5. A meteorologist measured the average rainfall received in cities A and
B. Both cities received 11 inches of rainfall in total. While City A received x
inches of rain, City B experienced three times the amount of rainfall than
City A. Find the number of inches of rain City A received.​

Answers

Answer 1

Answer:

2.75 inches

Step-by-step explanation:

City A received x  inches of rain.

City B experienced three times the amount of rainfall than  City A, therefore :

City B received 3x inches of rain.

Since both cities received 11 inches of rainfall in total.

We have that:

x+3x=11

4x=11

Divide both sides by 4

x=2.75 Inches

Therefore, we City A received 2.75 inches of rain.


Related Questions

y
6
Which points are located on this graph? Check all that
apply.
4
(1,1)
3
B (2,4)
2
(-3,0)
(0, 3)
(3,5)
-5 -4 -3 -2 -1
2 3
4
5
-2
(1,4)
-3
-4
-5






plssssss hellpppp​

Answers

Answer:

(-3,0) (0,3) (1,4)

Step-by-step explanation:

Answer:

the two you selected and the last choice

(-3, 0)

(0, 3)

(1, 4)

Step-by-step explanation:

The distance it takes a truck to stop can be

modeled by the function

Determine the value off, rounde

hundredth.

2

DONE

2.150 ?

d(u)=-

64.4f

d = stopping distance in feet

y = initial velocity in miles per hour

f= a constant related to friction

When the truck's initial velocity on dry pavement is

40 mph, its stopping distance is 138 ft.

Answers

Your question is not well presented (Refer below for correct question)

The distance it takes a truck to stop can be modeled by the function;

d(u) = 2.15u²/64.4f

Where

d = stopping distance in feet

u = initial velocity in miles per hour

f = a constant related to friction

When the truck's initial velocity on dry pavement is 40 mph, its stopping distance is 138 ft.

Determine the value of f.

Answer:

The friction constant is approximately 0.3871

Step-by-step explanation:

Given

Stopping distance, d(u) = 138ft

Initial Velocity, u = 40mph

Required

Friction constant, f.

To get the value of f, we need to simply substitute 40 for u and 138 for d(u) in the above expression.

In other words;

d(u) = 2.15u²/64.4f becomes

138 = 2.15 * 40²/64.4f

138 = 2.15 * 1600/64.4f

138 = 3440/64.4f

Multiply both sides by 64.4f

138 * 64.4f = 64.4f * 3440/64.4f

8887.2f = 3440

Divide both sides by 8887.2

8887.2f/8887.2 = 3440/8887.2

f = 3440/8887.2

f = 0.387073544

f = 0.3871 (Approximated)

Hence, the friction constant is approximately 0.3871

Answer:

first one is  .39
second answer is C   the last  one

Step-by-step explanation:

If f(x) = 4x^2 and g(x) = x+1, find (f.g)(x).

Answers

Answer:

4x^3 + 4x^2

Step-by-step explanation:

f(x) = 4x^2

g(x) = x + 1

=> (f.g)(x) = 4x^2*(x + 1) = 4x^3 + 4x^2

Hope this helps!

if f(x)= 4x squared + 1 and g(x) = x squared -5 , find (f+g)(x)

Answers

Answer:

5x^2 -4

Step-by-step explanation:

f(x)= 4x^2+ 1

g(x) = x^2 - 5

(f+g)(x) = f(x) + g(x)

= 4x^2+ 1 + x^2 - 5

= 4x^2 + x^2 + 1- 5

= 5x^2 -4

In a game of poker a player receives a subset of 5 cards from a standard deck of 52 cards. There are four suites (clubs, spades, hearts, diamonds) with 13 cards in each suite. What is the probability your hand contains exactly 3 hearts (out of 5 cards)?

Answers

Answer:

8.15% probability your hand contains exactly 3 hearts

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the cards are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

What is the probability your hand contains exactly 3 hearts (out of 5 cards)?

We have 52 cards in total.

13 are clubs, 13 are spades, 13 are hearts, 13 are diamonds.

Desired outcomes:

3 hearts, from a set of 13.

Other 2 cards, from a set of 52-13 = 39.

So

[tex]D = C_{13,3}*C_{39,2} = \frac{13!}{3!(13-3)!}*\frac{39!}{2!(39-2)!} = 211926[/tex]

Total outcomes:

5 cards, from a set of 52. So

[tex]T = C_{52,5} = \frac{52!}{5!47!} = 2598960[/tex]

Probabilities:

[tex]p = \frac{D}{T} = \frac{211926}{2598960} = 0.0815[/tex]

8.15% probability your hand contains exactly 3 hearts

Select one: A. ∠T ≅ ∠F B. ∠T ≅ ∠D C. ∠J ≅ ∠F D. ∠J ≅ ∠D

Answers

Answer:

B

Step-by-step explanation:

Since you are given line RT and ND, then all you need to do by ASA is the make sure that the angles are the two endpoints are congruent. Since the problem already gave you R and N, then all thats left is to relate the other two endpoints, namely, T and D

Notice that the alternative hypothesis is a two-tailed test. Suppose ttest_ind method from scipy module is used to perform the test and the output is (-1.99, 0.0512). What is the P-value for this hypothesis test

Answers

Answer:

The p-value of the test is 0.0512.

Step-by-step explanation:

The p-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

In this case the output of the t-test_ind method from scipy module is provided as follows:

Output = (-1.99, 0.0512)

The first value within the parentheses is the test statistic value.

So the test statistic value is, -1.99.

And the second value within the parentheses is the p-value of the test.

So the p-value of the test is 0.0512.

An investment of ​$100 comma 000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned​ 8% interest, the second​ 6%, and the third​ 9%. Total interest from the investments was $ 7380. The interest from the first investment was 2 times the interest from the second. Find the amounts of the three parts of the investment.

Answers

Answer:

$54000 was invested at​ 8% interest$36000 was invested at​ 6% interest$10000 was invested at​ 9% interest

Step-by-step explanation:

Total Investment = ​$100,000

The investment was split into three parts (say x, y and z)

x+y+z=100000

Simple Interest = Principal X Rate/100 X Time

The first part of the investment earned​ 8% interest

Interest on the first part = 0.08x

The second part of the investment earned​ 6% interest

Interest on the second  part = 0.06y

The third part of the investment earned​ 9% interest

Interest on the third part = 0.09z

Total interest from the investments = $ 7380.

Therefore:

0.08x+0.06y+0.09z=7380

The interest from the first investment was 2 times the interest from the second.

0.08x=2 X 0.06y

0.08x=0.12y

Substituting we have:

0.12y+0.06y+0.09z=7380

0.18y+0.09z=7380

From 0.08x=0.12y

x=1.5y

Substituting x=1.5y into x+y+z=100000

1.5y+y+z=100000

2.5y+z=100000

z=100000-2.5y

Substituting z=100000-2.5y into 0.18y+0.09z=7380

0.18y+0.09(100000-2.5y)=7380

0.18y+9000-0.225y=7380

-0.045y=-1620

Divide both sides by -0.045

y=36000

Recall: x=1.5y

x=1.5 X 36000

x =54000

x+y+z=100000

54000+36000+z=100000

z=100000-(54000+36000)

z=10,000

Therefore:

$54000 was invested at​ 8% interest$36000 was invested at​ 6% interest$10000 was invested at​ 9% interest

Video Example EXAMPLE 5 Where is the function f(x) = |x| differentiable? SOLUTION If x > 0, then |x| = and we can choose h small enough that x + h > 0 and hence |x + h| = . Therefore, for x > 0 we have

Answers

Answer:

Step-by-step explanation:

We say that a function is differentiable if it's derivative exists and it is continous over the domain of the original function. Recall that the function |x| is given as |x| = x if [tex]x\geq 0[/tex] and |x|=-x if x<0. In both cases, we have either the function x or -x, which are one-degree polynomials. So, we can find easily their derivatives. So if f(x) = |x|. Then, we have that

[tex]f'(x) = (x)' = 1 \text{if } x\geq 0[/tex]

[tex]f'(x) = (-x)' = -1 \text{if } x<0[/tex]

We should check what happens x=0, since that is the point where the definition of f changes. We can check that

[tex]\lim_{x\to 0^+} f'(x) = 1[/tex] and

[tex]\lim_{x\to 0^-} f'(x) = -1[/tex]

since this limits are not equal, the derivative is not continous at x=0. Hence, the derivative doesn't exist at x=0.

In this case, we say that |x| is differentiable at any x different from 0.

1. (a) The life time of a certain brand of bulbs produced by a company is normally distributed, with mean 210 hours and standard deviation 56 hours. What is the probability that a bulb picked at random from this company’s products will have a life time of:
(i) (ii) (iii) at least 300 hours,
at most 100 hours, between 150 and 250 hours.
(b) In a contest, two friends, Kofi and Mensah were asked to solve a problem. The probability that Kofi will solve it correctly is and the probability that Mensah
will solve it correctly is . Find the probability that neither of them solved it correctly.
2. Suppose that the random variable, X, is a number on the biased die and the p.d.f. of X is as shown below;
X
1
2
3
4
5
6

P(X=x)
1/6
1/6
1/5
k
1/5
1/6

a) Find;
(i) (ii) (iii) (iv) (v) the value of k. E(X)
E(X2) Var(X) P(1 £X <5)
b) If events A and B are such that they are independent, and P(A) = 0.3 with P(B) = 0.5;
i. ii. Find P(A n B) and P(AUB)
Are A and B mutually exclusive? Explain.
c) In how many ways can the letters of the word STATISTICS be arranged?

Answers

Answer:

See explanation

Step-by-step explanation:

Q1)a

- Denote a random variable ( X ) as the life time of a brand of bulb produced.

- The given mean ( μ ) = 210 hrs and standard deviation ( σ ) = 56 hrs. The distribution is symbolized as follows:

                           X ~ Norm ( 210 , 56^2 )

i) The bulb picked to have a life time of at least 300 hours.

- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:

          P ( X ≥ x ) = P ( Z ≥ ( x - μ ) / σ )

          P ( X ≥ 300 ) = P ( Z ≥ ( 300 - 210 ) / 56 )

          P ( X ≥ 300 ) = P ( Z ≥ 1.607 )  

- Use the standard normal look-up table for limiting value of Z-score:

         P ( X ≥ 300 ) = P ( Z ≥ 1.607 ) = 0.054  .. Answer

ii) The bulb picked to have a life time of at most 100 hours.

- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:

          P ( X ≤ x ) = P ( Z ≤ ( x - μ ) / σ )

          P ( X ≤ 100 ) = P ( Z ≤ ( 100 - 210 ) / 56 )

          P ( X ≤ 100 ) = P ( Z ≤ -1.9643 )  

- Use the standard normal look-up table for limiting value of Z-score:

         P ( X ≤ 100 ) = P ( Z ≤ -1.9643 ) = 0.0247  .. Answer

iii) The bulb picked to have a life time of between 150 and 250 hours.

- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:

          P ( x1 ≤ X ≤ x2 ) = P ( ( x1 - μ ) / σ ≤ Z ≤ ( x2 - μ ) / σ )

          P ( 150 ≤ X ≤ 250 ) = P ( ( 150 - 210 ) / 56 ≤ Z ≤ ( 250 - 210 ) / 56 )

          P ( 150 ≤ X ≤ 250 ) = P ( -1.0714 ≤ Z ≤ 0.71428 )  

- Use the standard normal look-up table for limiting value of Z-score:

         P ( 150 ≤ X ≤ 250 ) = P ( -1.0714 ≤ Z ≤ 0.71428 ) = 0.6205  .. Answer

Q1)b

- Denote event (A) : Kofi solves the problem correctly. Then the probability of him answering successfully is:

                    p ( A ) = 0.25

- Denote event (B) : Menesh solves the problem correctly. Then the probability of him answering successfully is:

                    p ( B ) = 0.4

- The probability that neither of them answer the question correctly is defined by a combination of both events ( A & B ). The two events are independent.  

- So for independent events the required probability can be stated as:

              p ( A' & B' ) = p ( A' ) * p ( B' )

              p ( A' & B' ) = [ 1 - p ( A ) ] * [ 1 - p ( B ) ]

              p ( A' & B' ) = [ 1 - 0.25 ] * [ 1 - 0.4 ]

              p ( A' & B' ) = 0.45 ... Answer

Q2)a

- A discrete random variable X: defines the probability of getting each number on a biased die.

- From the law of total occurrences. The sum of probability of all possible outcomes is always equal to 1.

             ∑ p ( X = xi ) = 1

             p ( X = 1 ) + p ( X = 2 ) + p ( X = 3 ) + p ( X = 4 ) + p ( X = 5 ) + p ( X = 6 )

             1/6 + 1/6 + 1/5 + k + 1/5 + 1/6 = 1

             k = 0.1  ... Answer

- The expected value E ( X ) or mean value for the discrete distribution is determined from the following formula:

             E ( X ) = ∑ p ( X = xi ) . xi

             E ( X ) = (1/6)*1 + (1/6)*2 + (1/5)*3 + (0.1)*4 + (1/5)*5 + (1/6)*6

             E ( X ) = 3.5 .. Answer

- The expected-square value E ( X^2 ) or squared-mean value for the discrete distribution is determined from the following formula:

             E ( X^2 ) = ∑ p ( X = xi ) . xi^2

             E ( X^2 ) = (1/6)*1 + (1/6)*4 + (1/5)*9 + (0.1)*16 + (1/5)*25 + (1/6)*36

             E ( X^2 ) = 15.233 .. Answer

- The variance of the discrete random distribution for the variable X can be determined from:

            Var ( X ) = E ( X^2 ) - [ E ( X ) ] ^2

            Var ( X ) = 15.2333 - [ 3.5 ] ^2

            Var ( X ) = 2.9833 ... Answer

- The cumulative probability of getting any number between 1 and 5 can be determined from the sum:

           P ( 1 < X < 5 ) = P ( X = 2 ) + P ( X = 3 ) + P ( X = 4 )

           P ( 1 < X < 5 ) = 1/6 + 1/5 + 0.1

           P ( 1 < X < 5 ) = 0.467  ... Answer

Q2)b

- Two independent events are defined by their probabilities as follows:

           p ( A ) = 0.3  and p ( B ) = 0.5

- The occurrences of either event does not change alter or affect the occurrences of the other event; hence, independent.

- For the two events to occur simultaneously at the same time:

          p ( A & B ) = p ( A )* p ( B )

          p ( A & B ) = 0.3*0.5

          p ( A & B ) = 0.15  ... Answer

- For either of the events to occur but not both. From the comparatively law of two independent events A and B we have:

        p ( A U B ) = p ( A ) + p ( B ) - 2*p ( A & B )

        p ( A U B ) = 0.3 + 0.5 - 2*0.15

        p ( A U B ) = 0.5 ... Answer

- Two mutually exclusive events can-not occur simultaneously; hence, the two events are not mutually exclusive because:

       p ( A & B ) = 0.15 ≠ 0

Q2)c

- The letters of the word given are to be arranged in number of different ways as follows:

                                  STATISTICS

- Number of each letters:

        S : 3

        T : 3

        A: 1

        I: 2

        C: 1

- 10 letters can be arranged in 10! ways.

- However, the letters ( S and T and I ) are repeated. So the number of permutations must be discounted by the number of each letter is repeated as follows:

                        [tex]\frac{10!}{3!3!2!} = \frac{3628800}{72} = 50,400[/tex]

- So the total number of ways the word " STATISTICS " can be re-arranged is 50,400 without repetitions.

                   

What’s the correct answer for this question?

Answers

C. 1/5 chance that they boy did not see the movie.

Answer:

C.

Step-by-step explanation:

The answer is c. Probability has a formula it is, what we want/what we don't want. This means that we can use the table to calculate what the probability is that a randomly selected boy didn't see the movie.

1. 4/16

2. 1/4

Hope this helps! (Please consider giving brainliest)

i need halp pls im confused and it would help me out

lateral area
surface area
volume​

Answers

Step-by-step explanation:

lateral area=area of the full triangle

surface area=area of the four triangles + area of the square

Find the missing side length. Show all of your work. I'll give you the brilliant crown if you answer the question correct.

Answers

Answer:

h = 6

Step-by-step explanation:

We need to use Pythagorean theorem.

h² + 8² = 10²

h² = 100 - 64 = 36

h = 6

I have attached 3 different problems, please could you help. Thank you

Answers

Answer:

  1a) 210

  1b) 0.18

  2) 17.7 will fit (> 17)

  3) 515 cm^2

Step-by-step explanation:

1a) The sample of 25 is exactly 1/30 of the population of 750, so the number of orange cakes in the population will be 30 times the number in the sample.

The total number of orange cakes made on Monday is 30·7 = 210.

__

1b) The lowest number that will round to 5 is 4.5. The lowest probability that a cake is an orange cake is ...

  4.5/25 = 18/100 = 0.18

The lower bound on the probability that the cake is orange is 0.18.

____

2) The working shown is partly correct.

The possible error in the box dimension is 1/2 cm, so the box may be as short as 28 -1/2 cm = 27.5 cm.

The possible error in the disc case dimension is 1/2 mm = 0.05 cm, so the case may be as thick as 1.5 +.05 = 1.55 cm.

The minimum number discs that will fit in the case is (27.5 cm)/(1.55 cm) = 17.7. Thus, 17 cases will definitely fit in the box.

____

3) The shaded area will be the largest when the outside rectangle is the largest and the inside rectangle is the smallest. Errors in dimensions can be as much as 1/2 cm, so the Outside rectangle can be 42.5 cm by 21.5 cm. The inside rectangle can be as small as 27.5 cm by 14.5 cm.

Then the shaded area can be as large as ...

  (42.5)(21.5) -(27.5)(14.5) = 515 . . . . cm^2

Match each term with its notation. Enter the number corresponding to the correct notation in the blank.


______:The number of treatment conditions
______:The number of scores in each treatment
______:The total number of scores in the entire study
______:The sum of the scores for each treatment condition
______:The sum of all of the scores in the research study
______:The F-ratio

1. G
2. k
3. n
4. T
5. n
6. F

Answers

Question:

Match each term with its notation. Enter the number corresponding to the correct notation in the blank.

______:The number of treatment conditions

______:The number of scores in each treatment

______:The total number of scores in the entire study

______:The sum of the scores for each treatment condition

______:The sum of all of the scores in the research study

______:The F-ratio

1. G

2. k

3. N

4. T

5. n

6. F

Answer:

i) K :The number of treatment conditions

ii) n :The number of scores in each treatment

iii) N :The total number of scores in the entire study

iv) T :The sum of the scores for each treatment condition

v) G :The sum of all of the scores in the research study

vi) F :The F-ratio

Step-by-step explanation:

Here we are dealing with ANOVA notations.

ANOVA which is the short form for Analysis of Variance is a test in staristics used to compare two population samples to check if they are equal.

Here, we have the following ANOVA notations:

G, K, n, T, N, F

Where, G is said to be the sum of scores in the research study.

K is the number of treatment.

n is the number of scores in each treatment

T is the sum of scores for each treatment condition.

N is the total number of scores in whole study

F is the F-ratio.

Matching them with the terms given, we have the following:

i) K :The number of treatment conditions

ii) n :The number of scores in each treatment

iii) N :The total number of scores in the entire study

iv) T :The sum of the scores for each treatment condition

v) G :The sum of all of the scores in the research study

vi) F :The F-ratio

Note the difference between "N" and "n"

10. A rectangular tank has length 4 m, width
12 m and height 3.5 m.
i) If the tank is filled with water to 2/3
of its capacity, calculate the volume
of the water in the tank.

Answers

Answer:

112m³

Step-by-step explanation:

VOLUME=L × W × H

= 4m × 12m × 3.5m

= 168m³

THE TANK IS FILLED TO 2/3 OF IT'S CAPACITY

= 2/3 × 168

= 112m³.

eu (european union) countries report that 46% of their labor force is female. The United Nations wnats to determine if the percentage of femailes in the U.S. labor force is the same. Based on sample, representatives from the United States department of labor find that the 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443. if the department of labores wishes to tighten it's interval they should

Answers

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the percentage of females in the U.S. labor force is the same. Based on a sample of 500 employment records, representatives from the United States Department of Labor found that the 95% confidence interval for the proportion of females in the U.S. labor force is 0.357 to 0.443. If the Department of Labor wishes to tighten its interval, they should:

A. increase the confidence level

B. decrease the sample size

C. increase the sample size

D. Both A and B

E. Both A and C

Solution:

Confidence interval for population proportion is written as

Sample proportion ± margin of error

Where sample proportion is the point estimate for the population proportion.

Margin of error = z × √pq/n

The z score for 95% confidence level is 1.96

p = 46/100 = 0.46

q = 1 - p = 1 - 0.46

q = 0.54

n = 500

Margin of error = 1.96√0.46 × 0.54/500 = 0.044

To tighten it's interval, the margin of error needs to be reduced.

If we increase the confidence level, say to 99%, z = 2.58

Then

Margin of error = 2.58√0.46 × 0.54/500 = 0.058

It increased

Also, If we increase the sample size, say to 700, then

Margin of error = 1.96√0.46 × 0.54/700 = 0.037

It has reduced

Therefore, the correct options is

C. increase the sample size

Juanita goes shopping in Times Square, where T-shirts are 20% off today. If she buys one in the next 10 minutes, she can get an extra 10% off the sale price. How much would Juanita pay for a T-shirt right now? *

Answers

Answer:

72%

Step-by-step explanation:

As the T-shirts have 20% off and Juanita would get an extra 10% off the sale price, the additional discount would be over the price with the 20% off included. This means that the sale price is the 80% of the normal price and an additional 10% over that 80% would be:

80*10%= 8

80%-8%= 72%

This means that Juanita would have to pay the 72% percent of the regular price of the T-shirt as the total discount would be 28% off.

Assume the readings on thermometers are normally distributed with a mean of 0degreesC and a standard deviation of 1.00degreesC. Find the probability that a randomly selected thermometer reads between negative 2.05 and negative 1.49 and draw a sketch of the region.

Answers

Answer:

[tex]P(-2.05<X<-1.49)=P(\frac{-2.05-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.49-\mu}{\sigma})=P(\frac{-2.05-0}{1}<Z<\frac{-1.49-0}{1})=P(-2.05<z<-1.49)[/tex]

And we can find this probability with this difference

[tex]P(-2.05<z<-1.49)=P(z<-1.49)-P(z<-2.05)=0.068- 0.0202= 0.0478[/tex]

And we can see the figure in the plot attached.

Step-by-step explanation:

Let X the random variable that represent the redings on thermometers of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0,1)[/tex]  

Where [tex]\mu=0[/tex] and [tex]\sigma=1[/tex]

We are interested on this probability

[tex]P(-2.05<X<-1.49)[/tex]

We can use the z score formula given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Using this formula we got:

[tex]P(-2.05<X<-1.49)=P(\frac{-2.05-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.49-\mu}{\sigma})=P(\frac{-2.05-0}{1}<Z<\frac{-1.49-0}{1})=P(-2.05<z<-1.49)[/tex]

And we can find this probability with this difference

[tex]P(-2.05<z<-1.49)=P(z<-1.49)-P(z<-2.05)=0.068- 0.0202= 0.0478[/tex]

And we can see the figure in the plot attached.

A local movie theater increased the price of
admission by 20%. Tickets had sold for $5.25.
What is the current ticket price?

Answers

Answer:

0.26

Step-by-step explanation:

This table gives a few (x,y) pairs of a line in the coordinate plane.

Answers

Answer:

-26

Step-by-step explanation:

y=mx+c

m= (y2 - y1 ) / (x2-x1)

m= (10-1) / (48 -36)

m = 0.75

10 = 0.75(48) + c

c = 10 - 36

c = -26

Apple weights in an orchard are normally distributed. From a sample farmer Fred determines the mean weight of a box of apples to be 270 oz. with a standard deviation of 10 oz. He wonders what percent of the apple boxes he has grouped for sale will have a weight less than 255 oz.

Answers

Answer:

2.07 is the answer as of e.2020

Step-by-step explanation:

A snack stand sells bottles of water for $1.35 each . Sam needs to buy as many bottles as he can. He can spend no more than $20. How much money will Sam have left after he buys the bottles of water?

Answers

Answer: 1.1

Step-by-step explanation:

If Sam buys 14 water bottles, he will have spent 18.9, so when you subtract 20 (the limit) from 18.9 (how much money he'll spend on the water bottles) you get 1.1

Todd is 3 years older than his brother Jack. If Jack is x years old and Todd is y years
old, write a rule that relates their ages over time. When Jack is 28 years old, how old will Todd be?

Answers

Answer:

1)   y = x + 3

2)   31 years old

Step-by-step explanation:

Jack is x years old

Todd is y years old

Todd is 3 years older than his brother Jack => y = x + 3

When Jack is 28 years old, Todd is y = 28 + 3 = 31 years old

Please answer this correctly

Answers

Answer:

The first one will be da answer

Step-by-step explanation:

happy to help you!

Write an equation of the line that passes through (2,-1) and (-3,3)

Answers

Answer:

Y=-4/5x+3/5y

Step-by-step explanation: first get the gradient

3--1/-3-2

=4/-5

y-3/x+3=4/-5

-5y+15=4x+12

-5y=4x-3

y=4/-5x+3/5

The distance between (-1,2) and (-2,1)

Answers

Answer:

About 10 i think

Step-by-step explanation:

idk

Exact Form:
√2
Decimal Form:
1.41421356...

Jennifer started a lawn mowing business and borrowed $85 to buy materials. Nicholas started a babysitting business and borrowed $60 to buy materials. Which statement correctly shows who has the greater debt?

Answers

Answer:

Jennifer because she would make less but spent more on supplies

Step-by-step explanation:

Answer: The answer is D! Jennifer, |-85| > |-60|

Step-by-step explanation: I did the quiz hope everyone does great ^^

What is the value of b^2- 4ac for the following equation? x(x+8)=9

Answers

Answer:

hope this is correct

Sam is rowing a boat away from a dock. The graph shows the relationship
between time and Sam's distance from the dock. Evaluate the function for an
input of 6.
Distance from Dock
Distance (meters)
110
100
90
80
70
50
50
40
10
20
0 1 2 3 4 5 6 7 8 9 10 11
Times (minutes)
O A. After 60 minutes, Sam is 6 meters from the dock
O B. After 6 minutes, Sam is 60 meters from the dock.
O c. After 60 minutes, Sam is 60 meters from the dock.

Answers

Answer: after 6 mins, sam is 60 meters from the dock

Step-by-step explanation:

Answer:

after 6 mins, sam is 60 meters from the dock

Step-by-step explanation:

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