. 2. Which has more atoms: 2.5 mol of calcium carbonate,

CaCO3, or 3.5 mol of calcium hydroxide, Ca(OH)2

Answers

Answer 1

Answer:

Calcium hydroxide has more atoms.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rules of three:

If 1 mole of calcium carbonate represents 6.023*10²³ atoms, 2.5 mole of calcium carbonate represents how many atoms?

[tex]amount of moles of calcium carbonate=\frac{2.5 moles*6.023*10^{23} atoms}{1 mole}[/tex]

amount of moles of calcium carbonate= 1.50575*10²⁴

If 1 mol of calcium hydroxide represents 6.023*10²³ atoms, 3.5 mol of calcium hydroxide represent how many atoms?

[tex]amount of moles of calcium hydroxide=\frac{3.5 moles*6.023*10^{23} atoms}{1 mole}[/tex]

amount of moles of calcium hydroxide= 2.10805*10²⁴

2.10805*10²⁴ is greater is 1.50575*10²⁴, so calcium hydroxide has more atoms.


Related Questions

Why can water birds drown if they still have detergent on their feathers?

Answers

Maybe cause the detergent wash’s off lol

How many grams in 4.5 moles of H2O?

Answers

the are 18.01528 grams

.....

What is the specific heat of ethanol if 4650 j are required to raise the temperature of 250.0g of ethanol from 22.0oc to 29.6 degrees Celsius

Answers

Answer:

[tex]C=2.45\frac{J}{g\°C}[/tex]

Explanation:

Hello there!

In this case, since the thermodynamic definition of heat in terms of mass, specific heat and temperatures is given by:

[tex]Q=mC(T_2-T_1)[/tex]

We are to calculate the specific heat of the ethanol as shown below:

[tex]C=\frac{Q}{m(T_2-T_1)}[/tex]

Thus, by plugging it the given data we can obtain:

[tex]C=\frac{4650J}{250.0g(29.6-22.00\°C)} \\\\C=2.45\frac{J}{g\°C}[/tex]

Regards!

Fill in the blank with the molar mass of calcium
nitrate. A link to the periodic table is provided for you.
g/mol

Answers

Answer: 61.98 is correct

Explanation:

Molar mass of calcium nitrate is 164  g/mole which is obtained by adding atomic weights of constituent elements.

What is molar mass?

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.

Molar mass of calcium nitrate =40+[14+(16×3)]×2=164 g/mole.

Thus, the molar mass of calcium nitrate is 164 g/mole.

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How many oxygen atoms are in 3.45 mol CaCO3

Answers

Answer:

The formula tells us that each mole of CaCO3 contains 3 moles of Oxygen. Then 3 moles of CaCO3 would contain 3 X 3 or 9 moles of Oxygen. I mole is define as avogadro’s number of units. Avogadro’s number is 6.02 X 10^23. so the answer is 3 X 3 X 6.02 X 10^23. = 5.42 X 10^24

What final temperature will be attained by a 250. g sample of Cu at 20.0oC if it absorbs 1000 J of heat? Cu 's c = 0.39 J/(g oC

Answers

Answer:

30.26 °C

Explanation:

From the question,

Q = cm(t₂-t₁)................ Equation 1

Where Q = Heat, c = specific heat capacity of Cu, m = mass of Cu, t₁ = Initial temperature, t₂ = Final temperature.

Given: Q = 1000 J, c = 0.39 J/g.°C, t₁ = 20°C, m = 250 g

Substitute into equation 1 and solve for t₂

1000 = 250×0.39(t₂-20)

250×0.39(t₂-20) = 1000

97.5(t₂-20) = 1000

(t₂-20) = 1000/97.6

(t₂-20) = 10.26

t₂ = 10.26+20

t₂ = 30.26 °C

How many atoms is 500.0 moles of pure gold?

Answers

Answer:

2.5385 mol

Explanation:

do a quick conversion : 1 grams gold = 0.0050770041918285 mole using ...powered by AnyClip. 1 ... 500 grams gold to mol = 2.5385 mol

Identify the acid, base, and salt in the following reaction

HNO3 + KOH —> H2O + KNO3

Answers

Explanation:

acid ,HNO3

base,KOH

salt ,KNO3

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!

Answers

D, the speed remains constant.

A student transfers a gas at STP from a 11.0 L tank to a 25.0 L tank. If the pressure
remains constant, what is the new temperature?

Answers

. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure

Answer:620 k

Explanation:

The outermost layers of the Earth are warm compared to the Earth's core.

[ ]False
[ ]True​

Answers

Answer:

I am not sure this one is False.

Explanation:

Answer:

False

Explanation:

This is false because the outer part of earth is cooler than the inner. For example, the inner is filled with lava, and all kinds of stuff, so this is technically saying that the outer is much cooler, It has dirt, and dirt can be cool.

Please help!! I have 10 minutes left!!

Answers

Explanation:

1 is a process that occurs when gases in earth's atmosphere trap the sun's heat .

2 . heat in the atmosphere to warm the planet .

I only know the first too sorry ✨

The volume and amount of aflium gas remains constant.
Under these conditions, aflium gas has an initial pressure of
635 torr when it is at 67.0°C. What is the new temperature if
the pressure drops to 250 torr?

Answers

Answer:

133.85 K

Explanation:

Initial pressure, P₁ = 635 torr

Initial temperature, T₁ = 67.0°C = 340 K

Final pressure, P₂ = 250 torr

We need to find the new temperature. The relation between temperature and pressure is given by :

[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{250\times 340}{635}\\\\T_2=133.85\ K[/tex]

So, the new temperature is equal to 133.85 K.

9) What is the density of the gold rock with a mass of 386 grams and has a volume of 20 cubic centimeters?
O 0.193 g/cc
O 193 g/cc
O 1.93 g/cc
19.3 g/cc

Answers

Answer:

density= mass/volume

hence density of gold rock

= 386/20

=19.3 g/cc

Answer all of these questions about the molecule glucose in order

i. the name of the molecule.
ii. the names of the different atoms that make up the molecule, and the color you chose for each of them.
iii. the state of the molecule (i.e., solid, liquid, or gas).
iv. any units of the molecule that repeat.
v. the type of bonds in the molecule, based on the molecule’s chemical formula.
vi. the characteristics of the substance, based on whether it is an ionic compound or a covalent compound (you may need to do additional research to find this information).

Answers

Iv. Any units of the molecule that repeat

how many grams of chromium are needed to react with of cuso4 to produce 10.2g cu

Answers

Answer:

14.7 g of chromium

Explanation:

3. Determine the pH of each of the following solutions. (Hint: See Sample Problem B.) a. 1.0 x 10-2 M HCI c. 1.0 x 10-MHI b. 1.0 x 10-3 M HNO3 d. 1.0 x 10-M HB​

Answers

Answer:

a. pH = 2 b. pH = 3 c. pH = 1 d. Unanswerable

Explanation:

pH = -log[H+] OR pH = -log{H3O+]

                    and inversely

pOH = -log[OH-]

1. Determine what substance you are working with, (acid/base)

2. Determine whether or not that acid or base is strong or weak.

a. 1.0 x 10^-2M HCl

HCl is a strong acid, therefore it will dissociate completely into H+ and Cl- with all ions going to the H+, therefore, the concentration of HCl and concentration of H+ are going to be equal, meaning we simply take the negative logarithm of the concentration of HCl and that would equal pH

pH = -log[H+]

pH = -log(1.0x10^-2)

pH = 2

b. 1.0 x 10^-3M HNO3

HNO3 like part a, is a strong acid, therefore it would simply require you to take the negative logarithm of the concentration of the compound itself, to find its pH.

pH = -log[H+]

pH = -log(1.0 x 10^-3)

pH = 3

c. 1.0 x 10^-1M HI

Like the previous parts, HI is a strong acid

pH = -log[H+]

pH = -log(0.10)

pH = 1

d. HB isn't an element, nor is it a compound so that would be unanswerable.

Right balanced chemical equations, complete ionic equations, and net ionic equations for the reactants below. Include a description of what you did while going through your solving.

1. HgI2+PbSO4

2. Sodium carbonate and calcium react in a single replacement, one of the resulting products immediately decomposes. (you should end up with one balanced equation - 3 product)

3. CaS + Al

Answers

I haven't learned this yet but my friend did I'll text them and get back to you with the answer in a bit brb!

IF the heat involved in a chemical reaction has a positive sign,

Answers

Answer: more explaintion

Explanation:



10. How many moles of glucose are in 0.5L of a 0.138M solution of glucose in

water?

Answers

Answer:

0.069 moles of glucose

Explanation:

(0.138 mol/L)(0.5 L) = 0.069 moles of glucose

Answer:

[tex]\boxed {\boxed {\sf 0.069 \ mol \ C_6H_12O_6}}[/tex]

Explanation:

Molarity is the moles per liter of a solution. It is found by dividing the moles of solute (glucose) by the liters of solution (water).

[tex]M= \frac {moles}{liters}[/tex]

We know the molarity is 0.138 M. 1 M is equal to 1 mole per liter, so we can rewrite the molarity as 0.138 moles per liter.

There are 0.5 liters of solution.

We are solving for the moles, so we can use x.

[tex]0.138 \ mol/L= \frac {x }{0.5 \ L}[/tex]

We must isolate the variable (x) to solve for the moles. It is being divided by 0.5 liters. The inverse operation of division is multiplication. Multiply both sides of the equation by 0.5 L.

[tex]0.5 \ L *0.138 \ mol/L= \frac {x }{0.5 \ L}* 0.5 \ L[/tex]

The liters on both sides cancel.

[tex]0.5 *0.138 \ mol= {x }[/tex]

[tex]0.069 \ mol =x[/tex]

[tex]0.069 \ mol \ C_6H_12O_6[/tex]

Ther are 0.069 moles of glucose in a 0.138 M solution with 0.5 liters of water.

How many moles are in 3.25 x 1025 molecules of H2O?

Answers

Answer:

[tex]27.72 g[/tex]

Explanation:

The relationship between the number of particles and the number of mole of a substance is given by the equation  N = n L ; where  N is the number of particles, n  is the number of mole, and  L  is Avogadro's constant.

Phosphoric acid is delivered to a drinks factory in
concentrated form. Why do you think the acid is not
diluted before transporting it?

Answers

Answer:

Because it might be reactive or may lose its property in liquid form..

With the dilution of phosphoric acid, its volume will increase. To avoid the transport cost the acid might not be diluted before transporting.

What is the food additive?

Food additives are the chemicals that are used in food products, that prevent food from spoiling due to bacterial growth.

Food additives are a kind of food preservative that is added to food products to prevent spoilage and retain their nutritional value for a long time. These additives inhibit microbial growth in food.

Different types of food additives are preservatives, nutrients, sweeteners, flavoring agents, antioxidants, and colorants.

Phosphoric acid acts as a preservative and prevents the growth of mold and bacteria in foods with sugary solutions. This increases the shelf life of that beverage and improves affordability.

Learn more about food additives, here:

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You use 50.00 mL of a 12.0 M solution of HCl solution to make a 500.00 mL solution. What is the concentration of the new solution? *

Answers

Answer:

1.2 M

Explanation:

If you use the dilution equation (M1V1=M2V2), you end up with (50)(12)=(500)(M2), and when you solve for M2 you get 1.2 M.

How many milliliters of a 3.28 M copper (II) nitrate Cu(NO3)2
solution are needed to provide a total of 146.59 g of Cu(NO3)2?
Use 187.56 g/mol as the molar mass of solute. Solve your answer
to two decimal places.

Answers

Answer:

237.80mL

Explanation:

Molarity of a solution can be calculated using the formula;

Molarity = number of moles (n) ÷ volume (V)

However, we first need to calculate the number of moles of Cu(NO3)2 by using the formula:

moles = mass/molar mass

Molar mass of Cu(NO3)2 = 187.56 g/mol

moles = 146.59 ÷ 187.56

moles = 0.782moles

Molarity = n/V

3.28 = 0.78/V

V = 0.78/3.28

V = 0.2378L

In milliliters (mL), 0.24 litres = 0.24 × 1000

= 237.80mL

The compound calcium carbonate contains the calcium ion (Ca2+) and the polyatomic carbonate ion (CO32-). Explain why calcium carbonate is considered to be an ionic compound when it contains both ionic and covalent bonds.

Answers

Answer:

Because of the electronegativity difference C-O (covalent) and Ca-O (ionic) bonds have.

Explanation:

Hello there!

In this case, in order to understand the polarity of this compound, calcium carbonate, it firstly necessary that it is comes from the definition of electronegativity, as a property defining the capacity to attract electrons from another atom; thus, since the electronegativities of calcium, carbon an oxygen are 1.0, 2.55 and 3.44, it is possible to realize this compound has O-Ca and O-C bonds according to its Lewis dot structure. In such a way, we calculate the difference electronegativity for these two bonds:

[tex]\Delta E_{O-Ca}=3.44-1.0 = 2.44\\\\\Delta E_{O-C}=3.44-2.55=0.89[/tex]

Thus, since 2.44 accounts for an ionic bond and 0.89 for a covalent one, we bear out the given statement in the question.

ionic bounds are quite weak and will break easily? T or F​

Answers

Answer:

False

Explanation:

Ionic bonds are actually strong, but unfortunately can be broken easily

Please help, I'm so confused!!!!

Answers

Answer:

[tex]\boxed {\boxed {\sf N_2}}[/tex]

Explanation:

Let's examine this reaction, especially the coefficients.

[tex]N_2+3H_2 \rightarrow 2NH_3[/tex]

First of all, remember that reactants are used to make the product. They are found on the left of the arrow usually. Therefore, N₂ and H₂ are the reactants, while NH₃ is the product. We can automatically eliminate NH₃ from our answer choices, because it is simply not a reactant.

Next, look at the coefficients.

N₂ has no coefficient, so a 1 is implied. H₂ has a coefficient of 3.

Therefore, for the reaction to work, there must be 1 mole of N₂ and 3 moles of H₂.

We have 3.2 moles of N₂ and 5.4 moles of H₂.

Divide each amount given by the required amount for completion.

3.2 mol N₂/ 1 mol N₂= 3.2 times 5.4 mol H₂/ 3  mol H₂=1.8 times

Therefore, there is enough nitrogen to complete the reaction 3.2 times, but only enough hydrogen for 1.8 times. If everything is completely reacted, we will run out of hydrogen and have excess nitrogen.

How
many
moles of water are produced from 12.8 moles of oxygen?
with work

Answers

Answer:

12.8 moles

Explanation:

The formula for water is H2O, so for every mole of water, there are two moles of hydrogen and one mole of oxygen.

As the ratio of oxygen particles to water particles is one to one, 12.8 moles of oxygen are required to produce 12.8 moles of water.

Therefore, 12.8 moles of water are produced from 12.8 moles of oxygen (assuming hydrogen is available in excess).

How does weather impacts our lives

Answers

Answer:

Weather affects us in a huge number of ways. Climate influences the growth of crops, thus affecting the availability and kind of food we eat. Fluctuations in weather (e.g. dry spells, wet spells) also affect crops. Weather affects what clothes we wear.

Explanation:


URGENT PLS I NEED THIS OR I WILL FAIL AND HAVE TO DO SUMMER SCHOOL

Carbon monoxide gas and oxygen gas combine to form carbon dioxide
gas in the following equation:
2CO(g) + O2(g) → 2CO2(g)
The enthalpy value for gaseous carbon monoxide is -110.5, and gaseous
carbon dioxide is -393.5, calculate the enthalpy change (AH) for the
reaction.



Answers

Answer:

ΔHr = -566kJ/mol

Explanation:

Based on Hess's law, the ΔH of a reaction is the sum of the ΔH's of products times its coefficient subtracting the ΔH of reactants. For the reaction:

2CO(g) + O2(g) → 2CO2(g)

ΔH is:

ΔHr = 2*ΔH CO2 - (2ΔH CO + ΔH O2)

As ΔH CO2 = -393.5kJ/mol; ΔH CO = -110.5kJ/mol and ΔH O2 = 0kJ/mol

ΔHr =  2*-393.5kJ/mol - (2*-110.5kJ/mol)

ΔHr = -566kJ/mol
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