50 Points! Multiple choice algebra question. Which function represents exponential growth? Photo attached. Thank you!

A. The 51st note on a piano keyboard corresponds to a pitch of 440 cycles per second.

B. The pitch that is 73 notes higher on the keyboard has a frequency of about 1760 cycles per second.

A. Use the formula to find how many notes up the piano keyboard the pitch of 440 cycles per second corresponds to:

440 = 27.5 × 2⁽ⁿ⁻¹⁾/12

Dividing both sides by 27.5 and taking the logarithm with base 2 gives:

log₂(440/27.5) = (n-1)/12

n-1 = 12 × log₂(440/27.5)

n-1 = 12 × 4.1702 ≈ 50.042

n ≈ 51.042

Therefore, the pitch of 440 cycles per second is the 51st note up the piano keyboard.

B. Use the same formula to find the frequency of the pitch that is 73 notes up the keyboard:

73 = 1 + 12 log₂(f/27.5)

72 = 12 log₂(f/27.5)

6 = log₂(f/27.5)

f/27.5 = 2⁶

f = 27.5 × 2⁶

f ≈ 1760

Therefore, the frequency of the pitch that is 73 notes up the keyboard is approximately 1760 cycles per second.

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Step-by-step explanation:

The constant of proportionality is just the slope of the line

using 0,0   and  3,2   points

slope = (y1-y2 ) / ( x1-x2) = (0-3) / ( 0-2) = 3/2 = constant of proportionality

Heracio used the computer 2 more hours to do homework than to shop online.

To solve the problem, we need to first calculate the number of hours Heracio spent on each activity:

Videos: 10% of 40 hours = 4 hours

Homework: 20% of 40 hours = 8 hours

Games: 20% of 40 hours = 8 hours

Social media: 25% of 40 hours = 10 hours

Shopping: 15% of 40 hours = 6 hours

To find out how many more hours Heracio used the computer to do homework than shop online, we need to subtract the number of hours spent shopping from the number of hours spent on homework:

8 hours (homework) - 6 hours (shopping) = 2 hours

Therefore, Heracio used the computer 2 more hours to do homework than to shop online.

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The first equation of this system is y = 2x + 3, the second equation is y = 3x - 1, and the solution of the system is (4, 11).

a) The first equation of this system can be found by using the points given in the first table. We can use the two points (-1, 1) and (0, 3) to find the equation of the line passing through them using the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

The slope of the line passing through (-1, 1) and (0, 3) is (3-1)/(0-(-1)) = 2/1 = 2.

Substituting one of the points in the slope-intercept form, we get 1 = 2(-1) + b, which gives us b = 3. Therefore, the equation of the line is y = 2x + 3.

b) Similarly, we can use the points given in the second table to find the equation of the second line. Using the points (0, -1) and (2, 5), we get the slope as

(5-(-1))/(2-0)

= 6/2

= 3.

Substituting one of the points in the slope-intercept form, we get

-1 = 3(0) + b, which gives us b = -1.

Therefore, the equation of the second line is y = 3x - 1.

c) To find the solution of the system, we need to find the point of intersection of the two lines. We can do this by solving the two equations simultaneously.

Substituting the second equation in the first, we get:

2x + 3 = 3x - 1

Simplifying, we get x = 4.

Substituting x = 4 in either of the equations, we get y = 11. Therefore, the solution of the system is (4, 11).

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Answer:

3 x 195 = 585 minutes

Step-by-step explanation:

In one week, Alejandro attends a 45-minute lesson and practices for (6 x 25) = 150 minutes (assuming a 7-day week). So, the total number of minutes that Alejandro spends on his guitar in one week is:

45 + 150 = 195 minutes

In 3 weeks, the total number of minutes that Alejandro spends on his guitar is:

3 x 195 = 585 minutes

Therefore, Alejandro spends 585 minutes on his guitar in 3 weeks, including attending a 45-minute lesson once a week and practicing for 25 minutes on the remaining days of the week.

Answer: The mean absolute deviation is approximately is 11.43.

$3988.71 should be invested by them to be able to contribute $9000 to his education.

We can use the continuous compound interest formula:

[tex]A = Pe^{(rt)[/tex]

where A is the future value, P is the present value, r is the interest rate, and t is the time in years.

We know that A = $9000, r = 0.085 (8.5% expressed as a decimal), and t = 12.

Solving for P, we get:

[tex]P = A / e^{(rt)}\\\\P = 9000 / e^{(0.085*12)}\\\\P = \$ \ 3988.71[/tex]

Therefore, Mr. and Mrs. Tran should invest approximately $3988.71 now in order to have $9000 in twelve years, assuming continuous compound interest at a rate of 8.5% per year.

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Answer:

The appropriate test statistic for testing the null hypothesis that the slope of the population regression line equals 0 is the t-statistic.

The t-statistic for testing the slope coefficient is calculated as follows:

t = (b1 - 0) / SE(b1)

where b1 is the estimated slope coefficient, and SE(b1) is the standard error of the estimated slope coefficient.

From the computer output, we see that the estimated slope coefficient for exercise time is -2.20, and the standard error of the estimated slope coefficient is 0.07.

Therefore, the t-statistic is:

t = (-2.20 - 0) / 0.07 = -31.43

This t-statistic follows a t-distribution with n-2 degrees of freedom, where n is the sample size. The sample size is not given in the output, so we cannot determine the exact degrees of freedom.

Step-by-step explanation:

step A is incorrect.

-40/5 does not equal to -40/-5.

-40/-5 is equal to 40/5 as we can simplify the negative 1 out.

Answer:

The correct answer is step A

Answer:

  (3, 9) and (3, -7)

Step-by-step explanation:

You want the end points of the latus rectum for the parabola defined by ...

 (y -1)² = 16(x +1)

Compare the given equation to the form ...

  (y -k)² = 4p(x -h)

we see that (h, k) = (-1, 1) and p = 16/4 = 4. The ordered pair (h, k) is the vertex of the parabola. The scale factor 'p' gives the distance from the vertex to the focus (and from the directrix to the focus). Larger 'p' values result in a "flatter" parabola.

Since the squared term is a y-term, and the value of 'p' is positive, we know the parabola opens to the right. The end points of the latus rectum are ...

  (h+p, k±2p) = (-1+4, 1±2·4) = (3, 9) and (3, -7)

__

Additional comment

If the roles of x and y are interchanged (the parabola opens up or down), then the end points of the latus rectum are (h±2p, k+p).

On a graph of the parabola, the end points of the latus rectum lie on lines through the vertex with slope ±2 (parabola opens in x-direction), or with slope ±1/2 (parabola opens in y-direction).

Answer:

6 presents / minute

Step-by-step explanation:

We can represent the given information in a ratio:

amount of present wrapped : minutes it took to wrap

                                        2/3   :   1/9

Then, we can multiply both sides by 9 (the reciprocal of 1/9) so that the right side of the ratio is 1 minute.

presents : minutes

       2/3   :   1/9

       × 9       × 9

        6     :     1

So, Patricia can wrap 6 presents in 1 minute.

The type of transformation modeled in the graph is Reflection across y-axis.

The three different kinds of coordinate transformation are listed below. The motor's three-phase current and voltage are transformed by the Clark transformation from their original natural coordinates to two-phase static coordinates determined with reference to the stator.

Because the domain or range values of the function f(x) have changed, rules of transformations assist in changing f(x) to a new function f'(x). With the use of these transformational rules, the function can be stretched or compressed as well as transformed vertically or horizontally.

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Answer:

15 19/20

Step-by-step explanation:

95 cents means 95/100 then reduce that and you get 19/20 and then on the end you still have the $15

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-1}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-4)}}} \implies \cfrac{-5}{0 +4} \implies \cfrac{ -5 }{ 4 } \implies - \cfrac{ 5 }{ 4 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{ 5 }{ 4 }}(x-\stackrel{x_1}{(-4)}) \implies y -4 = - \cfrac{ 5 }{ 4 } ( x +4) \\\\\\ y-4=- \cfrac{ 5 }{ 4 }x-5\implies {\Large \begin{array}{llll} y=- \cfrac{ 5 }{ 4 }x-1 \end{array}}[/tex]

Answer:

b

4 x 3.2 = 12.8

17.8 - 5 =12.8

so,

4 x 3.2 = 17.8-5

12.8=12.8

The integral of  [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]  is (2/3)[tex]e^{3/2}[/tex] - (4/9).

To find the integral of   [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]  , we can use integration by parts. Let u = ln x and dv = [tex]x^{1/2}[/tex] dx. Then du/dx = 1/x and v = (2/3) [tex]x^{3/2}[/tex] .

Using the formula for integration by parts, we have:

∫[tex]x^{1/2}[/tex]lnx dx = uv - ∫v du/dx dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - ∫(2/3) [tex]x^{3/2}[/tex]  * (1/x) dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - (2/3) ∫ [tex]x^{1/2}[/tex]  dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - (4/9) [tex]x^{3/2}[/tex]  + C

where C is the constant of integration.

To evaluate the definite integral from 1 to e, we substitute e for x in the expression above and subtract the result when x = 1:

 [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]   = [(2/3) [tex]e^{3/2}[/tex] ln e - (4/9) [tex]e^{3/2}[/tex] ] - [(2/3)[tex]1^{3/2}[/tex]ln 1 - (4/9)[tex]1^{3/2}[/tex]]

= (2/3) [tex]e^{3/2}[/tex] - (4/9)

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b. The range is 32 - 16 = 16. and IQR  4

c. 32

a. Here is a box and whisker plot to represent the given data:

The horizontal axis shows the range of the data, and the vertical axis represents the frequency. The box represents the middle 50% of the data, with the bottom of the box being the 25th percentile and the top of the box being the 75th percentile. The whiskers represent the lowest and highest values within 1.5 times the interquartile range (IQR) of the box, and any points outside the whiskers are considered outliers.

b. The range is the difference between the highest and lowest values in the data set. In this case, the range is 32 - 16 = 16.

c. There is one outlier in the data set, which is the value of 32. It is outside the whiskers of the box and is considered to be an outlier.

The interquartile range (IQR) is the difference between the 75th and 25th percentiles of the data set. In this case, the IQR is:

IQR = Q3 - Q1

   = 22 - 18

   = 4

where Q1 is the first quartile (the value below which 25% of the data falls), and Q3 is the third quartile (the value below which 75% of the data falls).

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Answer:

a) y = 5.2727x + 32.5276

b) y = 5.2727(6) + 32.5276

= 64.1638 inches

c) y = 5.2727(7.153) + 32.5276

= 70.2432 inches

Answer:-₍1,3₎

Step-by-step explanation:

To solve this system of equations, we can use the method of elimination to eliminate one of the variables. We can multiply the first equation by 5 and the second equation by -3, then add the two equations to eliminate $y$:

$(5)(2x + 3y = 4) \Rightarrow 10x + 15y = 20$

$(-3)(3x + 5y = 7) \Rightarrow -9x - 15y = -21$

Adding the equations, we get:

$10x + 15y - 9x - 15y = 20 - 21$

Simplifying, we get:

$x = -1$

Now we can substitute $x=-1$ into one of the original equations to solve for $y$. Using the first equation, we have:

$2(-1) + 3y = 4$

Solving for $y$, we get:

$y = 2$

Therefore, the solution to the system of equations is $x=-1$ and $y=2$. We can check this solution by substituting $x=-1$ and $y=2$ into the other two equations:

$3(-1) + 5(2) = 7$

$10(-1) + 15(2) = 20$

Both equations are true, so our solution is correct.

first off, let's find out how much he's making on the 2nd year, so since he's getting slashed by 20%, that means his new commission is 100% - 20% = 80%, so 80% of 60000, how much is that?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{80\% of 60000}}{\left( \cfrac{80}{100} \right)60000}\implies 48000[/tex]

now, if we want to go up to 57600, that means we need to increase his commission by 57600 - 48000 = 9600.

So, if we take 48000(origin amount) to be the 100%, what's 9600 off of it in percentage?

[tex]\begin{array}{ccll} Amount&\%\\ \cline{1-2} 48000 & 100\\ 9600& x \end{array} \implies \cfrac{48000}{9600}~~=~~\cfrac{100}{x} \\\\\\ 5 ~~=~~ \cfrac{ 100 }{ x }\implies 5x=100\implies x=\cfrac{100}{5}\implies \boxed{x=20}[/tex]

Answer:

option c) x=-6

Step-by-step explanation:

-15x = 90

= x = 90/-15

= x = (-6)

The piecewise function is

f(x) = { x -3 , x≤3

             8, -3 < x ≤ 5

           x+10, x>6

For values less than or equal to -3, we have a line with a positive slope. We have two lines, y = x - 2, and y = x - 3.

1. For y = x - 2

-5 = -3 - 2= -5

2. For y = x - 3

-5 = -3-3 = -6

The fact that the domain is specified for x less than -3  further demonstrates that the first choice is not an option.

Additionally, we know that the function's value is equal to 8 for the range from x greater than -3 to less than or equal to 5.

Additionally, the equation is given as y = -x + 10 and the line has a negative slope for values greater than 6.

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Answer:

10) 73

11) 107

12) 107

13) x = 23

14) 135

15) 45

16) 123, 28 29

17) 180 - 72 - 28 = 80

Angle K is 80

Step-by-step explanation:

10:

Vertical angels are congruent.  The same measurement.

11:

Supplements angles add to 180

180 - 73 = 107

12:

Same as 11

13:

135

Vertical angles are congruent

5x + 20 = 3x + 66  Subtract 3x from both sides

2x + 20 = 66 Subtract 20 from both sides

2x = 46  Divide both sides by 2

x = 23

14:

5x + 20  Substitute 23 for x

5(23) + 20

115 + 20

135

15:

This angle is supplemental to ABC

180 - 135 = 45

16:

The sum of the interior angles of a triangle is 180

123 + x-2 + x -3 = 180 Combine like terms

118 +2x = 180  Subtract 118 from both sides

2x = 62  Divide both sides by 2

x = 31

x- 2

31 - 2 = 29

x - 3

31 - 3 = 28

Three angles 123, 29, 28

17:

The sum of the interior angles is 180

180 - 72 - 28 = 80

Helping in the name of Jesus.

A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money and he needs to withdraw at least x dollars, but not more than $2.75.

A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money. He needs to withdraw at least x dollars, but not more than $2.75.

What is the largest possible value of x that John can withdraw and still have a positive balance in his account?

In this scenario, the variable x represents the amount that John can withdraw from his account, and the inequality -2.75 > x means that x must be less than -2.75 (i.e., negative and greater in magnitude than 2.75)

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The amount of the final payment is $1,004.99.

To solve the given problem, we will use the concept of present value. We need to find the present value of the two payments due in the past, and then find the future value of the remaining payments due in the future.

Let's first find the present value of the two past payments:

PV1 = $1010 / (1 + 0.0775/12)⁵ = $868.15

PV2 = $1280 / (1 + 0.0775/12)⁰ = $1280

Next, we can find the future value of the remaining payments due in the future

FV1 = $615 x (1 + 0.0775/12)⁴ = $664.69

FV2 = X

Now we can set up an equation to solve for X, the final payment:

PV1 + PV2 = FV1 + FV2 / (1 + 0.0775/12)⁷

Substituting the values we have calculated:

$868.15 + $1280 = $664.69 + X / (1 + 0.0775/12)⁷

Simplifying and solving for X

X = ($868.15 + $1280 - $664.69) x (1 + 0.0775/12)⁷ = $1,004.99

Therefore, the amount of the final payment is $1,004.99.

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Answer: I believe it would be 2/5.

Step-by-step explanation:

Reduction means the fraction is reduced to it's simplest form.

7/7=1

2/5=2/5

15/13=1 2/13

See as the '2/5' does not change in reduction.

So, '2/5' would be your answer.

Hope this helps! :)

The expression that Sally can use to determine how many dominoes can fit in the tin based on the number of dominoes in each row stacked is (Number of rows stacked ÷ 0.75) x (9 x 4)

Sally can use the fact that she can fit 3 dominoes stacked on top of each other, 9 dominoes side-by-side, and 4 dominoes end-to-end in the tin to figure out how many dominoes can fit in the tin. Since she knows that 27 dominoes fit in one row stacked, she can use addition to determine the total number of dominoes that can fit in the tin.

First, she can find the number of dominoes that can fit in one layer of the tin by multiplying the number of dominoes that fit side-by-side and the number that fit end-to-end: 9 x 4 = 36.

Then, she can divide the total number of dominoes that fit in one row (27) by the number of dominoes that can fit in one layer (36): 27 ÷ 36 = 0.75.

This means that each layer of the tin can hold 0.75 rows of dominoes.

To find the total number of dominoes that can fit in the tin, Sally can multiply the number of layers by the number of dominoes in each layer: Number of layers x Number of dominoes in each layer = Total number of dominoes that can fit in the tin.

Therefore, the expression that Sally can use to determine how many dominoes can fit in the tin based on the number of dominoes in each row stacked is:

Total number of dominoes = Number of layers x Number of dominoes in each layer

Total number of dominoes = (Number of rows stacked ÷ 0.75) x (9 x 4)

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