X²

0 = -0.0034925 + 0.00911457X + 0.00362897 X²

Solving for X:

X = -2.8 → False answer. There is no negative concentrations

X = 0.3378 moles

Replacing:

PCl₅: 2.3162 moles - 0.3378 / 16.6L = 0.1192M

PCl₃: 0.8806 moles + 0.3378 / 16.6L = 0.0734M

Cl₂: 0.8806 moles + 0.3378 / 16.6L = 0.0734M

Beeing these concentrations the concentrations in equilibrium of the three gases

Answer:

Sodium Chloride, Potassium Chloride

Explanation:

Sodium Chloride, Potassium Chloride, are the most common example of a strong electrolyte. Most salts are strong electrolytes, such as hydrochloric acid, nitric acid, perchloric acid and sulphuric acid. Strong bases, such as sodium hydroxide and calcium hydroxide, are also potent electrolytes.

hope this helped!

Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

Answer:

Yes its both a physical and chemical change heres why.

When heated , the wax melts to form a liquid wax . The liquid wax then becomes a solid wax upon cooling ( Physical change )

When the candle is lit, the wax near the tip of the candle will melt . The wick then absorbs the liquid wax . The liquid wax then vapourizes due to the heat emitting from the flame . The wax vapour then burns to give off a black substance ( what we will to as CO₂ , soot ) , heat and water vapour

(Chemical change )

Brainliest ? Hope I answered your question

Answer:

LDL is

low density lipid

HDL is

high density lipid

Explanation:

HDL helps rid your body is excess cholesterol so so it won't end up in your arteries

LDL is also called "bad cholesterol" because it takes cholesterol to your arteries

Answer:

fluid pressure

Explanation:

a p e x

Answer:

Synthesis

Explanation:

Because the reactants aren't compounds, it has to be a synthesis reaction, in which Cu and O combine to make copper oxide.

Answer:

Synthesis

Explanation:

d

Answer:

The chemical bond between atoms in metallic elements

Explanation:

Metallic bond is a bond that exist between metallic elements. It does not occur between metals and non metals.

Answer:

39.44 %

Explanation:

Step 1: Write the balanced equation

I⁻(aq) + AgHCO₃(aq) = AgI(s) + HCO₃⁻(aq)

Step 2: Calculate the moles corresponding to 0.235 g of AgI

The molar mass of AgI is 234.8 g/mol.

[tex]0.235g \times \frac{1mol}{234.8g} = 1.001 \times 10^{-3} mol[/tex]

Step 3: Calculate the moles of I⁻ that form 1.001 × 10⁻³ mol of AgI

The molar ratio of I⁻ to AgI is 1:1. The reacting moles of I⁻ are 1/1 × 1.001 × 10⁻³ mol = 1.001 × 10⁻³ mol

Step 4: Calculate the mass corresponding to 1.001 × 10⁻³ mol of I⁻

The molar mass of I⁻ is 126.90 g/mol.

[tex]1.001 \times 10^{-3} mol \times \frac{126.90g}{mol} = 0.1270 g[/tex]

Step 5: Calculate the percent by mass of I⁻ in the original compound

[tex]\frac{0.1270g}{0.3220g} \times 100 \% = 39.44 \%[/tex]