27 - [ 38 - { 46 - ( 15 - 25) }]​

Answer:

For multiplication you added the exponents and for division you minus the exponents

Answer:

kdkdjdduidddsisiodiod

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Answer:

32 plates

Step-by-step explanation:

If the pottery class has 16 pounds  of clay and each student got 1/2 of a pound;

then;

1 plate = 1/2 pounds

xplate = 16pounds

Divide both expressions

1/x = 1/2÷16

1/x = 1/2*!6

1/x = 1/32

x = 32

Hence the student will make 32 plates

Answer:

2/5 *(5x+32)

Step-by-step explanation:

Answer:

x=47°

Step-by-step explanation:

..,........................

Answer:

I believe it is 47.  

Step-by-step explanation:  The reason why is because for a right angle it must be 90 degrees So, the way I solved this was getting 90-43 I got the 43 from BCD.  then subtracted it and applied it to the other side,  keep in mind I am only a freshman and it might be wrong super tiny chance but it might.  

This question is incomplete, the complete question is;

A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at liftoff (including its fuel) is m, the fuel consumed at rate r, and the exhaust gases are ejected with constant velocity v(sub e) [relative to the rocket]. A model for the velocity of the rocket at time t is given by the equation:

v(t) = -gt - v(sub e) ln [(m-rt)/m]

where g is the acceleration due to gravity, and t is not too large. If g = 9.8 m/s^2, m = 30,000 kg, r = 160 kg/s, and v(sub e)= 3000 m/s, find the height of the rocket one minute after liftoff.

Answer:

the height of the rocket one minute after liftoff is 14.8441 km

Step-by-step explanation:

Given the data in the question;

Velocity of the rocket at time t is;

v(t) = -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex])

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] = ₀∫⁶⁰(  -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex]) )dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] ₀∫⁶⁰In( [tex]\frac{m-rt}{m}[/tex]) dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] [ t In( [tex]\frac{m-rt}{m}[/tex]) + [tex]\frac{m}{r}[/tex] - t - mr[tex]\frac{1}{r^{2} }[/tex] In |m-rt| [tex]]^{60}_0[/tex]

= -g([tex][\frac{60^{2} }{2}][/tex]  - [tex]V_{e\\}[/tex] [ 60 (In(1 -  [tex]\frac{60r}{m}[/tex])-1) + [tex]\frac{m(In(m^{2})-In((m-60r)^2))) }{2r}[/tex] ]

we input our given values; g=9.8 m/s², m=30000 kg, Ve = 3000 m/s, r = 160 kg)

= -9.8([tex][\frac{60^{2} }{2}][/tex]  - 3000 [ 60 (In(1 - [tex]\frac{60(160)}{m}[/tex])-1) + [tex]\frac{30,000(In(30,000^{2})-In((30,000-60(160))^2))) }{2(160)}[/tex] ]

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 m

we convert to kilometer

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 ÷ 1000

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14.8441 km

Therefore, the height of the rocket one minute after liftoff is 14.8441 km

Answer:

33 boys

Step-by-step explanation:

Since 45% of the participants were female and there were a total of 80 students, 36 of the 80 students were female. That means that 44 of the students were male.

25% of 44 is 11. So there are 11 boys that are not employed. From there you can just subtract 44 - 11 and get 33.

33 boys are employed

Answer:

33 students

Step-by-step explanation:

Let's take this step-by-step. First, we know that the sample includes a total number of 80 high school students, and 45% of them are female.

This means that 55% of them are male students, which is required to answer the question. 80 × 0.55 = 44 male students.

Next, 25% of the male students are not employed. This means that 75% of the male students are employed. So, 44 × 0.75 = 33 male students.

Hope this helps! I had hw similar to this... so..

Answer:

kkk

Step-by-step explanation:

Answer:

1 hour 42 minutes

Step-by-step explanation:

Given :

Time table :

BRIGHTON _____ LONDON

0718 __________ 0900

0725 __________0832

0728 __________ 0848

Tine taken by the 0718 train :

Arrival time, London - Departure time

09:00 - 07:18

2 hours (60 - 18) minutes

Answer:

Cups at $3.20

Step-by-step explanation:

Gallon - $3.99

Quarts - $5,00

Pints - $5.20

Cups - $3.20

Answer:

X=3 y=-1

Step-by-step explanation:

X+y=2

X-y=4

so that means

y=X-4

substitute it in

X+X-4=2

2x-4=2

2x=2+4

2x=6

x=3

3+y=2

3+-1=2

y=-1

ways to check

3--1=4

double minus equal plus

3+1=4

Answer:

The answer would be 20.25 i think!

Step-by-step explanation:

Answer:

g o f = [tex]g(f(x)) = 32x^2 + 32x + 4[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 4x +2[/tex]

[tex]g(x) =2x^2 - 4[/tex]

Required:

Find g o f

This is calculated as:

[tex]gof = g(f(x))[/tex]

[tex]g(x) =2x^2 - 4[/tex]

So:

[tex]g(f(x)) = 2(4x+2)^2 - 4[/tex]

[tex]g(f(x)) = 2(4x+2)(4x+2) - 4[/tex]

[tex]g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4[/tex]

[tex]g(f(x)) = 32x^2 + 32x + 8 - 4[/tex]

[tex]g(f(x)) = 32x^2 + 32x + 4[/tex]

Answer: $73.8 15% of 60 is 9 and 8% of 60 is4.8 then if you add them all together you get 73.8$

Step-by-step explanation:

Answer:

$73.8

Step-by-step explanation:

(15+8)= 23 -> .23 = .23 times 60 = $73.8

Answer:

2x² + 13x + 15

Step-by-step explanation:

| 2x | 3

x | 2x*x = 2x² | 3*x = 3x

5 | 2x*5 = 10x | 3*5 = 15

We have, 2x² + 3x + 10x + 15

Combining like terms, we would have the final expression as:

2x² + 13x + 15

Answer:

x = 3

y = 4

Step-by-step explanation:

You need to get ridof the 2y so add the equations together:

3x - 2y = 1

*add

2x + 2y = 14  

5x + 0 = 15

5x = 15

*divide by 5

x = 3

Now that we have x we can find y by substituting

2(3) + 2y = 14

6 + 2y = 14

* subtract 6

2y = 8

*divide by 2

y = 4

Hope this helps :)

Answer:

David decorated the cookies at a faster rate than Colton.

Step-by-step explanation:

David decorated one cookie every 3 and 1/3 minutes. Colton decorated one cookie every 3.5 minutes. The way to find the answer to your question is by dividing the number of minutes by the number of cookies decorated.

Answer:

D

Step-by-step explanation:

1+3(6-3n)= -6-4n

1+18-9n= -6-4n

1+18+6= 9n-4n

25=5n

25/5=n

5=n

The 2 {} you have are called sets. The union is what the 2 sets have in all.

You can think of this as you have green blue yellow cards. and your friend have green orange red cards. What colors do you have if you combine your cards.

Now that's just an example, in the question's case is what numbers does the 2 sets have in total.

Therefore the union of these 2 sets are {9,10,11,13}

Hope it helps!

Step-by-step explanation:

(3×6) + (2×6)

= 18 + 12

= 30 in²

Answer:

2√5-4(3√5-2)

6√25-4√5-12√5+8

6(5)-16√5+8

30+8-16√5

38-16√5

Answer:

The answer is "0.30%"

Step-by-step explanation:

To assign employees to work, we have to select 6 out of 20 to do work, instead select 4 out of another 14 jobs, 2 to do, and 5 out of another 10 works 3. The other five were going to go do work four. They may decide how often ways of making each of these options. Their service would be how many forms to allocate those four positions to staff. The random sample is from the height.

There are equally estimated that numbers of arrangements with both the four in Job 1.They then allocate all four to work 1. In this situation We must then select 2 out from the 16 existing spaces in job 1, 4 out from the 14 remaining spaces in job 2, 5 out of the 10 existing spaces in job 3 as well as the ones remaining in job 4.

The possibility of any four being at 1 is that they've been all divided by the overall amount of circumstances in 1 task.

[tex]\to \frac{[ \frac{16!}{(2!4!5!5!)}]}{[\frac{20!}{(6!4!5!5!)}]}\\\\\to [ \frac{16!}{(2!4!5!5!)}] \times [\frac{(6!4!5!5!)}{20!}]\\\\\to [ \frac{16!}{(2!)}] \times [\frac{(6!)}{20!}]\\\\\to [ \frac{16!}{(2!)}] \times [\frac{(6\times 5 \times 4 \times 3 \times 2!)}{20!}]\\\\\to 16! \times [\frac{(360)}{20 \times 19 \times 18 \times 17 \times 16!}]\\\\\to \frac{(360)}{20 \times 19 \times 18 \times 17 }\\\\\to \frac{(360)}{20 \times 19 \times 18 \times 17 }\\\\\to \frac{360}{116,280}[/tex]

[tex]\to 0.00309597523 \approx 0.30 \%[/tex]