12. AABC is a right triangle. If AB = 3 and AC = 7, find BC. Leave your answer in simplest radical form.

A 2 square root 3
B 4 square root 3
C square root 58
D 2 square root 13

Answer:

C

Step-by-step explanation:

the answer is C because √8 can be rewrite as 8^1/2

A is wrong because 8 is another number

B is wrong because 4 is not the square root of 8

D is wrong because 8^2 = 64

Answer:

V= +5 and -5

Step-by-step explanation:

just square root both sides

Answer:

9.2, 11/12, 91.7, 91.6, .91

Step-by-step explanation:

Answer:

for the first one, x + 3 * y = 5

and the second equation, x - y = 5

Step-by-step explanation:

the sum of two numbers means for example the sum of 5 and 8 is 13, so as an equation that is 5 + 8 = 13

the difference is the same thing as the sum but it's subtraction.

and then times is just multiplication.

Answer:

d. 463246.7

Step-by-step explanation:

V=4 /3πr^3=4/3·π·48^3≈463246.7

Answer:

373248 cm³ of wax

Step-by-step explanation:

If the crayon is 90 millimeters long, how many cubic centimeters of wax is used to make a box of 8 crayons?

1 crayon = 90mm

8 crayons = x

Cross Multiply

x = 8 × 90mm

x = 720mm

Converting to cubic mm

= (720mm)³ = 373248000mm³

Converting to cubic centimeter

1 mm³ = 0.001 cm³

373248000 mm³ = x

Cross Multiply

373248000 × 0.001 cm³

= 373248 cm³ of wax

Answer: D I think

Step-by-step explanation:

Answer: [tex]915.68\ \%[/tex]

Step-by-step explanation:

Given

Original Price=$10360

New Price=$1020

Percentage decrease in its Price is given by

[tex]\%\ \text{decrease}=\dfrac{\text{New-Original Price}}{\text{Original Price}}\times 100[/tex]

[tex]\Rightarrow \dfrac{10360-1020}{1020}\times 100=915.68\ \%[/tex]

Answer: 100

Step-by-step explanation:

The formula for the area of a trapezoid is (B1+B2)/2*h

so substitute:

(8+12)/2*10

20/2*10

10*10

100

Answer:

100 sq inches

Step-by-step explanation:

Simply use the formula for finding the area:

[tex]\frac{1}{2} * (sum of parallel sides) * height\\= \frac{1}{2} * (8 + 12) * 10\\= \frac{1}{2} * 20 * 10\\= 100 sq. inches[/tex]

Answer:

32

Step-by-step explanation:Not the best at math but it should be the same

Answer:

  9 in

Step-by-step explanation:

For an n-sided polygon, the length of the apothem is ...

 a = r·cos(180°/n)

We assume your problem statement is saying the radius is 10 inches. For a hexagon, n=6 and we have ...

 a = (10 in)cos(30°) ≈ 8.66 in

Rounded to the nearest inch, the apothem is 9 in.

Answer:

9

Step-by-step explanation:

cos(30)=x/10

X=8.66

Answer:

area of a square= length ²

area of a rectangle=length*breadth

area of parallelogram=base *height

Answer:

#1

a. Covert % to fraction

b. Whole is 100%, remaining is:

#2

Answer:

25(45) +200= 1125+200=1325

Answer:

Step-by-step explanation:

To find the volume of a Rectangular prism you have to do W*H*L

L=1/5

W=4/5

H=3/5

So just multiply them all and you get .0096 cm^3

Answer:

(2a,2b)

(-4a,b)

Step-by-step explanation:

for the first one

the x value of coordinate L is going to be twice the value of the x coordinate of k (a)

That being said the x value of L = 2a

The y value of L is going to be half the value of the y value of coordinate A ( 4b )

4b/2=2b so the y value of coordinate L is 2b

now we put the values as an ordered pair

The answer would be (2a,2b)

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

2sinxcosy = sin(x + y) + sin(x - y) , then

with x = 70 and y = 20

2sin70cos20

= sin(70 + 20) + sin(70 - 20)

= sin90 + sin50

= right side , thus proven

Answer:

The volume of the prism is other; 5.04 m^3

Step-by-step explanation:

Here, we want to get the volume of the prism

What we have to do here is to calculate the area of the trapezoid base and multiply by the height of the prism

The area of the base is;

A = 1/2(a + b) h

a and b are the parallel sides of the trapezoid which is 80 cm and 2 m

h is the height of the trapezoid which is 1.2 m

80 cm is same as 80/100 = 0.8 m (100 cm = 1 m)

A = 1/2( 0.8 + 2)1.2

A = 1/2 * 2.8 * 1.2 = 1.68 m^2

So we proceed to multiply this with the height of the prism which is 3 m

This will be ;

1.68 m^2 * 3 m = 5.04 m^3

Answer:

Length of the radii of the circles → 4 units and 1 unit

Equation of common tangent → x = 4

Step-by-step explanation:

From the figure attached,

Length of radii of each circles are,

Radius of circle S = 4 units

Radius of circle T = 1 unit

Common point where the circles are touching → (4, 1)

Common tangent to these circles is a line perpendicular to x-axis passing through x = 4,

Equation of the tangent will be,

x = 4

Answer:

[tex] \cos(51) = \frac{h}{9.7} \\ h = 9.7 \times \cos(51) \\ h =(6.10440779318)[/tex]

Answer:

you're answer would be d

Answer:

D. All of the above

Step-by-step explanation:

Answer:

is 3 units away from c

Step-by-step explanation:

Step-by-step explanation:

L+W+L+W=26 so 2L=26–2W and you can find length from the perimeter as L=13−W

LW=42 so L=42/W is the other way to find the length, from the area. Both ways require you to know W, but if you have both pieces of information the two answers for length must be the same 42/W=13−W, and you solve this:

42=13W−W2

W2–13W+42=0

(W−6)(W−7)=0

Either W−6=0 or  W−7=0

Answer:

Step-by-step explanation:

Using exponential function concepts, it is found that:

The model is: .

The car will be worth $13,625 in 7 years.

Answer:

5x2=10 centimeter

Step-by-step explanation:

Answer: 20

Step-by-step explanation:

The area of a quadrilateral with given vertices is 20 square units.

The area of a rectangle is defined as the product of the length and width.

The area of a rectangle = L × W

Where W is the width of the rectangle and L is the length of the rectangle

We have to determine the area of a quadrilateral with vertices at (-6,6), (-1,6),(-6,10), and (-1,10).

As per the attached graph, we can see that the dimensions of the rectangle are as follows:

Length (L) = 5 units

Width (W) = 4 units

Area of the rectangle = L × W

Area of the rectangle = 5 × 4 = 20 square units

Learn more about the Area of the rectangle here:

brainly.com/question/20693059

#SPJ2

Answer:

Trench warfare was a technique used to fight in World War 1. As they could hide/defend there. Get supplie there. They could even have medical areas there, but the problem was a stalemate as that was such a thing that no one attacks and they stay without moving on in the battle.