3 m
3 m
3 m
6 m
Area:

Answer:

[tex]\csc \left(x\right)=\frac{\csc \left(x\right)+\sec \left(x\right)}{1+\tan \left(x\right)}[/tex]

[tex]=\frac{1}{\sin \left(x\right)}[/tex] (expressed with sine and cosine)

[tex]\frac{1}{\sin \left(x\right)}=\csc \left(x\right)[/tex]

[tex]=\csc \left(x\right)[/tex]

Therefore, the identity has been proven true.

Answer:

h = - [tex]\frac{3}{10}[/tex]

Step-by-step explanation:

23h - 13h + 11 = 8 ( subtract 11 from both sides )

10h = - 3 ( divide both sides by 10 )

h = - [tex]\frac{3}{10}[/tex]

Your answer(s) will be:

0.3 (Decimal Form)

              or

3/10 (Fraction Form)

The positive integer for which g(x) first exceeds f(x) is 178 according to the number line.

The function f of (x) is used to denote a linear algebra that can be represented on the graph.

Given that:

We are to determine a positive integer for which g(x) first exceeds f(x). Using the following option;

Therefore, we can conclude that the positive integer for which g(x) first exceeds f(x) is 178 according to the number line.

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Answer:

25 to 3 power ÷ 3 = 69

Answer:

0.32

Step-by-step explanation:

3/10=0.3

2/5=0.4

0.32 is between these two numbers.

Hope this Helps

Answer:

Step-by-step explanation:

(1 + 11)/(-2+5)= 12/3=4

y + 11 = 4(x + 5)

y + 11 = 4x + 20

y = 4x + 9

The length of the hypotenuse will be equal to H=122.25 when value of x=14.

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal the square of the sum of the other two sides.

It is given that:

Value of x=14

The perpendicular is  =6x+5=6x14+5=89

The base is  =6x=84

So by using the Pythagorean theorem:-

[tex]H^2=P^2+B^2\\\\\\H^2=89^2+84^2\\\\\\H=\sqrt{89^2+84^2}\\\\\[/tex]

Hence the value of hypotenuse will be H=122.25

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The value of the expressions (-0.3)⁴ equal to 0.0081.

A mathematical expression is the representation of numbers in the form of powers or mathematical signs.

Here we have the (-0.3)⁴

Now by evaluating the expression we will get:

(-0.3)⁴=(-0.3x-0.3x-0.3x-0.3)

Hence the value of the given expression will be 0.0081

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Answer:

its 3

Step-by-step explanation:

id ont know the formula but im certain im a very smart 6th grader!

Answer:

10 times

Step-by-step explanation:

4 in 547 is equal to 40

4 in 84 is equal to 4

When you separate that number into smaller parts

Ex: 547 = 500 + 40 + 7

Answer:

You could ask what her average score is using mean (which is 36.25)

Step-by-step explanation:

Answer:

You could ask what her average score is using mean (which is 36.25)

Step-by-step explanation:

Answer:

6

Step-by-step explanation:To find the median, first order your data. Then calculate the middle position based on n, the number of values in your data set. If n is an odd number, the median lies at the position (n + 1) / 2. If n is an even number, the median is the mean of the values at positions n / 2 and (n / 2) + 1.

Answer:

6

Step-by-step explanation:

Answer:

here

Step-by-step explanation:

find the circumference of the lid (this is like a side length of a rectangle)

2*pi*2= 12.566in

Then multiply by 3 (the other side length)

12.566*3= 37.7in squared :)

Answer:

h > 1600

Step-by-step explanation:

Since the elevation at which it is difficult for Matt to breathe (h) has to be *higher* than 1600, h is greater than 1600.

Answer:

B is the correct answer from my understanding

Step-by-step explanation:

Answer: 113 ( 34x3+11

Step-by-step explanation:

34x 3 on top + 7 + 24/6

34 x 3 on top + 7 = 4

34 x 3 on top + 7 + 4

34 x 3 on top + 11

34 x 3 on top + 11

Answer:

See below ~

Step-by-step explanation:

Table 1

⇒ Side length : Perimeter = 1 : 4

⇒ Perimeter : Side length = 4 : 1

Table 2

⇒ Radius : Diameter = 1 : 2

⇒ Diameter : Radius = 2 : 1

Table 3

⇒ Number of people : Number of tables = 5 : 1

⇒ Number of tables : Number of people = 1 : 5

The number of tops on the 6th day based on the exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent [tex]\rm y = a^x[/tex]

where a is a constant and a>1

First day class collected = 2 tops

Third day class collected = 8 tops

The exponential function can be modelled:

[tex]\rm D(N) = 2^N[/tex]

D(1) = 2  (first day)

D(3) = 8  (third day)

D(6) = 64 (sixth day)

The linear function can be modeled:

D(N) = 3N -1

D(1) = 2  (first day)

D(3) = 8 (third day)

D(6) = 17 (sixth day)

Thus, the number of tops on 6th day based on exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.

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After applying operations between functions, we find the following four transformations for the function [tex]f(x) = 2^{x}[/tex]:

a) 6 · f(x) - [tex]g(x) = 6 \cdot 2^{x}[/tex]

b) f(6 · x) - [tex]g(x) = 2^{6\cdot x}[/tex]/[tex]g(x) = 2^{6}\cdot f(x)[/tex]

c) f(x + 6) - [tex]g(x) = 2^{x+6}[/tex]/[tex]g(x) = 2^{6}\cdot f(x)[/tex]

d) f(x) + 6 - [tex]g(x) = 2^{x}+6[/tex]

Mathematically speaking, transformations are operations applied on a function such that its domain or range are altered. There are five operations for functions:

Let suppose that [tex]f(x) = 2^{x}[/tex], the images of this function are, respectively:

a) 6 · f(x) - Multiplication between two functions

[tex]g(x) = 6 \cdot 2^{x}[/tex]

b) f(6 · x) - Composition between two functions

[tex]g(x) = 2^{6\cdot x}[/tex]

[tex]g(x) = (2^{x})^{6}[/tex]

[tex]g(x) = (f(x))^{6}[/tex]

c) f(x + 6) - Composition between two functions

[tex]g(x) = 2^{x+6}[/tex]

[tex]g(x) = 2^{x}\cdot 2^{6}[/tex]

[tex]g(x) = 2^{6}\cdot 2^{x}[/tex]

[tex]g(x) = 2^{6}\cdot f(x)[/tex]

d) f(x) + 6 - Addition between two functions

[tex]g(x) = 2^{x}+6[/tex]

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Step-by-step explanation:

cubic root(56) + cubic root(189) =

= cubic root(7×8) + cubic root(27×7) =

= 2×cubic root(7) + 3×cubic root(7) = 5×cubic root(7) =

= 9.564655914...

Answer:

Step-by-step explanation

the figure is composed of a square with an isosceles right triangle inside, we find the area of ​​the square and we take away the area of ​​the triangle.

Triangle area = lxl, right-angled triangle area side by side divided by two.

8 * 8 = 64cm²

6 * 6 : 2 = 18 cm²

Area of the shaded region

64 - 18 = 46 cm²

The completed code to generate and save a number in the program which allow a user to guess a number from (1,10) is input.

Program or programming is the combination of codes. These codes are used to generate the program such that a machine can understand the inputs given to it.

The program is written to allow a user to guess a number. This number should be between the number 0 to 10.

Here, the input is needed to a machine or computer, for which it's process the number and show if the guessed number is correct or not.

Hence, the completed code to generate and save a number in the program which allow a user to guess a number from (1,10) is input.

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Answer:

45.5 m²

Step-by-step explanation:

Area (Shaded) = Area (Rectangle) - Area (Trapezoid)

Area of trapezoid:-

Area of triangle:-

Which part is shaded not said so both shaded regions area calculated

Answer: 21 J (Joules) of work done.

Step-by-step explanation:

W = Fs, where F is force and s is displacement.

F = 7 N

s = 3 m

W = 7 N * 3 m = 21 N*m, or 21 J

21 N/m of work is done by a man to push the box.

The displacement plus a component of the applied force of the item in the direction of displacement make up the work done by a force. Work is accomplished when we push a block with some force; the body moves more quickly.

We have,

Force = 7 Newton

Distance = 3 m

We know, Work done = Force x distance

Work done = 7 x 3

Work done = 21 N/m

Thus, the amount work done is 21 N/m.

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Answer:

an acute triangle im guessing ik its not a right and the degrees and  the inches are small So it can't be absolute thats just what i was thinking but i might be wrong

Step-by-step explanation:

Answer:

-13f

Answer:

[tex]\textsf{Area of a triangle}=\dfrac{1}{2} ab \sin C[/tex]

(where [tex]a[/tex] and [tex]b[/tex] are the sides, and [tex]C[/tex] is the included angle)

[tex]\textsf{Area of a sector}= \dfrac{\theta}{360} \pi r^2[/tex]

(where [tex]\theta[/tex] is the angle in degrees and [tex]r[/tex] is the radius)

Therefore, using the above formulas:

[tex]\begin{aligned}\textsf{Area of segment } \rm (A) & = \textsf{area of sector}- \textsf{area of triangle}\\& = \dfrac{\theta}{360} \pi r^2 - \dfrac{1}{2}r^2 \sin \theta\\\end{aligned}[/tex]

Given:

Substitute the given values into the formula and solve for r:

[tex]\begin{aligned}\implies 20 & = \dfrac{90}{360} \pi r^2 - \dfrac{1}{2}r^2 \sin 90\\\\20 & = \dfrac{1}{4} \pi r^2 - \dfrac{1}{2}r^2 (1)\\\\20 & = \left(\dfrac{1}{4} \pi -\dfrac{1}{2}\right)r^2\\\\20 & = \left(\dfrac{\pi -2}{4}\right)r^2\\\\r^2 & = 20\left(\dfrac{4}{\pi -2}\right)\\\\r^2 & =\dfrac{80}{\pi-2}\\\\r & =\sqrt{\dfrac{80}{\pi-2}}\\\\r & = 8.37\: \sf (2\:dp)\end{aligned}[/tex]

Answer:

30.96

Step-by-step explanation:

First you must find the diameter of the circle which is 12

Then you must use the formula A=πr²

So it should be = to A = 3.14 ×144 which is 30.96

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

[tex] \large\underline{ \boxed{ \sf{✰\:Notes }}}[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

[tex] \large\underline{ \boxed{ \sf{✰\: formule\: used\:✰ }}}[/tex]

[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: circle = \pi {r}^{2} \: }}}✟}}[/tex]

[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: square = side \times side \: or \: ( {s}^{2}) \: }}}✟}}[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

✛ 1st taking out the the area of circle✛

[tex] \qquad \rm{➛ \: radius(r) = \frac{12}{2} } \\ \\ \qquad \rm{➛ \: radius(r) = \frac{ \cancel{12}}{ \cancel2} } \\ \\ \qquad \rm{➛ \: radius(r) =6m}[/tex]

[tex] \\ \qquad \rm{➛Area \: of \: circle = 3.14 \times {6}^{2} \:} \\ \\ \qquad \rm{➛Area \: of \: circle = \:3.14 \times 36} \\ \\ \qquad \rm{➛Area \: of \: circle = \:113.04 {m}^{2} }[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

✛ now finding the area of square✛

[tex]\\ \qquad \rm{➛Area \: of \:square = 12×12} \\ \\ \\ \qquad \rm{➛Area \: of \:square = 144 {m}^{2} }[/tex]

[tex]\\ \rm{➛Area \: of \:shaded \: part = \: area \: of \: circle - area \: of \: squre} \\ [/tex]

★ Let's substitute value ★

[tex]\\ \rm{➛Area \: of \:shaded \: part =113.04-144} \\ \\ \qquad \rm{➛Area \: of \:shaded \: part =30.96 {m}^{2} }[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

★ Hence area of shaded part =

[tex]{ \boxed{✜\underline{ \boxed{ \sf{ \: 30.96 {m}^{2} \green✓\: }}}✜}}[/tex]

★ note here we neglect minus (-)

[tex] \rule{70mm}{2.9pt}[/tex]

Hope it helps !