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What statement best compares photosynthesis and cellular respiration?
A. Both photosynthesis and cellular respiration break down sugars to release chemical energy.
OB. Photosynthesis breaks down sugars to release energy, while cellular respiration stores energy as sugars.
OC. Photosynthesis only takes place in the light, while cellular respiration takes place in the light and dark.
Both photosynthesis and cellular respiration take place during the light and during the dark.
D.
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Answers

Answer 1
C because you need sunlight to make food in photosynthesis.Cellular respiration is just breaking down energy so it can happen anywhere. Good luck on your homework :)

Related Questions

After implementing a solution to an environmental problem, environmental workers often continue to collect and analyze data associated with the problem area. Why is it important for public officials to follow through and check the results of implemented solutions to environmental problems?

Answers

It is important for public officials to follow through and check the results of implemented solutions to environmental problems because it helps ensure that the problem has been effectively addressed and that there are no unforeseen negative consequences.

Environmental problems can have significant impacts on human health, the economy, and the natural world. When a solution is implemented, it is important to determine whether it has been effective in addressing the problem.

Additionally, it is important to monitor the area to ensure that there are no unintended consequences. For example, if a chemical is used to treat contaminated soil, it is important to determine if the chemical has migrated to other areas and caused additional contamination.

By continuing to collect and analyze data, public officials can ensure that the solution was effective and sustainable in the long run. In summary, monitoring the results of implemented solutions is crucial for environmental management and protection.

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which of the following statements is correct? topographical occlusal radiographs yield a greater amount of information in the alveolar crest and apical areas than periapical radiographs. topographical occlusal radiographs may be exposed only on the maxillary arch. cross-sectional occlusal radiographs work best to image the maxilla. topographical occlusal radiographs cannot be used on children.

Answers

The correct statement is: Topographical occlusal radiographs yield a greater amount of information in the alveolar crest and apical areas than periapical radiographs therefore the correct option is A.

Topographical occlusal radiographs are special type of X-ray which allow the dentist to view an image of the entire mouth, including both structural and functional relationships between teeth, as well as any abnormalities or changes. The topographical technique focuses on a limited area of interest, such as a single tooth or few teeth,

and produces an image that shows detailed contours relating to that particular location. It can identify changes in the contour of the occlusal surface, which may reflect trauma or wear. It also helps to detect caries and other dental diseases related to wear and tear.

Hence the correct option is A.

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Units of distance on a computer's screen are measured in microns.


true


false

Answers

To help with your question about units of distance on a computer's screen.

Units of distance on a computer's screen are measured in microns.

Units of distance on a computer's screen are not measured in microns, but rather in pixels. Pixels are the smallest unit of display on a digital screen and represent a single point of light. Microns are a unit of length equal to one-millionth of a meter, and they are typically used for measuring very small objects, such as in scientific contexts. In summary, it is pixels that are used to measure distance on a computer screen, not microns.

Today's gaming graphics cards utilize a significant amount of memory made by Micron, most notably Nvidia's enthusiast-grade RTX 30-series GPUs.

Micrometer, often known as micron, is a unit of length in the metric system equal to 0.001 mm, or roughly 0.000039 inch. m is its symbol.

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Some people like to read books, while others like to watch or play sports. Clearly, everyone prefers some activities over others. Why do you think this is? Consider choices you make concerning your own entertainment. Why do you like to do the things you do? Why does it feel good to you to do them while they might not appeal as much to someone else? Do genetics play a part in your decisions?

Answers

The reasons why we enjoy certain leisure activities are complex and multifaceted. It is important to remember that there is no right or wrong way to spend one's free time, and we should embrace and celebrate our individual differences and preferences.

It is natural for people to have different preferences when it comes to their leisure activities. Some individuals may find enjoyment and fulfillment in reading books, while others may prefer watching or playing sports. These preferences can be shaped by a variety of factors such as personal experiences, cultural background, and individual temperament.

For me personally, I enjoy spending my free time reading books because it provides me with an opportunity to relax, learn new things, and escape from the stresses of daily life. However, these reasons may not resonate with someone who prefers a more active form of entertainment like sports.

Genetics may also play a role in our leisure activity preferences. For example, studies have shown that certain personality traits, such as extraversion and openness to experience, are partially influenced by genetics and may influence our attraction to certain activities.

Ultimately, the reasons why we enjoy certain leisure activities are complex and multifaceted. It is important to remember that there is no right or wrong way to spend one's free time, and we should embrace and celebrate our individual differences and preferences.

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Explain, using complete sentences, the trend in levels of blood glucose from 11:00 a. M. To 10:00 p. M.


In your answer use the following terms:


[Feedback mechanism] [stimulus] [response] [positive or negative]

Answers

The trend in levels of blood glucose from 11:00 a.m. to 10:00 p.m. can be explained using the feedback mechanism of homeostasis.

A steady internal environment is what the body is able to maintain through a number of feedback processes, which is known as homeostasis. Insulin and glucagon are the two hormones that control blood glucose levels. Glucagon raises blood glucose levels whereas insulin lowers them.

After breakfast, about 11:00 a.m., blood glucose levels rise as a result of the meal's carbs. Insulin is then released by the pancreas in response, assisting the body's cells in absorbing glucose from the bloodstream. Blood glucose levels consequently start to drop.

The feedback system of homeostasis continues to control blood sugar levels throughout the day. Insulin is secreted to lower blood glucose levels whenever they are too high. Glucagon is secreted to boost blood glucose levels when they fall too low.

Due to the stimulus of food and the body's reaction to it, blood glucose levels are normally lower by 10:00 p.m. after dinner than they were at 11:00 a.m. The body has the energy it needs to function effectively thanks to the feedback system of homeostasis, which has helped to keep blood glucose levels consistent throughout the day. Overall, this feedback mechanism is negative, reversing any departures from the set point in order to maintain a steady internal environment.

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Thomas is growing strawberries in the garden he has placed pools in a garden for his strawberry vines to grow on which response to stimuli will Thomas when is as a strawberry run begin to grow?

Answers

The response that Thomas will observe when the strawberry vine begins to grow is a positive tropism towards the pool.

A tropism is a directional growth response of a plant to a stimulus, and in this case, the stimulus is likely to be the availability of support and a growing medium for the strawberry vine.

The positive tropism response means that the strawberry vine will grow towards the pool and utilize the support and growing medium provided by the pool.

This is a natural response of plants to stimuli in their environment, and it ensures that they are able to access the resources necessary for their growth and survival.

Thomas can use this knowledge to strategically place pools or other supports in his garden to encourage the growth of his strawberry vines and optimize their yield.

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Tubular secretion involves the movement of substances
from capillary blood to tubular fluid.
from proximal convoluted tubule to distal convoluted tubule.
from tubular fluid to capillary blood.
from proximal convoluted tubule to glomerulus.

Answers

Tubular secretion involves the movement of substances from capillary blood to tubular fluid.

Tubular secretion is the process by which substances are transported from the capillary blood to the renal tubular fluid. This process occurs in various parts of the nephron, including the proximal convoluted tubule, the loop of Henle, and the distal convoluted tubule.

The substances that are secreted include hydrogen ions, creatinine, and certain drugs and toxins. This process is important for regulating the pH of the blood and eliminating waste products from the body.

The substances that are secreted are actively transported from the capillary blood into the tubular fluid through specialized transport proteins in the epithelial cells lining the tubules.

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pigeons in urban areas have darker feathers than pigeons in rural areas explain how this is an example of natural selection.

A. The amount of heavy metals found in urban and rural environments.

B. ALLELE FREQUENCY.


C. The impact of heavy metals on feather color.


E. How having darker feathers became so common in the urban pigeon population.

Answers

A


Prolly due mutation

which biome is known for being hot and moist with constant rain?

Answers

The biome that is known for being hot and moist with constant rain is: the tropical rainforest biome.

This biome is located around the equator, and it is characterized by high levels of precipitation, high humidity, and warm temperatures year-round.

The average temperature of this biome ranges from 68 to 93°F (20 to 34°C), and it receives between 60 and 400 inches (150 and 1000 cm) of rain per year.

Tropical rainforests are home to a wide variety of plant and animal species, many of which are found nowhere else in the world. The dense vegetation of this biome includes tall trees, shrubs, vines, and epiphytes, which form a complex and layered ecosystem.

The rich biodiversity of this biome provides numerous ecological services, including carbon sequestration, oxygen production, and water cycling.

However, tropical rainforests are also facing significant threats from human activities such as deforestation, mining, and agriculture, which are leading to the destruction of this important biome and the loss of countless species.

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During the spring of 2015, it was predicted that the number of chipmunk babies born increased by 20%. Data collected through observations confirmed this prediction. Chipmunks were seen scurrying all over the forest.



The availability of berries and flowers will vastly decrease.



The population of Red-Tailed Hawks will increase.



The amount of grass will decrease.



The bears will move out of the area, decreasing their numbers

Answers

While the increase in chipmunk babies born may seem harmless at first, it can have significant impacts on the ecosystem.

During the spring of 2015, there was a 20% increase in the number of chipmunk babies born, which was confirmed through observations. As a result, chipmunks were seen scurrying all over the forest. However, this increase in chipmunk population may have negative effects on the ecosystem. With more chipmunks, there will be increased competition for resources such as berries and flowers, leading to a decrease in their availability.

Additionally, the increase in the chipmunk population may cause the population of Red-Tailed Hawks to increase as they prey on chipmunks. As chipmunks consume more resources, the amount of grass in the area may also decrease. On a positive note, the increase in chipmunks may cause bears to move out of the area, which could ultimately lead to a decrease in their population.

Overall, while the increase in chipmunk babies born may seem harmless at first, it can have significant impacts on the ecosystem.

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What do you observe on the wall whan light strikes an object in the dark room?describe what you observed

Answers

When light strikes an object in a dark room, it casts a shadow on the wall. Depending on the shape of the object, the shadow will be a different size and shape.

Depending on the type of light, the shadow will also have different colors. For example, if the light is a normal white light, the shadow will be a dark gray or black. If the light is a colored light, the shadow will be a different color depending on the light.

For example, if the light is a red light, the shadow will be a deep red color. The intensity of the light will also affect the darkness of the shadow. The brighter the light, the darker the shadow will be. Therefore, the shadows on the wall can tell us a lot about the object that is being illuminated, as well as the type of light being used.

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I need help with alleles

Answers

Allelic and genotypic frequencies remain the same through generations in a population that is in H-W equilibrium. Frequency of dominant allele: 0.99. Frequency of recessive allele: 0.01. % homozygous dominant: 98%. % heterozygous: 2%. % homozygous recessive: 0.01%.

What is Hardy-Weinberg equilibrium?

The Hardy-Weinberg equilibrium is a theory that states that the allelic and genotypic frequencies in a population in equilibrium remain the same generation after generation.

Populations in H-W equilibrium are not evolving.

Assuming a diallelic gene,

The frequency of the dominant allele p(X) is pThe frequency of the recessive allele p(x) is q

The addition of the allelic frequencies equals 1

p + q = 1.

The genotypic frequencies after one generation are

p² (Homozygous dominant genotypic frequency), 2pq (Heterozygous genotypic frequency), q² (Homozygous recessive genotypic frequency).

The sum of genotypic frequencies equals 1

p² + 2pq + q² = 1

In the exposed example, the frequency of the homozygous recessive genotype is given.

frequency of the homozygous recessive genotype

q² = 1/10000 = 0.0001

From this information, we can get the frequency of the recessive allele by taking the root square of the value.

recessive allele frequency

p² = 0.0001

p = √0.0001

p = 0.01

Now, we can clear the equation p + q = 1 and the get recessive allele frequency.

dominant allele frequency

p + q = 1

p  + 0.01 = 1

p = 1 - 0.01

p = 0.99

Now, we can get the frequency of the homozygous dominant genotype and the heterozygous one.

frequency of the homozygous dominant genotype

p = 0.99

p² = 0.99²

p² = 0.98

frequency of the heterozygous genotype

2pq = 2 x 0.99 x 0.01

2pq = 0.019

p² + 2pq + q² = 1

0.98 + 0.02 + 0.0001 = 1

Frequency of dominant allele: 0.99Frequency of recessive allele: 0.01% homozygous dominant: 98%% heterozygous: 2%% homozygous recessive: 0.01%

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Please help me ;(

Match each system of equations with the constant that can be multiplied by equation A to create a system of equations that can be solved using the linear combination method.


Equation A: 3x – 2y = 5
Equation B: 9x + 7y = –34


Equation A: 3x – 4y = 5
Equation B: 7x + 8y = 4


Equation A: 13x – y = 51
Equation B: 12x + 3y = –90

Answers

To solve a system of equations using the linear combination method, the goal is to eliminate one variable by adding or subtracting the equations.

To do this, we need to find a constant that can be multiplied to one of the equations so that the coefficients of one variable will be the same or opposite in both equations.

For the first system, if we multiply equation A by 3, we get 9x - 6y = 15, which can be added to equation B to eliminate the y-variable. Thus, the constant for this system is 3.

For the second system, multiplying equation A by 2 gives 6x - 8y = 10, which can be added to equation B to eliminate the y-variable. Therefore, the constant for this system is 2.

For the third system, if we multiply equation A by 3, we get 39x - 3y = 153, which can be added to equation B to eliminate the y-variable. Thus, the constant for this system is 3.

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what would happen if the amount of freshwater entering mono lake decreased/increased using race?

Answers

Answer:  If the amount of fresh water entering mono lake decreased, the concentration of salinity increases and finally the lake would dry out. The opposite is true if more fresh waster entered the lake.

Explanation: The water in the lake is snowmelt and rainwater runoff from the mountains. It enters the lake through streams. Water can only remove by evaporation. When the water evaporates, the salts left behind.

So we can conclude that if the amount of fresh water entering mono lake decreased, the concentration of salinity increases and in the last the lake dry out.

What is the second leading cause of unintentional death for teenagers?.

Answers

The second leading cause of unintentional death for teenagers is motor vehicle accidents.

Motor vehicle accidents are a major cause of death and injury among teenagers in many countries. In the United States, for example, motor vehicle accidents are the leading cause of death for teenagers aged 16-19, and the second leading cause of unintentional death overall for this age group.

There are a variety of factors that contribute to the high incidence of motor vehicle accidents among teenagers. Inexperience, risk-taking behavior, and distractions such as cell phone use are all common factors. Alcohol and drug use also increase the risk of motor vehicle accidents among teenagers.

Preventing motor vehicle accidents among teenagers requires a multi-faceted approach, including education on safe driving practices, enforcement of traffic laws, and measures to discourage alcohol and drug use among young drivers.

New technologies, such as driver assistance systems and vehicle-to-vehicle communication, may also play a role in reducing the incidence of motor vehicle accidents among teenagers in the future.

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To maintain homeostasis, materials have to move across cell membranes. Some examples of these movements are listed below.

1. Amoeba consuming a bacterium
2. Somatic cell absorbing cholesterol from the blood
3. Brain neuron taking up glucose from the blood
4. Paramecium absorbing water from its surroundings
5. Pancreatic cell secreting insulin into the blood

Which three processes require the cell to spend energy?

A. 1, 2 and 5

B. 1, 3 and 5

C. 2, 3 and 4

D. 3, 4 and 5

Answers

Answer:

The three processes that require the cell to spend energy are typically those that move materials against their concentration gradient or require the cell to perform active transport. Based on this criteria, the correct answer is:

B. 1, 3 and 5

Explanation:

1. Amoeba consuming a bacterium requires energy as the cell engulfs the bacterium using its cell membrane.

2. Somatic cell absorbing cholesterol from the blood requires energy as the cell needs to move the cholesterol against its concentration gradient.

3. Brain neuron taking up glucose from the blood requires energy as the glucose needs to be transported against its concentration gradient.

Processes 4 and 5 do not require the cell to spend energy as the paramecium simply absorbs water from its surroundings (which is a passive process), and pancreatic cell secreting insulin into the blood is a facilitated diffusion process.

Complete the T-chart by categorizing each statement as an advantage or disadvantage of sexual reproduction.

Not all mutations are passed on.
It is time and energy consuming.
The reproduction process is slow.
It provides genetic variation.

Answers

Advantages:

It provides genetic variation.

Disadvantages:

Not all mutations are passed on.It is time and energy consuming.The reproduction process is slow.

Sexual reproduction is a process that involves the fusion of two gametes, usually from different parents, to form a new individual. This process has advantages and disadvantages. One of the main advantages is that it provides genetic variation, which increases the chances of survival of a species in changing environments. Genetic variation is important because it allows organisms to adapt to new environmental conditions, avoid predators, and increase their chances of reproduction.

However, sexual reproduction also has several disadvantages. For example, not all mutations are passed on, which means that some beneficial mutations may not be transmitted to the offspring. Additionally, sexual reproduction is a time and energy-consuming process that requires finding a mate, courtship rituals, and fertilization. Finally, the reproduction process is slow compared to asexual reproduction, which can produce many offspring quickly.

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The southern pine bark beetle lives in the bark of pine trees. The beetles feed on the tree and live within the bark of the tree, producing offspring. Once the beetles have infested a tree, they will spread to other trees in the same area. Eventually a pine tree infested by the beetle will die. The population of pine bark beetles can be expected to increase in a new habitat where it is introduced. The population would NOT be expected to decrease until what happens?

Group of answer choices


All the pine trees in the area have been killed off. Birds that feed on insects migrate away from the area


Other insects that feed on pine bark move out of the area. The pine trees in the area begin to produce seeds

Answers

The population of pine bark beetles introduced to a new habitat is not expected to decrease until all the pine trees in the area have been killed off.

The southern pine bark beetle lives in the bark of pine trees and feeds on the tree, producing offspring within the bark. Once a tree is infested by the beetles, it will eventually die.

The population of pine bark beetles will continue to increase in a new habitat as long as there are healthy pine trees for them to infest. Other factors, such as the migration of birds that feed on insects or the presence of other insects that feed on pine bark, may affect the population of pine bark beetles in the area, but ultimately the availability of healthy pine trees is the most important factor in determining the beetle population.

When all the pine trees in the area have been killed off, the population of pine bark beetles will have no more suitable habitat and will therefore decrease.

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Which of these statements best contrasts the dangers of working with cows versus horses?




Horses spook or startle quicker than cows do, but cows are more combative.



Cows tend to react as a herd, but horses react more quickly to danger.



Cows are more territorial than horses, but horses are more protective.



Horses are more naturally aggressive than cows, but cows weigh more

Answers

The statement that best contrasts the dangers of working with cows versus horses is :-Horses spook or startle quicker than cows do, but cows are more combative.

Horses are known to spook or startle easily, which can put handlers at risk of injury if they are not prepared to control the animal.

On the other hand, cows are generally less reactive but can be more combative when they feel threatened or cornered, which can also lead to dangerous situations for handlers.

This statement effectively contrasts the two animals' different types of danger, rather than simply comparing their natural aggression or protective instincts, which may not be as relevant to their behavior around humans.

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The Cori cycle is a metabolic pathway that involves active muscles and the liver. In the liver, fatty acids react to form C O 2 and H 2 O, releasing A T P, and lactate uses the A T P to form glucose in a process called gluconeogenesis. The glucose moves to the muscles to form lactate, releasing A T P, a process called glycolysis. The lactate then moves from the muscles to the liver to complete the cycle. Complete the sentences about the Cori cycle. Muscles break down into , which undergoes glycolysis. The end product of glycolysis in active muscles is , which is transported in the blood. The liver uses energy from to drive. The produced in the liver is transported to the muscle in the bloodstream. Answer Bank

Answers

The Cori cycle is a metabolic pathway that involves active muscles and the liver. The cycle begins when fatty acids are broken down in the liver, releasing carbon dioxide, water, and ATP.

This ATP is then used by the liver to form glucose in a process called gluconeogenesis. The glucose is then transported to the muscles, where it is broken down into lactate, releasing ATP in a process called glycolysis.

The lactate is then transported back to the liver, where it is used to generate more ATP to complete the cycle. The ATP generated in the liver is then transported to the muscle in the bloodstream, allowing the cycle to repeat. In this way, the Cori cycle allows for the efficient production of energy, which can be used for muscular activity.

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Construct an explanation of why the drought caused the lions' home range and movement patterns to change, using a claim-evidence-reasoning

Answers

Claim: The drought caused the lions' home range and movement patterns to change.

Evidence: During a drought, water and prey become scarce, forcing lions to expand their home range in search of resources. In some cases, lions may also move closer to human settlements or livestock to find food and water.

Reasoning: As the drought persists and resources continue to dwindle, the lions are forced to adapt their behavior to survive.

By changing their home range and movement patterns, the lions are able to increase their chances of finding food and water, even if it means encroaching on human territory.

This adaptation allows them to survive during the drought and maintain their population until conditions improve.  

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A) assume that you are going to a galapagos island to measure natural selection on morphology in a ground finch (geospiza fortis). you suspect that some morphological traits will determine whether the individual bird survives or dies in the upcoming dry spell (drought). is it a good research strategy to measure as many body traits as possible (wing length, leg length, body weight, tail length, etc.) or should a wise researcher just "bet" on a certain trait (for example, wing length) to be the key trait for surviving the drought? why or why not?

Answers

While measuring as many body traits as possible to determine the key trait for surviving a drought in ground finches may appear to be a good idea, it is better to focus on specific traits that are known to be important for survival in dry conditions.

When going to measure natural selection on morphology in a ground finch (geospiza fortis), it may seem like a good research strategy to measure as many body traits as possible to determine which trait is most important for survival during a drought. However, this approach could be time-consuming, costly, and may not provide the best results. Instead, a wise researcher should focus on specific traits that are known to be important for survival in dry conditions, such as beak size and shape, which can affect a bird's ability to feed on specific types of seeds.

By focusing on a specific trait, a researcher can also gain a better understanding of the ecological factors that drive selection in the population. This approach would allow for more precise predictions and could lead to a better understanding of how natural selection operates in this species. Furthermore, this approach could reduce the number of individuals required for the study, which would be important for conserving endangered populations.

In conclusion, while it may seem like a good idea to measure as many body traits as possible to determine the key trait for surviving a drought in ground finches, it is better to focus on specific traits that are known to be important for survival in dry conditions. This approach will provide a more focused and precise understanding of the ecological factors that drive selection in this population.

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Using the drop-down menus below, identify the processes cells use to maintain homeostasis.

A. is the movement of water along the concentration gradient.
B. is the use of energy to move particles against the concentration gradient.
C. is the movement of particles by diffusion without energy.
D. is the movement of particles along the concentration gradient.

Answers

The processes cells use to maintain homeostasis.

1. Osmosis 2. Active transport i3. Passive transport 4. Diffusion

What is homeostasis?

Homeostasis is the  an organism or system's ability to maintain a stable internal environmnt regardless of changes in the environment around it.

Orgaisms achieve homeostasis through the cordination of various physiological and bio-chemical mechanisms that work to maintain a constant balnce of parameters like temperature, pH, and blood sugar levels.

Homeostasis is vital in the survival and proper functioning of organisms.

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sally wants to lose weight by only eating rice for all her meals. explain why is not advisable for her to do so for a prolonged period time

Answers

Theres not a lot of nutritional value in just rice so she wouldnt be able to get all the vitamins and minerals she needs

The coracobrachialis muscle shares a common attachment with the:.

Answers

The coracobrachialis muscle is a small, triangular muscle located in the upper arm that has a common attachment with other muscles and bones in the shoulder joint.

Specifically, it shares a common attachment with the coracoid process of the scapula and the humerus bone in the arm. The coracoid process is a bony protrusion located on the scapula that provides attachment sites for several muscles, including the coracobrachialis.

The coracobrachialis muscle then extends downward to attach to the humerus bone near the middle of the arm. This muscle plays a role in arm flexion and adduction, and is innervated by the musculocutaneous nerve.

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The temperature of the areas surrounding santa catarina before each storm was about 13°c, and there was the same amount of water vapor in the air.

Answers

The temperature of the areas surrounding Santa Catarina before each storm was consistently around 13°C, and the humidity level remained constant with the same amount of water vapor in the air.

This data indicates that atmospheric conditions were generally consistent prior to each storm outbreak. It is crucial to note, however, that temperature and humidity are only two of many elements that influence the creation and intensity of storms. Aspects such as atmospheric pressure, wind speed and direction, and topography are also considered.The amount of energy available for a storm to start and evolve can be influenced by temperature and humidity levels, as warmer air can contain more moisture and generate instability in the atmosphere.

However, even with consistent temperature and humidity levels, other factors may come into play that trigger a storm event. It is also worth considering that the data provided may not be representative of the entire region, and there could be variations in temperature and humidity levels in other areas that may impact storm formation.

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Describe the function of each organelle.
Vacuoles

Answers

Answer:

In biology, a vacuole is an area of a cell that is devoid of cytoplasm, membrane-lined, and filled with fluid. Vacuoles are crucial cytoplasmic organs (organelles), particularly in protozoa (single-celled eukaryotic creatures), carrying out tasks such water storage, intake, digesting, excretion, and expulsion. Plant cells frequently have big core vacuoles, which allow them to grow large without acquiring the mass that would make metabolism challenging. Plants, fungi, algae, and certain other species also store potent secondary compounds in their vacuoles to shield the cell from self-toxicity, such as tannins or other biological colors.

BRAINLIEST :) Human height is a good example of polygenic inheritance. Assume that three genes control height. The capital


letter alleles (A, B and C) produce proteins that stimulate growth in skeletal muscles and bones. The lower case


alleles of these three genes (a, b & c) donât produce these proteins. A genotype with all capital genes (AABBCC)


has the maximum amount of protein for growing tall. A genotype with all lower-case allele (aabbcc) has no


capital letters, and would very short in stature. A genotype with three capital alleles and three lower case


alleles (AaBbCc) has a medium amount of protein and would be average height.


Cross the following genotypes: AABbCc x AaBbCC


28. List all of the possible genotypes that have at least 5 growth protein factors. What is the probability of


having a child that has 5 or more units of growth protein?


29. What is the least amount of capital letters an offspring could receive? What is the probability of having this type of individual?

Answers

Crossing the genotypes AABbCc and AaBbCC will result in a Punnett square with 16 possible offspring genotypes. To determine which of these genotypes have at least 5 growth protein factors, we need to identify those with at least 3 capital letters (A, B, or C).

28: These genotypes are: AABBCC, AABBCc, AABbCC, AABbCc, AaBBCC, AaBBCc, AaBbCC, and AaBbCc. The probability of having a child with 5 or more units of growth protein would be the sum of the probabilities of these 8 genotypes, which is 1/16 + 2/16 + 2/16 + 4/16 + 2/16 + 4/16 + 4/16 + 8/16 = 27/32 or approximately 0.84.

The least amount of capital letters an offspring could receive is zero. This would occur if the offspring received all lower case alleles from both parents (aabbcc). The probability of having this type of individual would be 1/16 or approximately 0.06. However, it's important to note that this genotype would result in a very short stature, as it lacks all growth protein factors.

29: In summary, when crossing AABbCc and AaBbCC, there are 8 possible genotypes that have at least 5 growth protein factors with a probability of 0.84. The least amount of capital letters an offspring could receive is zero with a probability of 0.06.

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(a) Identify ONE component of the sewage that is targeted for removal by primary treatment and ONE component of the sewage that is targeted for removal by secondary treatment. (b) For EACH of the pollutants that you identified in part (a), describe how the pollutant is removed in the treatment process. (c) Explain how sewage treatment plants create the solid waste problem that Dr. Goodwin mentioned in the article. (d) Two common methods of disposing of solid waste from sewage treatment plants are transporting it to a landfill or spreading it onto agricultural lands. Describe an environmental problem associated with EACH of these methods. (e) The final step in sewage treatment is disinfection. Identify ONE pollutant that is targeted during disinfection and identify ONE commonly used

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(a) One component of the sewage that is targeted for removal by primary treatment is suspended solids. Suspended solids refer to any solid particles that are present in the wastewater, including fecal matter, food scraps, and other debris. Primary treatment involves the use of physical processes, such as sedimentation, to remove these suspended solids from the water.

One component of the sewage that is targeted for removal by secondary treatment is biological oxygen demand (BOD). BOD refers to the amount of oxygen used by microorganisms as they break down organic matter in the wastewater. Secondary treatment involves the use of biological processes, such as activated sludge, to remove BOD from the water.

(b) For EACH of the pollutants that you identified in part (a), describe how the pollutant is removed in the treatment process:

(i) Suspended solids: Suspended solids are removed through physical processes, such as sedimentation. In sedimentation, the wastewater is allowed to stand in a basin or tank, and the heavy suspended solids settle to the bottom of the basin, where they can be removed.

(ii) Biological oxygen demand (BOD): BOD is removed through biological processes, such as activated sludge. In activated sludge, microorganisms are added to the wastewater, which consume the organic matter in the water and produce a sludge that can be removed from the water.

(c) Explain how sewage treatment plants create the solid waste problem that Dr. Goodwin mentioned in the article:

Sewage treatment plants create the solid waste problem because the biological processes used to remove pollutants from the wastewater produce a large amount of sludge. The sludge contains a mixture of bacteria, organic matter, and inorganic materials, and it must be removed from the water in order to meet discharge standards. The sludge is typically dried and dewatered, and then it is either transported to a landfill or spread onto agricultural lands.

(d) Two common methods of disposing of solid waste from sewage treatment plants are transporting it to a landfill or spreading it onto agricultural lands. Describe an environmental problem associated with EACH of these methods:

(i) Transporting the sludge to a landfill: One environmental problem associated with transporting the sludge to a landfill is that it can contaminate the soil and groundwater in the area where the landfill is located. Landfills are designed to contain the waste, but leaks can still occur, which can contaminate the surrounding environment.

(ii) Spreading the sludge onto agricultural lands: One environmental problem associated with spreading the sludge onto agricultural lands is that it can contaminate the soil and water resources in the area. The sludge can contain high levels of pathogens, nutrients, and other pollutants, which can harm the plants and animals that rely on those resources. Additionally, the sludge can leach into the soil and groundwater, which can contaminate the water supply.

(e) The final step in sewage treatment is disinfection. Identify ONE pollutant that is targeted during disinfection and identify ONE commonly used chemical for disinfection:

(i) The pollutant targeted during disinfection is pathogens. Pathogens are microorganisms, such as bacteria and viruses, that can cause disease in humans and animals. Disinfection is used to kill these pathogens in the water before it is released into the environment.

(ii) A commonly used chemical for disinfection is chlorine. Chlorine is added to the water to kill pathogens and other pollutants. However, chlorine can also be harmful to humans and the environment if not used properly.  

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A zygote has implanted itself in the uterine wall. This signifies the end of the _____ stage of development and the beginning of the _____ stage.

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Answer:

germinal, embryonic

Explanation:

i just know

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