2 MnO4−(aq) + 10 Cl−(aq) + 16 H+(aq) → 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l) Oxidizing agent: Reducing agent:

Answers

Answer 1

Answer:

MnO4 is the oxidizing agent.

Cl is the reducing agent.

Explanation:

To know which is oxidizing agent and which is reducing agent, let us calculate the change in oxidation number of each element in the equation below:

2MnO4−(aq) + 10Cl−(aq) + 16H+(aq) → 5Cl2(g) + 2Mn2+(aq) + 8H2O(l)

Please note:

1. The oxidation state of oxygen is always –2 except in peroxide where it is –1

2. The oxidation state of Hydrogen is always +1 except in hydrides where it is –1

3. The oxidation state of chlorine is always –1

For Mn:

At left hand side

MnO4 = –1

Mn + 4O = –1

O = –2

Mn + (4 x –2) = –1

Mn – 8 = –1

Collect like terms

Mn = –1 + 8

Mn = +7

At the right hand side, Mn is +2.

The oxidation state of Mn changes from +7 to +2.

For Cl:

At the left hand side

Cl = –1

At the right hand side

Cl = 0

The oxidation state of Cl changes from – 1 to 0.

The oxidation state of O and H are unchanged.

Since the oxidation state of Mn changes from +7 to +2 i.e reduced, MnO4 is the oxidizing agent.

Since the oxidation state of Cl changes from – 1 to 0 i.e increase, Cl is the reducing agent.


Related Questions

Ashley notice that the mineral appear metallic under the light. What property was actually measuring?

Answers

Answer:  The property is called Luster

Explanation:

Luster is a term used to describe the appearance of  light from the surface of the mineral when it reflects light. The two types of classification of Luster is Mettalic or Non Mettalic.

some examples of minerals with mettalic lustre are --- Galena, graphite, Gold, Silver, Copper etc

Some examples of minerals with non mettalic lustre are--- Barite, Serpentine, Fluorite etc.

Answer:

Lustrous property

Explanation:

Materials like metals that have lustre usually glow or display sheen when light comes in contact with the surface of the material.

It is derived from the Latin word "lux" meaning "light", which is indicative of radiance or gloss.

Lustre is a common property of metals, including sonourousity, malleability and ductility amongst others.

Explain why airborne and water-borne chemicals are both local and global issues.

Answers

Airborne and water-borne chemicals are both local and global issues because they may be in high concentration near the source (locally) where they can do much damage to the environment. However, they can travel long distances so that chemicals produced in one country can have a harmful effect in another country.

Based on its location on the periodic table, how many electrons does nitrogen have in its outer energy level?

Answers

Answer:

its 5 got it right

The active ingredient in many commercial liquid bleaches is sodium hypochlorite. The bottle lists the percentage of sodium hypochlorite as 6.0%. If the density of commercial bleach is 1.084 g/mL, how many mL of 0.150 M sodium thiosulfate is required to reach the end point in a titration similar to the one performed in this experiment, if a student analyzed a 2.0 mL sample of bleach.

Answers

Answer:

23.3mL of 0.150M sodium thiosulfate

Explanation:

The  net reaction of sodium hypochlorite (NaClO) with sodium thiosulfate (Na₂S₂O₃) is:

NaClO + 2 Na₂S₂O₃ + 2H₃O⁺ → NaCl + 3 H₂O  +  Na₂S₄O₆ + 2 Na⁺

2.0mL of the sample of bleach are:

2.0mL ₓ (1.084g / mL) ₓ (6 / 100) ₓ (1 mol / 74.44g) = 1.75x10⁻³ moles of NaClO

As 1 mole of NaClO reacts with 2 moles of thiosulfate:

1.75x10⁻³ moles of NaClO ₓ (2 mol Na₂S₂O₃ / 1 mol NaClO) =

3.50x10⁻³ moles of Na₂S₂O₃

If you have a 0.150M solution of thiosulfate, mL of this solution you need to reach the end point of the titration are:

3.50x10⁻³ moles of Na₂S₂O₃ ₓ (1L / 0.150mol) = 0.0233L =

23.3mL of 0.150M sodium thiosulfate

Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 374 mL. Express your answer to three significant figures.

Answers

Answer:

Explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me...

True or False: reactions in which the oxidation state of an element decreases are reduction processes

Answers

Answer:

False; An oxidation-reduction is any chemical process that involves any chemical process in which elements undergo changes in oxidation number. hope that helps love!

A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
significant figures when answering this question.

Answers

Answer:

1.3223 acres

Explanation:

a football field's area is 360 feet (120 yards) x 160 feet (53.333 yards) = 57,600 sq. feet

if the area of an acre is 43,560 sq. feet, then a football field in acres = 57,600 sq. feet / 43,560 sq. feet = 1.3223 acres

we can verify our answer by doing the same calculation in sq. yards:

football field = 120 yards x 53.33 yards = 6,400 sq. yards

an acre is 4,840 sq. yards

football field in acres = 6,400 sq. yards / 4,840 sq. yards = 1.3223 acres

The area of the field is 1.3223 acres

From the question given above, the following data were obtained:

Dimension = 120 yard × 53.333 yard

Area =?

The area of the field can be obtained as follow:

Area = Dimension

Area = 120 yard × 53.333 yard

Area = 6399.96 yard²

Finally, we shall convert 6399.96 yard² to acre. This can be obtained as follow:

4840 yard² = 1 acre

Therefore,

6399.96 yard² = 6399.96 / 4840

6399.96 yard² = 1.3223 acres

Thus, the area of the field is 1.3223 acres

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A certain atom has 22 protons and 19 electrons. This atom loses an electron. The net charge on the atom is now ___.If this same
atom with 22 protons and 19 electrons were to gain 3 electrons, the net charge on the atom would be ____

Answers

Answer:

I think first one has net charge 4+

second one has earlier 3+ charge after gaining net charge becomes zero

I think this is correct

Explanation:

if wrong means pls correct me bro

An atom has 22 protons and 19 electrons. The net charge on the atom is now elementary, 1e+. If the same atom with 22 electrons and 19 electrons were to gain 3 electrons, the net charge on the atom would be, negative, -3.

What are electrons?

Electrons are the positively charged particles that revolve around the negatively charged nucleus. Electrons revolve around the nucleus, and protons and neutrons are also present.

When the electrons gain electron they acquire negative charge and when they donate electrons it acquires positive charge.

It gains 3 electrons that why -3 charge.

Thus, the correct elementary charge, negative, -3.

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The force that moves sediment in a landslide or mudflow is _.

Answers

Answer:

Erosion.

Explanation:

Erosion is the act of loose soil crumbling under itself and causes it to slide down a hill.

Answer:

erosion

Explanation:

Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) chloride precipitate. What was the molar concentration of chloride ions in the solution (in mol/L)?

Answers

Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

A gas sample has a pressure of 2.65 atm when the temperature is -18 ∘C. What is the final pressure, in atmospheres, when the temperature is 39 ∘C, with no change in the volume or amount of gas?

Answers

Answer:

P₂ = 3.24atm

Explanation:

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 1.83 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 22.08 mL. What volume of base was required for the titration?

Answers

Answer:

20.25 mL.

Explanation:

The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.

i.e Final volume - initial volume

= (22.08 - 1.83)mL

= 20.25 mL.

(Repeat and average volume results for accuracy.)

Why LDL called "bad" cholesterol?​

Answers

Answer:

Its called bad cholesterol because a high LDL level leads to  buildup of cholesterol in your arteries.

Explanation:

Identify which subatomic particles match each of these descriptions. One of the descriptions describes two particles. Make sure to include both particles it describes.

Description Particle(s)
have a relative charge of +1
have a relative charge of −1
have no charge
located in the nucleus of an atom
have a much lower mass than the other two types of particles

Answers

Explanation:

First off, it's important to know that the three subatomic particles we have are the proton, neutron and electron.

have a relative charge of +1 : This is the proton. It is the postive subatomic particle present in an atom.

have a relative charge of -1 : This is the electron. It is the negative subatomic particle present in an atom.

have no charge : This is the neutron. It is the neutral subatomic particle present in an atom.

located in the nucleus of an atom : Twoo subatomic particles are located in the nucleus, the neutron and proton.

have a much lower mass than the other two types of particles: This is the electron. The proton and neutron are almost similar in mass. The electron is abut 1 / 1840 times the mass of the proton.

The number of cubic centimeters (cm) in 20.6 mL is
A) 0.0206 cm
B) 2.06 cm
I
C) 20.6 cm
D) none of these

Answers

Answer:

c

Explanation:

1 [tex]cm^{3}[/tex] = 1 mL

20,6 mL = 20,6 [tex]cm^{3}[/tex]

Answer:

C-20.6 cm^3

Explanation:

Cubic centimeters directly correspond to mL. Thus the answer would be the same as the mL


Which of the following is a characteristic of the lanthanides?
O A. They are silvery metals that conduct electricity.
B. There are no known uses for the metals.
C. They are all radioactive.
D. They are used in making fireworks

Answers

Answer:

A

Explanation:

Lanthanides share the following common properties: Silvery-white metals that tarnish when exposed to air, forming their oxides. Relatively soft metals. Hardness increases somewhat with higher atomic number.

Answer:

APEX

Explanation:

A

There is a container on the lab bench containing some unknown chemical. You should:
a. Dump it, wash the glassware. Some people are slobs.
b. Move it out of the way in case it is dangerous. Otherwise, not your problem.
c. Leave it. The rightful owner will claim it eventually.
d. Tell your lab supervisor.

Answers

Answer:

D

Explanation:

Your supervisor is in charge of you so therefore you must always tell your supervisor first.

Answer:

C.

Explanation:

Because you might get hurt, could be dangerous.

Explain why the benzene molecule usually reacts with electrophiles

Answers

Answer:

Explanation:Because of the delocalised electrons exposed above and below the plane of the rest of the molecule, benzene is obviously going to be highly attractive to electrophiles - species which seek after electron rich areas in other molecules.

Answer:

Benzene has a pi electron system that is electron rich.

Electrophiles are molecules that are attracted to electron rich molecules as they are electron deficient in order to form a more stable complex.

Hence, as benzene is electron rich, electrophiles will be attracted to it.

7. Which molecular solid would have the lowest boiling point?

a. One that has hydrogen bonding

b. One made of molar molecules

c. One with dipole-dipole attractions

d. One with induced dipole attractions

Answers

Answer:

The molecular solids would have the lowest boiling point because of WEAK INTERMOLECULAR FORCES.

Explanation:

Answer: One with induced dipole attractions

A balloon is cooled by removing 0.784 kJ of heat. It shrinks on cooling, and the atmosphere does 655 J of work on the balloon. Calculate the change in internal energy, ∆E, of the system.

Answers

Answer:

The correct answer is -0.129 kJ

Explanation:

In the given case, the cooling of the balloon is done by withdrawing 0.784 J of heat, and the work done by the atmosphere on the balloon is 655 J. First, there is a need to transform kJ into J, 1 kJ = 1000 J. So, 0.784 kJ would be 784 J.  

The ΔE or the change in the internal energy can be calculated by using the formula, ΔE = q + w ----- (1).  

In the given case, q refers to the heat moved out of the system, that is, the value of q would be less than 0 or will be a negative quantity. Therefore, the heat moved out of the system will be -784 J. On the other hand, as the work or w is done on the system, therefore, the value of w would be more than 0 or will be a positive quantity. Thus, the value of w will be +655 J.  

Now putting the values in the equation (1) we get,  

ΔE = -784 J + 655 J

ΔE = -129 J or -0.129 kJ

As the change in internal energy comes out to be a negative value, therefore, the process is considered exothermic.  

Water is intentionally present in a state where its molecules are far apart during a change of state is molecule slow down which change of state has most likely taking place

Answers

Answer:

melting

Explanation:

A maple tree could be studied in many fields of science. What aspect of a maple tree might be studied in chemistry

Answers

Answer:

botany because a maple tree is a plant

Explanation:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolite , resulting in the reduction of the to pure aluminum. Suppose a current of is passed through a Hall-Heroult cell for seconds. Calculate the mass of pure aluminum produced. Round your answer to significant digits. Also, be sure your answer contains a unit symbol.

Answers

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

Erbium (Er) is element 68 on the periodic table. A sample contains 5.04×1023 atoms of Er. Calculate the amount of Er.

Answers

Answer:

139.98 g to nearest hundredth.

Explanation:

Using Avogadro's Number:

One mole (167.26 g) of Erbium  equates to  6.022141 * 10^23 atoms.

So 5.04 * 10^23 = 167.26 * 5.04/6.022141

= 139,98 g.

Al2O3 would be typed in as Al2O3 Al2(SO4)3 would be typed in as Al2(SO4)3.

Required:
a. Write the formula for calciumnitride.
b. Write the formula for magnesium phosphide
c. Write the formula for rubidium chromate
d. Write the formula for aluminum nitrate
e. Write the formula for ammonium arsenide
f. Write the formula for nickel(II) nitrite
g. Write the formula for copper(I) sulfate
h. Write the formula for iron(III) nitrate
i. Write the formula for manganese(II) nitride

Answers

Answer:

Explanation:

Hello,

We are required to write the chemical formula of the following compounds

1. Calcium nitride = Ca₃N₂

2. Magnesium Phosphide = Mg₃P₂

3. Rubidium Chromate = Rb₂CrO₄

4. Aluminium nitrate = Al(NO₃)₃

5. Ammonium Arsenide = (NH₄)₃As

6. Nickel(ii) nitrite = Ni(NO₂)₂

7. Copper(i)sulfate = Cu₂SO₄

8. Iron(iii)nitrate = Fe(NO₃)₃

9. Manganese(ii)nitrate = Mn(NO₃)₂

The left hand side are the common names when the right hand side are the chemical formula.

Why we need blood cholesterol?​

Answers

Answer:

We need blood cholesterol because our body uses it to build your structure of cell membranes, make hormones like oestrogen, and testosterone, and to help your metabolism work well.

Answer:

our cells need some cholesterol but too much cuz it can cause problems. HDL carries cholesterol to your liver, where it can be removed from the body.so it  helps protect your heart from atherosclerosis

Explanation:

Draw a Lewis structure for each covalent molecule. a. CH3F b. N2H4

Answers

Answer:

See attached picture.

Explanation:

Hello,

In this case, given the compounds we notice:

a. Since carbon has four valence electrons (group IVA), it has three hydrogen atoms around it as well as a fluorine atom which has seven valence electrons (group VIIA). Moreover, we notice both carbon and fluorine attaining the octet.

b. In this case, two nitrogen atoms which have five valence electrons each (groupVA) are bonded via a single bond and two hydrogen atoms are bonded to each nitrogen atom in order to attain the octet for nitrogen only.

Thus, structures are given on the attached picture.

Regards.

Lewis structure for each covalent molecule CH₃F and N₂H₄ are attached to the image below.

a. CH₃F:

Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Fluorine (F) has 7 valence electrons.

The total number of valence electrons in CH3F can be calculated as follows:

1 carbon atom (C) × 4 valence electrons = 4 valence electrons

3 hydrogen atoms (H) × 1 valence electron = 3 valence electrons

1 fluorine atom (F) × 7 valence electrons = 7 valence electrons

Total valence electrons = 4 + 3 + 7 = 14

b. N₂H₄:

Nitrogen (N) has 5 valence electrons, and Hydrogen (H) has 1 valence electron.

The total number of valence electrons in N2H4 can be calculated as follows:

2 nitrogen atoms (N) × 5 valence electrons = 10 valence electrons

4 hydrogen atoms (H) × 1 valence electron = 4 valence electrons

Total valence electrons = 10 + 4 = 14

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How many grams of silver sulfide are formed when 0.280 g of hydrogen sulfide reacts with excess silver and oxygen?

Answers

Answer:

[tex]2.03~g~Ag_2S[/tex]

Explanation:

For this question we have to start with the reaction:

[tex]Ag~+~H_2S~+~O_2~->~Ag_2S~+~H_2O[/tex]

Now, we can balance the reaction, so:

[tex]4Ag~+~2H_2S~+~O_2~->~2Ag_2S~+~2H_2O[/tex]

With this in mind, we have to start with the amount of [tex]H_2S[/tex]. The first step is to convert from grams to moles. For this, we need to find the molar mass of [tex]H_2S[/tex]. If we check the periodic table we will find the atomic masses for Ag and H; H: 1 g/mol and A: 32 g/mol, so:

(1*2)+ (32*1) = 34 g/mol.

Now we can calculate the moles of [tex]H_2S[/tex]:

[tex]0.280~g~H_2S\frac{34~g~H_2S}{1~mol~H_2S}=0.0082~mol~H_2S[/tex]

With the moles of [tex]H_2S[/tex] we can calculate the moles of [tex]Ag_2S[/tex] if we check the molar ratio in the balanced equation, [tex]2~mol~H_2S=2~mol_Ag_2S[/tex], so:

[tex]0.0082~mol~H_2S\frac{2~mol_Ag_2S}{2~mol~H_2S}=0.0082~mol~H_2S[/tex]

With the molar mass of [tex]Ag_2S[/tex] we can convert from moles to grams (Ag: 107.86 g/mol, S: 32 g/mol), so:

(107.86*1)+(32*2)=247.80 g/mol

[tex]0.0082~mol~H_2S\frac{247.8~g~Ag_2S}{1~mol~H_2S}=2.03~g~Ag_2S[/tex]

I hope it helps!

Sodium metal and water react to form hydrogen and sodium hydroxide. If 11.96 g of sodium react with water to form 0.52 g of hydrogen and 20.80 g of sodium hydroxide, what mass of water was involved in the reaction

Answers

Answer:

9.36g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction.

2Na + 2H2O —> 2NaOH + H2

Next, we shall determine the mass of Na and H2O that reacted from the balanced equation.

This is illustrated below:

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

46g of Na reacted with 36g of H2O.

Now, we can determine the mass of H2O involved in reaction as follow:

From the balanced equation above,

46g of Na reacted with 36g of H2O.

Therefore, 11.96g of Na will react with = (11.96 x 36)/46 = 9.36g of H2O.

Therefore, 9.36g of H2O were used for the reaction.

the amount of order in an isolated system cannot increase; it may only stay the same or decrease. This expresses which of the following?
Conservation of mass
The First Law of Thermodynamics
The second Law of Thermodynamics
Kinetic Theory
The definition of work
the definition of heat

Answers

Answer:

Second law of thermodynamics.

Explanation:

Second law of thermodynamics states the entropy or order in an isolated system always increases. The isolated system evolve spontaneously toward thermal thermal equilibrium.

For example if a room is untidy and dirty,it will become messy over time and disorder. So when the room is cleaned, there won't be disorderliness and entropy will decrease.

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