8 girls eat a total of 210 candies. after adding the number of candies eat by the ninth girl, the average number of candies eaten became 29. how many did the 9th girl eat?

Mr. Bilo received 8 P50-bills, 5 P100-bills, and 5 P20-bills.

The number of P50, P100, and P20 bills Mr. Pilo got is calculated as follows;

Amount from P50-bills: 2/5 x P1,000 = P400

Amount from P100-bills: 1/2 x P1,000 = P500

The total amount he received from the P50-bills and P100-bills = P400 + P500

The total amount he received from the P50-bills and P100-bills = P900. The amount left to be changed into P20-bills = P1,000 - P900

The amount left to be changed into P20-bills = P100.

The number of bills will then be:

Number of P50-bills: P400 ÷ P50 = 8

Number of P100-bills: P500 ÷ P100 = 5

Number of P20-bills: P100 ÷ P20 = 5

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Complete question:

Mr Bilo has a P1,000-bill and asked someone to exchange in to 2/5 P50-bill and 1/2 P100-bill and the rest into 20-bill. How many P50,P100 and P20 bills did he get.

The Alverados spend $1,200 more on taxes than on clothing.

To determine how much more the Alverados spend on taxes than on clothing, we need to know how much they spend on each.

If we assume that the Alverados spend 25% of their income on taxes, that would be:

0.25 x $6,000 = $1,500

If we assume that the Alverados spend 5% of their income on clothing, that would be:

0.05 x $6,000 = $300

To find how much more they spend on taxes than on clothing, we can subtract the amount spent on clothing from the amount spent on taxes:

$1,500 - $300 = $1,200

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The value of tan(ф) when cos(ф) = 8/9 in quadrant IV is - √17/8

To solve for the value of tan(ф), we need to use the trigonometric identity: tan(ф) = sin(ф)/cos(ф).

Since ф is in quadrant IV, we know that the cosine value is positive (due to cosine being positive in the adjacent side of quadrant IV) and the sine value is negative (due to sine being negative in the opposite side of quadrant IV).

We are given the value of the cosine, which is cos(ф) = 8/9. To find the sine, we can use the Pythagorean identity: sin²(ф) + cos²(ф) = 1.

Plugging in the given value of the cosine, we get: sin²(ф) + (8/9)² = 1. Solving for sin(ф), we get sin(ф) = - √(1 - (64/81)) = - √(17/81) = - √17/9.

Now that we have the values of sin(ф) and cos(ф), we can substitute them into the tan(ф) equation: tan(ф) = sin(ф)/cos(ф) = (- √17/9)/(8/9) = - √17/8.

Therefore, the value of tan(ф) when cos(ф) = 8/9 in quadrant IV is - √17/8.

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Therefore, Tariq has collected 201.09 g trace element.

We are given that Tariq uses a container that is in the shape of a cylinder. The radius of the cylinder is 7.6 cm and the height of the cylinder is 17 cm.

Firstly, we will find the volume of the cylinder by applying the formula

The volume of the cylinder = [tex]\pi r^{2} h[/tex]

As we know the values of r and h, we will substitute these values in the given formula

The volume of cylinder = 3.14 * 17.6 * 7.6 *7.6

The volume of cylinder = 55.264 * 57.76

Volume = 3192.04 [tex]cm^{3}[/tex]

We are given that the water sample shows 0.063 grams of some trace element for every cubic centimeter of water. Therefore, we will multiply the volume of the cylinder by 0.063 to calculate the number of trace elements collected.

= 3192.04 * 0.063

= 201.09

Therefore, a total of 201.09 g of trace elements was collected by Tariq.

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The number name of 346. 725 is three hundred forty-six point seven two five.

A number name refers to the name that is used to describe the number in words. This is helpful in communicating it orally.

To convert the given number to word form, we do as follows:

1. We check the digits of the number before decimals

In this case, the number of digits in the question is 3

2. The highest place value is then checked.

It comes out to be hundreds

3. We name it accordingly and add a suffix to the face value

This is 3 and the name comes out to be Three hundred

4. We continue it till we encounter the decimal

We get the number as Three hundred forty-six

5. Then we mention the word decimal or point

The result is Three hundred forty-six point

6. The number after the decimal is written as it is

Hence, the name comes out to be Three hundred forty-six point seven two five.

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Answer: the median is 26, the first quartile is 19, and the third is 38

Step-by-step explanation:

if you count the numbers and x one by each side you will find the median which in this equation is 26, to find any first quartile you need to find the value under which 25% of data points are found when they are arranged in increasing order, to find the upper quartile you need to find the mean of the values of data point of rank.

Check the picture below.

Answer:

250 degrees

Step-by-step explanation:

For any circle tangent to line FG at point F, as shown in the diagram, and for any point E on the circle, the relationship between the measure of angle GFE and the arclength of FE is given by [tex]m~\text{arc}~FE=2m \angle GFE[/tex].

So, the measure of the arc FE is 110 degrees.  Since a circle is fully 360degrees, the missing arc represented by the question mark is given by the following equation:

? + 110 = 360

Solving for the ?

? = 250 degrees

Answer: 9/64

Step-by-step explanation:

First, we find the probability of blue in one spin.

One spin: 3/8

Next, we also know that the second spin will also have a probability of 3/8.

To combine these probabilities in both spins, we multiply. This will combine the two independent events. It can be similar to Permutation.

Probability of both spins: 3/8 x 3/8

=9/64

9/64 is the combined probability of both spins.

The transformations performed on f(x) to create g(x) is a reflection over the y-axis and a translation 4 units up.

An equation for g(x) in terms of f(x) is g(x) = f(-x) + 4.

In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

By applying a reflection over the y-axis to coordinate A of the image ABCD, we have the following:

(x, y)                               →              (-x, y)

Coordinate = (-1, 1/10)   →  Coordinate A' = (-(-1), 1/10) = (1, 1/10).

Furthermore, the transformation rule for the translation of a point by k units up is given by;

(x, y + k)         →  (x', y')

(1, 1/10 + k)       →  E(1, 4 1/10)

1/10 + k = 4 1/10

k = 4 1/10 - 1/10

k = 4.

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The probability of being 25-35 years and having a hemoglobin level above 11 is 0.102. The probability of having a hemoglobin level above 11 is 0.356. Being 25-35 years and having a hemoglobin level above 11 are dependent on each other.

From the two-way table, the total number of individuals who have a hemoglobin level above 11 is 153+44+40=237. The probability of having a hemoglobin level above 11 is the total number of individuals with hemoglobin level above 11 divided by the total number of individuals, which is 237/429=0.356.

The number of individuals who are between 25-35 years and have a hemoglobin level above 11 is 44. The probability of being 25-35 years and having a hemoglobin level above 11 is the number of individuals who are between 25-35 years and have a hemoglobin level above 11 divided by the total number of individuals, which is 44/429=0.102.

Being 25-35 years and having a hemoglobin level above 11 are dependent on each other because the probability of having a hemoglobin level above 11 changes based on the age group.

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Answer:

  a) multiply by cos²/cos², move sin/cos inside parentheses, simplify

  d) multiply by (cot+cos); use cot=cos·csc, csc²-1=cot² in the denominator

Step-by-step explanation:

You want to prove the identities ...

Usually, we want to prove a trig identity by providing the steps that transforms one side of the identity to the expression on the other side. Here, each of these identity expressions can be simplified, so it is actually much easier to simplify both expressions to one that is common.

We are going to use s=sin(x), c=cos(x), (s/c) = tan(x), and (c/s) = cot(x) to reduce the amount of writing we have to do.

  [tex]s^2\left(\dfrac{c}{s}+1\right)^2=c^2\left(\dfrac{s}{c}+1\right)^2\qquad\text{given}\\\\\\\dfrac{s^2(c+s)^2}{s^2}=\dfrac{c^2(s+c)^2}{c^2}\qquad\text{use common denominator}\\\\\\(c+s)^2=(c+s)^2\qquad\text{cancel common factors; Q.E.D.}[/tex]

Using the same substitutions as above, we have ...

  [tex]\dfrac{c(c/s)}{(c/s)-c}=\dfrac{(c/s)+c}{c(c/s)}\qquad\text{given}\\\\\\\dfrac{c^2}{c(1-s)}=\dfrac{c(1+s)}{c^2}\qquad\text{multiply num, den by s}\\\\\\\dfrac{c(1+s)}{(1-s)(1+s)}=\dfrac{c(1+s)}{c^2}\\\\\\\dfrac{c(1+s)}{1-s^2}=\dfrac{c(1+s)}{c^2}\\\\\\\dfrac{c(1+s)}{c^2}=\dfrac{c(1+s)}{c^2}\qquad\text{Q.E.D.}[/tex]

__

Additional comment

The key transformation in (d) is multiplying numerator and denominator by (1+sin(x)). You can probably prove the identity just by doing that on the left side, then rearranging the result to make it look like the right side.

For (a), the key transformation seems to be multiplying by cos²(x)/cos²(x) and rearranging.

Sometimes it seems to take several tries before the simplest method of getting from here to there becomes apparent. The transformations described in the top "Answer" section may be simpler than those shown in the "Step-by-step" section.

Andre's claim that the greatest product possible in the game is 987x65 is incorrect.

While 987x65 is a large product, it is not the greatest possible product in the game. In fact, a larger product can be obtained by multiplying the two largest numbers available in the game. Without knowing the specific rules of the game, it is impossible to determine the exact greatest product, but it is certain that 987x65 is not it.

To elaborate, the game likely has certain constraints or rules that limit the numbers that can be multiplied. It may be possible to combine multiple numbers to create a larger product, or to find a different pair of numbers that yield a larger product. Therefore, without knowing the specifics of the game's rules, it is impossible to determine the greatest possible product.

The actual greatest product possible in the game will depend on the specific rules and constraints that are in place. It may be possible to combine multiple numbers to create an even larger product, or to find a different pair of numbers that yield a larger product. Without knowing the specifics of the game's rules, it is impossible to determine the greatest possible product.

In mathematics, the concept of maximum or greatest products is important and is studied in various areas such as algebra, number theory, and calculus. In real-world applications, maximum products play a critical role in determining profits, yields, and returns on investments in economics and finance. In engineering, the concept of maximum product is used in optimization problems, where the goal is to maximize or minimize a certain function or output.

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Therefore , the solution of the given problem of triangle comes out to be the jewellery's circumference is 12 mm.

If a polygon contains at least one more segment, it is a hexagon. It is a simple rectangle in shape. Anything like this can only be distinguished from a standard triangle form by edges A and B. Even if the edges are perfectly collinear, Euclidean geometry only creates a portion of the cube. A triangle is made up of a quadrilateral and three angles.

Here,

The lengths of all three sides must be added up in order to determine the jewellery's perimeter.

=> c²= a² + b²

where a and b are the lengths of the other two sides, and c is the length of the hypotenuse.

=> A = 3mm, and B = 4mm.

Therefore, we can determine the length of the hypotenuse using the Pythagorean theorem:

=> c² = a²+ b²

=> c² = 3² + 4²

=> c² = 9 + 16

=> c² = 25

=> c = √25)

=> c = 5 mm

As a result, the hypotenuse is 5 mm long.

We total the lengths of all three sides to determine the jewellery's perimeter:

=> perimeter = 4mm, 3mm, and 5mm.

=> 12 mm is the diameter.

Therefore, the jewellery's circumference is 12 mm.

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The probability of drawing a diamond or a spade card from a standard deck of cards and rolling a 2 on a six-sided die is 8.33%

To calculate the probability of drawing a diamond or a spade card from a standard deck of cards, we need to find the total number of diamond and spade cards in the deck. There are 13 cards in each suit, so there are 26 diamond and spade cards in total. The deck has 52 cards in total, so the probability of drawing a diamond or a spade card is:

P(diamond or spade) = 26/52 = 1/2 = 50%

To calculate the probability of rolling a 2 on a six-sided die, we need to find the total number of possible outcomes, which is 6 (since there are 6 sides on the die), and the number of favorable outcomes, which is 1 (since there is only one face with a 2 on it). Therefore, the probability of rolling a 2 on a six-sided die is:

P(rolling a 2) = 1/6 = 16.67%

To find the probability of both events happening together (drawing a diamond or a spade card and rolling a 2 on a six-sided die), we multiply the probabilities of each event:

P(diamond or spade AND rolling a 2) = P(diamond or spade) * P(rolling a 2)
= 50% * 16.67%
= 8.33%

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Answer:

Blue = 4

Red = 24

Green = 4

All = 32

Step-by-step explanation:

Area of a triangle: 1/2 * base * height, so for both blue and green:

1/2 * 2 * 4

1 * 4

4

Area of an object with 4 sides: length * width, so for red:

6 * 4

24

Area of everything: blue + red + green, so for all:

4 + 4 + 24

8 + 24

32

(a) The quadrant in which u/2 lies is either Quadrant I or Quadrant II.

(b) The exact values of sin(u/2), cos(u/2), and tan(u/2) are:
sin(u/2) = √10/5
cos(u/2) = 3√10/10
tan(u/2) = 2/3

(a) To determine the quadrant in which u/2 lies, we need to look at the value of sin u. Since sin u is positive (3/5 is positive and π/2 is in Quadrant I), we know that u is in either Quadrant I or Quadrant II.

To find u/2, we divide u by 2, which means u/2 will be in either Quadrant I or Quadrant II as well. Therefore, the answer is either Quadrant I or Quadrant II.

(b) We can use the half-angle formulas to find the values of sin(u/2), cos(u/2), and tan(u/2):

sin(u/2) = ±√[(1 - cos u)/2]
cos(u/2) = ±√[(1 + cos u)/2]
tan(u/2) = sin(u/2)/cos(u/2)

Since sin u = 3/5, we can find cos u using the identity sin^2 u + cos^2 u = 1:

cos u = ±√[(1 - sin^2 u)] = ±√[(1 - 9/25)] = ±4/5

Since u/2 is in either Quadrant I or Quadrant II, we know that sin(u/2) and cos(u/2) are positive. Therefore, we can choose the positive square roots for sin(u/2) and cos(u/2):

sin(u/2) = √[(1 - cos u)/2] = √[(1 - 4/5)/2] = √[1/10] = √10/10 = √10/5
cos(u/2) = √[(1 + cos u)/2] = √[(1 + 4/5)/2] = √[9/10] = 3/√10 = 3√10/10

Finally, we can use these values to find tan(u/2):

tan(u/2) = sin(u/2)/cos(u/2) = (√10/5)/(3√10/10) = 2/3

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The statement on finding the areas of a trapezoid and a kite are True.

To determine the area of a trapezoid, it can be broken down into separate geometrical shapes. One possible breakdown would include a rectangle with two adjacent right triangles or an isosceles triangle with one right triangle configuration. By calculating each smaller compartment's size and summing them together, one can obtain the total area for the trapezoid.

Similarly, in order to find the surface area of a kite shape, drawing a diagonal creates two adjoining triangles that are easily computed individually then summed.

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Options for this question :
True

False

Answer: x + 4.8 = 14.3

Step-by-step explanation:

Let x be the initial amount of water that was already in the bucket before the additional 4.8 liters of water was poured in.

Then the total amount of water in the bucket after pouring in the 4.8 liters is the sum of the initial amount x and the amount of water poured in, which is 4.8 liters. This can be represented by the equation:

x + 4.8 = 14.3

We can simplify this equation by solving for x:

x = 14.3 - 4.8

x = 9.5

Therefore, the initial amount of water in the bucket was 9.5 liters, and after pouring in 4.8 liters, the bucket contained a total of 14.3 liters.

The equation of line passing through the points (8, 6) and (-3, 6) is y = 6. Since the y-coordinate is the same for both points, the line is a horizontal line at y = 6.

To find the equation of the line passing through the points (8, 6) and (-3, 6), we can use the slope-intercept form of a linear equation:

y = mx + b

where m is the slope of the line and b is the y-intercept.

First, we need to find the slope, which is given by

m = (y2 - y1) / (x2 - x1)

where (x1, y1) = (8, 6) and (x2, y2) = (-3, 6)

m = (6 - 6) / (-3 - 8)

m = 0 / -11

m = 0

Since the slope is zero, the line is a horizontal line. We can see from the given points that the line passes through y = 6. Therefore, the equation of the line is

y = 6

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The area of triangle ABC is 13.95 square inches.

We can start by finding the length of AB, which is equal to the diameter of the circle. Since the radius is 3 inches, the diameter is 2 times the radius, or 6 inches.

Next, we can use the fact that AC is tangent to the circle to conclude that angle CAB is a right angle. Therefore, triangle ABC is a right triangle.

Let's use the information about the arcs CD and CE to find the measure of angle BAC. The measure of an inscribed angle is half the measure of the arc that it intercepts, so angle CAD is 80 degrees and angle CAE is 50 degrees. Since angles CAD and CAE are opposite each other and AC is a tangent, we have angle BAC is 180 - 80 - 50 = 50 degrees.

Now we know that triangle ABC is a right triangle with a 90-degree angle at B and a 50-degree angle at A. To find the area of the triangle, we need to know the length of BC.

Using trigonometry, we can find that BC = AB * sin(50) ≈ 4.65 inches.

Therefore, the area of triangle ABC is (1/2) * AB * BC = (1/2) * 6 * 4.65 = 13.95 square inches. Rounded to the nearest hundredth, the area of triangle ABC is 13.95 square inches.

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Answer:

n = 10

Step-by-step explanation:

36 can be written as 6^2 because 6*6 = 36.

Since exponents multiply, 36^5 = (6^2)^5 = 6^(2*5) = 6^10 = 6^n.

n = 10.

Alternatively, 36^5 = 36 * 36 * 36 * 36 * 36.

If you replace each 36 with 6*6, the new equation is (6*6) * (6*6) * (6*6) * (6*6) * (6*6).

n = the number of 6's = 10.

The answer is B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.

To solve this problem, we are given a function h(x) and asked to find its antiderivative or indefinite integral, which is denoted by H(x) and is defined as the function whose derivative is h(x). We are also given a specific value of H(x) at x = 6 and asked to use it to find the constant of integration, denoted by C.

The given function is h(x) = 22x - 3x² - 6/x, and we want to find H(x), which is the antiderivative of h(x). Using the power rule of integration, we can integrate each term of h(x) separately:

where C is the constant of integration. Note that we need to include an absolute value sign around x in the natural logarithm term because the function is not defined for x = 0.

Next, we are given that H(6) = 31, which means that when x = 6, the value of H(x) is 31. Substituting x = 6 and H(x) = 31 into the above equation, we get:

Simplifying, we get:

Therefore, the antiderivative of h(x) is:

We can simplify the expression by using the identity ln|a/b| = ln|a| - ln|b|:

where C is the constant of integration. Thus, the final answer is:

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Answer:

Step-by-step explanation:

(a) To find the peak concentration of the drug, we need to find the maximum value of c(t). Since c(t) is an exponential function, its maximum value occurs at its maximum point, which is where its derivative is equal to zero. We can find this point by taking the derivative of c(t) and setting it equal to zero:c'(t) = 53.2e^{-0.26} - 13.832te^{-0.26} = 0Solving for t, we get t = 3.870 hours. Therefore, the peak concentration of the drug is c(3.870) = 109.2 ng/ml.(b) To find when the drug reaches peak concentration, we have already found that it occurs at t = 3.870 hours. Therefore, the drug reaches peak concentration 3.870 hours after it is administered.

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The peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.

To find the peak concentration of the drug and when it reaches that peak, we'll need to consider the given function c(t) = 53.2te^(-0.26t), where t is the time in hours.

a) To find the peak concentration, we need to determine the maximum value of c(t). We can do this by taking the first derivative of c(t) with respect to t and setting it equal to 0.

c'(t) = 53.2(-0.26)e^(-0.26t) + 53.2e^(-0.26t) = 0

Now, solve for t:

t ≈ 3.85 hours

b) Plug the value of t back into the c(t) function to find the peak concentration:

c(3.85) = 53.2(3.85)e^(-0.26(3.85)) ≈ 42.83 ng/ml

So, the peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.

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The "St. Petersburg Workmen's Petition to the Tsar" was a document written in 1870 by a group of Russian workers, which expressed their grievances and called for greater rights and protections in the workplace.

While the text of the petition is too long to summarize in its entirety, the following points illustrate some of the connections that the authors draw between workers' rights and their quality of life:

- The petitioners argue that workers have the right to a fair wage that allows them to support themselves and their families, and that without this right, workers are forced to live in poverty and squalor.

- They also argue that workers have the right to safe and healthy working conditions, and that without this right, workers are subjected to disease and injury that can shorten their lives and reduce their quality of life.

- The petitioners further argue that workers have the right to organize and advocate for their own interests, that without this right, workers are powerless to negotiate with their employers and to protect themselves against exploitation.

- They also argue that workers have the right to education and self-improvement, and that without this right, workers are trapped in a cycle of ignorance and subservience that limits their potential and reduces their quality of life.

- Overall, the authors of the petition argue that workers' rights and their quality of life are inextricably linked, and that without the former, the latter is impossible to achieve.

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The images of points B and C are B'(x, y) = (- 2, 6) and C'(x, y) = (- 1, 7), respectively.

In this problem we find must determine the image of two points by translation, whose formula is introduced below:

T(x, y) = P'(x, y) - P(x, y)

Where:

First, determine the translation vector:

T(x, y) = (1, 4) - (0, 0)

T(x, y) = (1, 4)

Second, determine the images of points B and C:

B'(x, y) = (- 3, 2) + (1, 4)

B'(x, y) = (- 2, 6)

C'(x, y) = (- 2, 3) + (1, 4)

C'(x, y) = (- 1, 7)

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Answer:

p = 38

Step-by-step explanation:

We Know

The 104° angle + (2p) angle must be equal to 180°.

Solve for the value of p.

Let's solve

104° + 2p = 180°

2p = 76°

p = 38

Your answer will depend on the measurements you obtain from the parallelograms.

To determine the scale factor of the dilation between the green parallelogram and the black parallelogram, follow these steps:
1. Choose corresponding sides of both parallelograms (e.g., the base or the height).
2. Measure the length of the chosen side in the green parallelogram and the same side in the black parallelogram.
3. Divide the length of the side in the green parallelogram by the length of the corresponding side in the black parallelogram.
The result will be the scale factor of the dilation. Compare the result with the given options:
A) 1/3
B) 1/2
C) 2
Your answer will depend on the measurements you obtain from the parallelograms.

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The volume of the fish tank is approximately 3,693,142,608 cubic inches

To find the volume of the rectangular prism-shaped fish tank, we need to multiply its width, length, and height.

Given the dimensions are 2014 inches wide, 1012 inches long, and 1812 inches tall, the calculation is as follows:

Volume = Width × Length × Height

Volume = 2014 in × 1012 in × 1812 in

Upon calculating the product, we get:

Volume ≈ 3,693,142,608 cubic inches

The volume of the fish tank is approximately 3,693,142,608 cubic inches

N.B: None of the answer choices has the correct answer.

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1. The growth factor for the number of customers over a year is approximately 1.4266.

2. the growth factor in customers over a decade period is approximately 5.927.

Factors that affect how many consumers there are in a year are

c(12)/c(0) = (400 x (1.03)¹²) / (400 x (1.03)⁰)

= (1.03)¹²

= 1.4266....

Therefore, the growth factor for the number of customers over a year is approximately 1.4266.

2. To write an equation for the number of customers c as a function of the number of years y, we can substitute m = 12y into the original equation

[tex]c(y) = 400 x (1.03)^{12y}[/tex]

one decade = 10 years

= 120 months

We must calculate the value of the equation at m=120 and divide it by the equation's value at m=0.

c(120) / c(0) = [400 x (1.03)¹²⁰] / [400 x (1.03)⁰]

= (1.03)¹²⁰

= 5.927...

Therefore, the growth factor in customers over a ten-year period is approximately 5.927.

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Given Question is incomplete, complete question is given below:

A small printing company launched an online ordering system to expand its business. The equation [tex]c=400(1. 03)^m[/tex] represents the number of customers c it has in terms of the number of months m since it launched the ordering system.

1. By what factor does the number of customers grow in one year? Write your answer as an expression and a numerical value

2. If y is time in years, write an equation for the number of customers c as a function of the number of years y after the introduction of the ordering system. If this model continues to apply for a decade, by what factor will the number of customers grow in one decade?