2
Which of the following notations is the correct noble gas configuration for Sr?
OA. [Ar]4s2
OB. [Ar]5s2
OC. [Kr]4s2
OD. [Kr]5s2

Answer:

Cu(NO₃)₂ (aq) + 2 KI (aq) ---> CuI₂ (s) + 2 KNO₃

Explanation:

When writing the reaction with the symbols, you need to take into account the charges of the ions. If he charges on the ions do not balance out in a molecule, they need to be made up for in the form of subscripts. For example, copper (+2) and iodine (-1) have charges which do not balance. Thus, to make the molecule neutral, you need to have two iodine atoms (CuI₂).

The unbalanced equation:

Cu(NO₃)₂ (aq) + KI (aq) ---> CuI₂ (s) + KNO₃

Reactants: 1 copper, 2 nitrate, 1 potassium, 1 iodine

Products: 1 copper, 1 nitrate, 1 potassium, 2 iodine

The balanced equation:

1 Cu(NO₃)₂ (aq) + 2 KI (aq) ---> 1 CuI₂ (s) + 2 KNO₃

Reactants: 1 copper, 2 nitrate, 2 potassium, 2 iodine

Products: 1 copper, 2 nitrate, 2 potassium, 2 iodine

The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.

Normal Distribution is a probability distribution which is symmetric about the mean , The frequency is more near the mean and less far from the mean.

It is given in the data that

10,000 more observations were collected

the percentage of the observations would be greater than 98.02 = ?

According to the 68-95-99.7 rule,

It states that approximately

68% of the observations lie within σ of µ

95% of the observations lie within 2σ of µ.

99.7% of the observations lie within 3σ of µ.

The percentage of the observation between various intervals is attached in the image in the answer.

2.1 percent of the population is distributed in the intervals between two and three standard deviations , which is the zone above 2SD and below 3SD.

As 2.1 % is approximate , Therefore from the given option , 2.5%

The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.

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If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour

The rate at which someone or something moves or operates or is able to move or operate.

Snail covers distance in 1 seconds = 228.16 cm

It covers in 60 seconds (1 min) = 228.16 cm x 60 = 6mtrs

It covers in 60 minutes (1 hour) = 228.16 cm x 60 x 60 = 821376 cm

Now, lets convert cm to miles :

As,                    1 cm = 6.21371 x 10⁻⁶ miles

Thus,     821376 cm = 5.10 miles

hence, If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour

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Answer:

1 C₂H₆O

Explanation:

The given equation:

C₂H₆O + 3 O₂ ---> 2 CO₂ + 3 H₂O

Reactants: 2 carbon, 6 hydrogen, 7 oxygen

Products: 2 carbon, 6 hydrogen, 7 oxygen

As you can see, the amount of each element on both sides is identical. Therefore, the reaction is already balanced. This means that the coefficient in front of C₂H₆O is 1. When writing the equation, writing the one is insignificant and usually left out.

5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH  is mathematically given as

V=2.107mL

Generally, the equation for Chemical Reaction is mathematically given as

CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O

Therefore

pka=-log(1.8*10{-5})

pKa=5-0.25527

pKa=4.3447

Hence

[tex]pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}[/tex]

x=0.0115898

Volume of NaOH

V=0.0021072L

V=2.107mL

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For the reactants,

For the products,

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]

formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]

It is important to record all accidents and breakages that occur in the laboratory to prevent them from happening again.

Laboratory accident is defined as the type of accident that occurs in the laboratory leading to harm.

Example of laboratory accidents include the following:

A record of these type of laboratory accidents would hel prevent it's reoccurrence.

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The experimental absolute zero value is less when compared to the accepted value of absolute zero.

Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.

Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.

At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.

Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.

Therefore, the experimental absolute zero value is less when compared to the accepted value.

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Answer:

The experimental absolute zero value is less when compared to the accepted value of absolute zero.What is absolute zero?Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.Therefore, the experimental absolute zero value is less when compared to the accepted value.

Explanation:

The Correct option is A. octahedral

because the molecule has 6 sigma bonds that results into sp³d² hybridization.

and octahedral structure is formed

Answer:

Octahedral

Explanation:

You have a atom connected to 6 others and each of the bonds are similar

Answer/Explanation:

The boy's muscle energy changes into potential energy due to the height. it then converts into kinetic energy as it goes further upwards into the air.

Answer:

Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3

Explanation:

Not much of one

The possible action your solution might contain is amongst [tex]Ag^+[/tex], [tex]Pb^{2+}[/tex], or [tex]Ca^{2+}[/tex].

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

NaCl: 20 drops of NaCl were used and no precipitate was formed.

No precipitation formed means the [tex]Cl^-[/tex] cation is soluble in water. From your chart, you might see the halide of [tex]Ag^+[/tex] and [tex]Pb^{2+}[/tex] is insoluble in water, which means they should have formed precipitation but you didn't. This means there's less possibility it contains [tex]Ag^+[/tex] or [tex]Pb^{2+}[/tex], so we are left with only [tex]Ca^{2+}[/tex]. Let's confirm it with the rest.

[tex]Na_2SO_4[/tex] : 20 drops of [tex]Na_2SO_4[/tex] were used yellow precipitate was produced.

Even though all other sulfates form precipitation ( Insoluble in water)

[tex]Na_2CO_3[/tex] : 20 drops of sodium carbonate were used and the silver-blue precipitate was produced.

It seems all of their Carbonate is insoluble in nature. ( which is our case too ).

From the above result, only the reaction with NaCl was deemed to be decisive and it indeed contains [tex]Ca^{2+}[/tex] ions. Means you are correct.

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Answer:

1.46 moles NaCl

Explanation:

To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.

1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)

0.731 mole BaCl₂           2 moles NaCl
---------------------------  x  -------------------------  = 1.46 moles NaCl
                                         1 mole BaCl₂

If 0.731 mol of BaCl₂ is allowed to react with an excess of Na₂SO₄, 1.462  moles of NaCl will be produced.

The balanced chemical equation is:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

The mole ratio of BaCl₂  to NaCl is 1:2. This means that 1 mole of BaCl2 will produce 2 moles of NaCl.

Moles of BaCl₂  = 0.731 mol

Mole ratio BaCl₂:NaCl = 1:2

Moles of NaCl = 0.731 mol * 2 = 1.462 mol

If we have 0.731 moles of BaCl₂, then we will produce 2 * 0.731 = 1.462 moles of NaCl.

Therefore, 1.462 moles of NaCl will be produced.

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11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex]  gas measured at 1.3 atm pressure and 298 K

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

Moles = 0.3588 moles

Now,

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.3588 moles = \frac{mass}{32}[/tex]

Mass= 11.48 gram

Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K

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Answer:

It's a Ionic compound

Explanation:

To tell if CaO (Calcium oxide) is ionic or covalent (also called molecular) we look at the Periodic Table that and see that Ca is a metal and O is a non-metal. When we have a metal and a non-metal the compound is usually considered ionic.

Because we have a metal and non-metal in CaO there will be a difference in electronegativity between the metal and non-metal. This difference results in an electron(s) being transferred from the metal (lower electronegativity) to the non-metal (higher electronegativity). The results in the metal becoming a postitive ion and the non-metal a negative ion. The two opposite charges are attracted and form the ionic bond between atoms in Calcium oxide.

Answer:

= 64584.7176 g

or

= 64.5847 kg

Explanation:

From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.

We know that from Avogadro's constant,

1 mole of a substance contains 6.02 x 10²³ ions/atoms/units

Thus,

1 mole => 6.02 x 10²³ atoms

x moles=> 6.075 × 10²⁶ atoms

We cross multiply;

x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)

= 1009.1362 moles

1 mole of SO2 = 64 g

1009.1362 moles = ?

=>

[tex] \frac{1009.1362 \times 64}{1} [/tex]

= 64584.7176 g

= 64.5847 kg

The specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C

How to calculate specific heat?

The specific heat capacity of a metal can be calculated using the calorimetry equation as follows:

Q = mc∆T

Where;

Q = quantity of heat absorbed

m = mass of substance

c = specific heat capacity

∆T = change in temperature

mc∆T (water) = -mc∆T (metal)

84.7 × 4.18 × 3.8 = - (22.7 × c × -72.7)

1345.375 = 1650.29c

c = 0.815J/g°C

Therefore, the specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C.

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The concentration of sodium chloride in the solution is 5.72% (weight/volume percent).

Weight/volume percent concentration (w/v) expresses the amount of solute (in grams) dissolved in a given volume of solution (in milliliters). Specifically, it is defined as the weight of the solute divided by the volume of the solution, multiplied by 100.

To calculate the weight/volume percent concentration, we need to determine the mass of NaCl per volume of the solution.

First, we need to convert the volume of the solution from milliliters (mL) to liters (L):

67.8 mL = 0.0678 L

Next, we calculate the concentration of NaCl in grams per liter (g/L):

Concentration = Mass of solute ÷ Volume of solution

Concentration = 3.88 g ÷ 0.0678 L

Concentration = 57.2 g/L

Finally, we convert the concentration to weight/volume percent by multiplying by 100:

Weight/volume percent = Concentration x 100

Weight/volume percent = 57.2 g/L x 100

Weight/volume percent = 5.72%

Therefore, the concentration of NaCl in the solution is 5.72% (weight/volume percent).

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Answer:

6PbO +O2 --> 2Pb3O4

Explanation:

The question is incomplete I assume it is

PbO + 02 - Pb304

A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy without itself being consumed by the reaction.

Answer: Decide whether they have designed the best possible product.

Answer:

Explanation:

Mining:

    Mining is when certain substances are removed from the Earth, usually in large quantities. Mining can occur below the surface of the Earth via tunnels and caves. It can also occur at surface level through methods such as strip mining, which removes huge amounts of soil in the process

180.189 g was the mass of the zinc sample with a specific heat of zinc is 0.390 j/g°C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Using specific heat capacity formula here:

[tex]C_{Zn}[/tex] × [tex]m_{Zn}[/tex]×  Δ[tex]T_{Zn}[/tex] = [tex]C_{H_2O}[/tex]× [tex]m_{H_2O}[/tex] ×  Δ[tex]T_{H_2O}[/tex]

0.390J/g°C × [tex]m_{Zn}[/tex] ×77.4ºC = 4.184J/g°C×  65.0g ×  20.00ºC.

[tex]m_{Zn}[/tex] = 180.189 g

Hence, 180.189 g was the mass of the zinc sample.

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Answer:

[tex]\fbox {2 moles}[/tex]

Explanation:

Relation between grams of Carbon and moles :

[tex]\fbox {12 g Carbon = 1 mole}[/tex]

Multiply both sides by 2 :

⇒ 1 x 2 moles = 12 x 2 g

⇒ 2 moles = 24 g

Answer:

C. electricity conductive

This is because fall has more weather patterns which are repetitive than summer.

This is defined as the atmospheric condition of a particular place at a given period of time.

The repetitive weather patterns have various effects on the stars which is why they were studied.

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Answer:

4.43 g Fe

Explanation:

To find the mass of iron, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs because the given value (2.14) has 3 sig figs.

Molar Mass (Al): 26.982 g/mol

2 Al(s) + Fe₂O₃ --->  2 Fe(s) + Al₂O₃(s)

Molar Mass (Fe): 55.845 g/mol

 2.14 g Al           1 mole              2 moles Fe           55.845 g
----------------  x  -----------------  x  --------------------  x  ------------------  =  4.43 g Fe
                         26.982 g           2 moles Al             1 mole

Aluminum reacts with ferric oxide to produce iron by the thermite reaction. The mass of the iron metal that will be formed by the chemical reaction is 4.43 g Fe.

Limiting reagent has been described as reactions that are present in lesser amounts than the other reactant in the reaction that determines the amount of formation of the products and are never left in a reaction.

The balanced thermite reaction is given as:

2 Al(s) + Fe₂O₃ → 2 Fe(s) + Al₂O₃(s)

Molar mass of aluminium = 26.982 g/mol

Molar Mass of iron= 55.845 g/mol

Mass of aluminium (Al) = 2.14 grams

Here, according to the reaction 2 moles of Aluminum are needed to produce 2 moles of iron (Fe).

Moles of aluminum is calculated as:

Moles = mass ÷ molar mass

n = 2.14 ÷ 26.982

= 0.079 mol

As aluminum is the limiting reagent, it determines the formation of iron as:

2 mol Al = 2 mol Fe

0.079 mol Al = 0.079 mol Fe

Mass of iron is calculated as:

Mass = moles × molar mass

mass = 0.079 × 55.845 g/mol

= 4.411 grams

Therefore, 4.43 g Fe will be produced from 2.14 gm Al.

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