Answer:
Biology
Physics
Chemistry
Explanation:
Biology (life like cells, human reproduction, etc.)
Physics (Studies forces, like gravity.)
Chemistry (studies the atoms, the elements, etc.)
A ball is thrown upward from the ground with an initial speed of 20.6 m/s; at the same instant, another ball is dropped from a building 14 m high. After how long will the balls be at the same height above the ground?
Answer:
t= 0.68 s
Explanation:
Neglecting air resistance, both balls are only under the influence of gravity, so we can use the kinematic equation for vertical displacement for both balls.First of all, we define two perpendicular axes, coincidently with horizontal and vertical directions, that we denote as x-axis and y-axis respectively.Assuming that the upward direction is the positive one, g must be negative as it always points downward.Taking the ground as our zero reference for the vertical axis (y axis), the equation for the ball thrown upward can be written as follows:[tex]y = v_{o}* t -\frac{1}{2} * g * t^{2} (1)[/tex]
As the second ball is dropped, its initial velocity is 0. Taking the height of the building as the initial vertical position (y₀), we can write the equation for the vertical displacement as follows:[tex]y = y_{o} - \frac{1}2}*g*t^{2} (2)[/tex]
As the left sides of (1) and (2) are equal each other (the height of both balls above the ground must be the same), the time must be the same also.We can rearrange (2) as follows:[tex]y -y_{o} = -\frac{1}{2}*g* t^{2} (3)[/tex]
Replacing the right side of (3) in (1), we get:[tex]y = v_{o}*t + (y- y_{o})[/tex]
⇒ [tex]t =\frac{y_{o} }{v_{o} } =\frac{14 m}{20.6 m/s} = 0.68 s[/tex]
⇒ t = 0.68s
1 poir
A track star in the long jump goes into the jump at 15 m/s and launches
herself at 17.0° above the horizontal.How long is she in the air before
returning to Earth? (g = 9.81 m/s2) (do not include units in answer) *
Helppp now
A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration).
a. 1.62*105 m/s2.b. 1000 m/s2.c. 0.62*105 m/s2.d. 3.62*105 m/s2.
Answer:
A. 1.62×10⁵m/s²Explanation:
Given
velocity of the bullet = 521m/s
distance = 0.840m
required
acceleration of the bullet a
Using the equation of motion:
v² = u²+2aS where:
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Substitute the given parameters into the equation to get a:
521² = 0²+2a(0.840)
271,441 = 0+1.68a
271,441 = 1.68a
a = 271,441/1.68
a = 161,572.02
a = 1.62×10⁵m/s²
Hence the acceleration of the bullet is 1.62×10⁵m/s²
Suppose that your favorite AM radio station broadcasts at a frequency of 1600 kHz. What is the wavelength in meters of the radiation from the station
Answer:
187.5
Explanation:
An electric drill starts from rest and rotates with a constant angular acceleration. After the drill has rotated through a certain angle, the magnitude of the centripetal acceleration of a point on the drill is 7.9 times the magnitude of the tangential acceleration. What is the angle
Answer:
The angle is 3.95 rad.
Explanation:
The angle can be calculated as follows:
[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta [/tex]
Where:
[tex]\omega_{f}[/tex]: is the final angular speed
ω₀: is the initial angular speed = 0 (it starts from rest)
α: is the angular acceleration
θ: is the angle=?
The centripetal acceleration is:
[tex]a_{c} = \omega_{f}^{2}*r[/tex]
And the tangential acceleration is:
[tex] a_{T} = \alpha*r [/tex]
Since the magnitude of the centripetal acceleration is 7.9 times the magnitude of the tangential acceleration:
[tex]a_{c} = 7.9a_{T}[/tex]
[tex]\omega_{f}^{2}*r = 7.9*\alpha*r \rightarrow \alpha = \frac{\omega_{f}^{2}}{7.9}[/tex]
Now, the angle is:
[tex]\omega_{f}^{2} = 2(\frac{\omega_{f}^{2}}{7.9})\theta[/tex]
[tex] \theta = \frac{7.9}{2} = 3.95 rad [/tex]
Therefore, the angle is 3.95 rad.
I hope it helps you!
The angular distance traveled by the electric drill is 3.95 radians.
The given parameters;
initial angular speed, [tex]\omega_i[/tex] = 0centripetal acceleration, [tex]a_c[/tex] = 7.9aThe angular distance traveled by the electric drill is calculated as follows;
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]
The relationship between centripetal acceleration, tangential acceleration and angular speed is given as;
[tex]a_c = \omega ^2 r\\\\a = \alpha r\\\\a_c = 7.9a= 7.9\alpha r\\\\7.9\alpha r = \omega^2 r\\\\\alpha = \frac{\omega ^2}{7.9}[/tex]
Substitute the value of angular acceleration into the first equation;
[tex]\omega _f^2 = 0 + 2(\a (\frac{\omega _f^2}{7.9})\theta\\\\2\theta \omega_f^2 = 7.9\omega_f ^2\\\\\theta = \frac{7.9}{2} \\\\\theta = 3.95 \ rad[/tex]
Thus, the angular distance traveled by the electric drill is 3.95 radians.
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Consider a 50-turn circular loop with a radius of 1.55 cm in a 0.35-T magnetic field. This coil is going to be used in a galvanometer that reads 45 μA for a full-scale deflection. Such devices use spiral springs which obey an angular form of Hooke's law, where the restoring torque is:
τs = -κ θ.
Here κ is the torque constant and θ is the angular displacement, in radians, of the spiral spring from equilibrium, where the magnetic field and the normal to the loop are parallel.
Required:
a. Calculate the maximum torque, in newton meters, on the loop when the full-scale current flows in it.
b. What is the torque constant of the spring, in newton meters per radian, that must be used in this device?
Complete Question
Consider a 50-turn circular loop with a radius of 1.55 cm in a 0.35-T magnetic field. This coil is going to be used in a galvanometer that reads 45 μA for a full-scale deflection. Such devices use spiral springs which obey an angular form of Hooke's law, where the restoring torque is:
τs = -κ θ.
Here κ is the torque constant and θ is the angular displacement, in radians, of the spiral spring from equilibrium, where the magnetic field and the normal to the loop are parallel.
Required:
a. Calculate the maximum torque, in newton meters, on the loop when the full-scale current flows in it.
b. What is the torque constant of the spring, in newton meters per radian, that must be used in this device? Assume the full scale deflection is 60° from the spring's equilibrium position
Answer:
a
[tex]\tau_{m} = 5.95 *10^{-7} \ N \cdot m[/tex]
b
[tex]\beta = 2.83 *10^{-7} \ N \cdot m / rad [/tex]
Explanation:
From the question we are told that
The number of turns is N = 50
The radius is r = 1.55 cm = 0.0155 m
The magnetic field is B = 0.35 T
The induced current is [tex]I = 45 \mu A = 45 *10^{-6} \ A[/tex]
Generally the area of loop is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A =3.142 * 0.0155^2[/tex]
=> [tex]A =0.000755\ m^2[/tex]
Generally the maximum torque is mathematically represented as
[tex]\tau_{m} = N * B * I * A[/tex]
=> [tex]\tau_{m} = 50 * 0.35 * 45 *10^{-6} * 0.000755[/tex]
=> [tex]\tau_{m} = 5.95 *10^{-7} \ N \cdot m[/tex]
Generally the torque 60° from the spring's equilibrium position is mathematically represented as
[tex]\tau = N * B * I * A * sin (60)[/tex]
=> [tex]\tau = 50 * 0.35 * 45 *10^{-6} * 0.000755 * sin (60)[/tex]
=> [tex]\tau = 2.973 *10^{-7} \ N \cdot m [/tex]
Generally the toque constant of the spring is mathematically represented as
[tex]\beta = \frac{\tau}{60}[/tex]
=> [tex]\beta = \frac{\tau}{\frac{\pi}{3}}[/tex]
=> [tex]\beta = \frac{2.973 *10^{-7}}{\frac{\pi}{3}}[/tex]
=> [tex]\beta = 2.83 *10^{-7} \ N \cdot m / rad [/tex]
A 50 kg bicyclist starts his ride down the road with an acceleration of 1m/s2 in air with a density of 1.2 kg/m3. If his velocity at a given moment is 2m/s, how much force is he exerting? Assume the area of his body is 0.5m^2.
a. The bicyclist is exerting 1.1 N of force.
b. The bicyclist is exerting 49 N of force.
c. The bicyclist is exerting 50 N of force.
d. The bicyclist is exerting 51 N of force.
Answer:
b. The bicyclist is exerting 49 N of force
Explanation:
Given;
mass of bicyclist start, m = 50 kg
acceleration, a = 1 m/s²
density of air, ρ = 1.2 kg/m³
velocity, v = 2 m/s
Area of the bicyclist body, A = 0.5 m²
The drag force on the bicyclist is given by ;
Fd = 0.5CρAv²
where;
C is drag coefficient = 0.9 for bicycle
Fd = 0.5 x 0.9 x 1.2 x 0.5 x 2²
Fd = 1.1 N
The force of the bicyclist is given by;
F = ma
F = 50 x 1
F = 50 N
The effective force exerted by the bicyclist is given by;
Fe = F - Fd = 50 N - 1.1 N
Fe = 49 N
Therefore, the force exerted by the bicyclist is 49 N
Water enters a 2 m3 tank at a rate of 6 kg/s and is withdrawn at a rate of 2 kg/s. The tank is initially half full. What type of process is this?
Answer:
This process is semicontinuous.
Explanation:
Given that,
Volume = 2 m³
Enter flow rate = 6 kg/s
Exit flow rate = 2 kg/s
The tank is initially half full.
We need to find what type of process
Using given data,
This process is not continuous because given enter and exit flow rate is not equal.
This process is semicontinuous and the water level in the tank does not reach a constant level.
Hence, This process is semicontinuous.
The name for this type of energy is
A.potential energy
B.motion
C.position
D.kinetic energy
Explanation:
[tex]kinetic \: energy \: is \: the \: energy \: of \: a \: body \: in \: motion. \\ that \: is \: energy \: of \: a \: body \: that \: is \: moving.\\ while \\ potential \: energy \: is \: the \: energy \: of \: a \: body \: by \: the \: virtue \: of \: its \: position \: \\ that \: is \: energy \: of \: a \: body \: that \: is \: not \: moving.[/tex]
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If I am driving down the highway going north at 50 miles per hour, and another car is driving south at 75 miles per hour. How fast is the car coming toward me?
Its an exam >.
I WILL GIVE BRAINLIEST
Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor dissipates more power
Answer:
A dissipates more power.
Explanation:
In a series circuit, the current is the same at any point in it.The power dissipated in any resistor follows Joule's law, as follows:[tex]P = I^{2} * R[/tex]
So, for a given current, the power is directly proportional to the resistance of the resistor.In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.Which factor increases as a result of increasing altitude? Air pressure, air density, heights of sea level, space between gas molecules.
Answer:
heights of sea level and the space between gas molecules.
Explanation:
Asking that Which factor increases as a result of increasing altitude?
As the height above the sea increases, air density decreases because the molecule of the air will spread out causing air density to decrease. Also, there will be less air pressing down which will lead to a decrease in air pressure.
Therefore, the heights of sea level, and space between gas molecules are the factor that will increase as a result of increasing altitude. Not Air pressure and air density. But the heights of sea level and the space between gas molecules.
Answer:
AnswerAnswer c
Explanation:
What are two different ways that resistors can be connected together in a circuit? Explain the difference between the two in terms of calculating equivalent resistance.
Explanation:
Resistors in circuits can either be connected in series or in parallel.
For a series connected resistors, the same current flows through the resistors while different voltages is passed across them. The formula for calculating effective resistances in a circuit is expressed as
[tex]R_T = R_1+R_2+R_3...+R_n[/tex] where R1, R2, R3 etc. are the resistances connected in series.
The effective resistances for series connected resistors is the sum of the individual resistors
For a parallel connected resistors, different current flows through the resistors while same voltage is passed across them. The formula for calculating effective resistances in a circuit is expressed as:
[tex]\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} +...\frac{1}{R_n}[/tex]
The effective resistances for parallel connected resistors is the sum of the reciprocal of the individual resistors
1 (4 points) A 2-kg ball is moving with a constant speed of 5 m/s in a horizontal circle whose radius is 50 cm. What is the magnitude of the net force on the ball
Answer:
100 N
Explanation:
The following data were obtained from the question:
Mass (m) = 2 Kg
Velocity (v) = 5 m/s
Radius (r) = 50 cm
Force (F) =.?
Next, we shall convert 50 cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
50 cm = 50 cm × 1 m / 100 cm
50 cm = 0.5 m
Therefore, 50 cm is equivalent to 0.5 m.
Finally, we shall determine the magnitude of the net force on the ball by using the following formula:
F = mv²/r
Mass (m) = 2 Kg
Velocity (v) = 5 m/s
Radius (r) = 0.5 m
Force (F) =.?
F = mv²/r
F = 2 × 5²/ 0.5
F = 2 × 25/ 0.5
F = 50 / 0.5
F = 100 N
Therefore, the magnitude of the net force on the ball is 100 N.
The magnitude of the net force on the ball will be "100 N".
Force and speedAccording to the question,
Mass, m = 2 kg
Velocity, v = 5 m/s
Radius, r = 50 cm or,
= 50 × [tex]\frac{1}{100}[/tex]
= 0.5 m
We know the relation,
Force, F = [tex]\frac{mv^2}{r}[/tex]
By substituting the values, we get
= [tex]\frac{2\times (25)^2}{0.5}[/tex]
= [tex]\frac{2\times 25}{0.5}[/tex]
= [tex]\frac{50}{0.5}[/tex]
= 100 N
Thus the above response is appropriate.
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A car drives 20 miles north and then 3 miles south. What is the displacement
of the car?
A. 23 miles north
B. 23 miles
C. 17 miles north
D. 17 miles
How did the Mayflower Compact influence colonists’ views on government?
Answer:
It demonstrated that the colonists were capable of local, self-government.
Explanation:
this is the correct answer because i have already done this
the amplitude of a wave is
Answer:
The amplitude of a wave is a measure of the displacement of the wave from its rest position. The amplitude is shown on the graph below. Amplitude is generally calculated by looking on a graph of a wave and measuring the height of the wave from the resting position. The amplitude is a measure of the strength or intensity of the wave.
Explanation:
Hope this helps! <3
Check all the answers that apply.
Energy is the ability to:
⚫️ Change direction
⚫️ Change speed
⚫️Change temperature
⚫️Do work
Energy is the ability to: ⚫️Do work
mark me brainiest pls
HELP PLS GIVING BRAINLIEST!!
Electromagnetic waves produced by the sun travel through space to Earth. What is this method of energy transfer called?
Answer:
Radiation
Explanation:
This is an example of radiation.
2. An archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force is...
a. Air resistance against the bow
b. Arrow's push against the bowstring
c. Grip of the archer's hand on the bow
Answer:b the arrows push against the bow string
Explanation:
The reaction force will be Arrow's push against the bowstring.
Option b is correct.
From Newton's Third Law of Action & Reaction, It states that for every action in nature there is an equal and opposite reaction.
It means that If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.Therefore, If an archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force will be Arrow's push against the bowstring
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What can reduce the flow of heat
Answer:
To minimize heat flow through a layer of material by conduction, choose the right material, make the layer as thick as possible, and make the surface area as small as possible. Clothing intended to reduce heat flow should use low-thermal conductivity materials.
g A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.03t3 (a) Find the velocity at time t (in ft/s). v(t) = 0.04t^3−0.09t^2 Correct: Your answer is correct. (b) What is the velocity after 1 second(s)? v(1) = -0.05 Correct: Your answer is correct. ft/s (c) When is the particle at rest? t = 0 Correct: Your answer is correct
Answer:
Explanation:
If a particle move with time and expressed according to the formula:
f(t) = 0.01t⁴ − 0.03t³
a) Velocity is the change in motion of the particle with respect to time and it is expressed as;
[tex]v(t) =\frac{d(f(t))}{dt}[/tex]
[tex]v(t) = 4(0.01)t^{4-1} - 3(0.03)t^{3-1}\\v(t) = 0.04t^3 - 0.09t^2[/tex]
Hence the velocity of the particle at time t is [tex]v(t) = 0.04t^3 - 0.09t^2[/tex]
b) To calculate the velocity after 1 second, we will substitute t = 1 into the function v(t) in (a) as shown:
[tex]v(t) = 0.04t^3 - 0.09t^2\\v(1) = 0.04(1)^3 - 0.09(1)^2\\v(t) = 0.04 - 0.09\\v(t) = -0.05[/tex]
Hence the velocity after 1second is -0.05
c) The particle is at rest when when the time is zero.
Initially, the body is not moving and the time during this time is 0. Hence the particle is at rest when t = 0second
In a double-slit arrangement the slits are separated by a distance equal to 120 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum
In a double-slit arrangement the slits are separated by a distance equal to 120 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum(b) What is the distance between these maxima on a screen 5.79m from the slits?
Answer:
a
[tex]\theta = 0.476 ^ o[/tex]
b
[tex]y = 0.0481 \ m [/tex]
Explanation:
From the question we are told that
The slit separation is [tex]d = 120 \lambda[/tex]
Here [tex]\lambda[/tex] is the wavelength of the light
Generally the condition for constructive interference is mathematically represented as
[tex]dsin (\theta) = m * \lambda[/tex]
=> [tex]\theta = sin^{-1} [\frac{n * \lambda}{ d } ][/tex]
=> [tex]\theta = sin^{-1} [\frac{n * \lambda}{ 120 \lambda } ][/tex]
Here n is the order of maxima which is 1 given that we are considering the central maximum and an adjacent maximum
So
[tex]\theta = sin^{-1} [\frac{1}{ 120} ][/tex]
=> [tex]\theta = 0.476 ^ o[/tex]
Generally given that the distance of the screen is D = 5.79 m from the slit then the distance between these maxima is mathematically represented as
[tex]y = D tan (\theta )[/tex]
=> [tex]y = 5.79 * tan (0.476)[/tex]
=> [tex]y = 0.0481 \ m [/tex]
I need help with this answer
Which statement best describes an atom? (2 points)
оа
Protons and neutrons grouped in a specific pattern
Ob
Protons and electrons spread around randomly
ос
A group of protons and neutrons that are surrounded by electrons
Od
A ball of electrons and neutrons surrounded by protons
Answer:
A group of protons and neutrons that are surrounded by electrons I think that's the answer...
Explanation:
convert 4.5 hour into second
Answer:
4.5 hours =
16200 seconds
Explanation:
here you go
Peter rides his bike 5 blocks north and then 10 blocks east. What is his displacement? What is his total distance traveled?
Answer:
5 blocks east. His total distance is 15 feet.
Explanation:
I hope that this helps! Have a good day!
can humans be considered carbon sinks? If so,for how long
Answer:
Humans be considered carbon sinks. Not only do humans
have a lot of carbon in them, they also use a lot of carbon.
hope this helps
A motorboat is a lot heavier than a pebble. Why does the boat float?
Answer:
The boat has more buoyancy
Explanation: