1) Consider this row in the periodic table. What changes can you predict based on what information is provided by the boxes for each element?

A) The elements change from solids to gases and the valence electrons decrease in number.

B) As you move across the row, the number of electrons increases and reactivity also increases.

C) They have different atomic numbers and mass numbers; they have the same number of valence electrons.

D) Both the atomic numbers and the mass numbers increase; the least reactive element is in the last box.

USA test prep question

The final volume of gas will be 137.17L .

According to ideal gas equation , PV=nRT , where P is pressure of gas , V is volume of gas , n is moles of gas , R is universal gas constant and T is the temprature of gas.

Now , according to the que at initial and final stage the temprature and amount of gas stays constant , so we would simply equate the initial PV to the final PV.

⇒[tex]P_{i} V_{i} = P_{f} V_{f} \\[/tex]

where [tex]P_{i}[/tex] ans [tex]V_{i}[/tex] are the initial pressure and volume of the gas and  [tex]P_{f}[/tex]  and [tex]V_{f}[/tex] are the final pressure and volume of the gas .

Here we have to find final volume of gas .

So , putting all values in above eq we get

18 x 22.1 = 2.9 x  [tex]V_{f}[/tex]

⇒ [tex]V_{f}[/tex] = 137.17 L

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The combustion of lauric acid is shown as CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

In a combustion reaction, a substance is burnt in oxygen. If the substance is an organic compound a the case is here, the products are carbon dioxide and hydrogen.

No the equation of the combustion of lauric acid is shown as;

CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

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1.05 moles of oxygen gas are consumed in the reaction when 2.10 mol of magnesium burns.

A mole is defined as [tex]6.02214076 × 10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

We are given:

Moles of magnesium = 2.10 mol

For the given chemical reaction:

2Mg + O₂ → 2MgO.

By Stoichiometry of the reaction:

2 moles of magnesium react with 1 mole of oxygen gas.

So, 2.10 moles of magnesium will react with = [tex]\frac{1}{2}[/tex] X2.10 =1.05 moles

Hence, 1.05 moles of oxygen gas are consumed in the reaction.

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The number of moles of the gas at 77°C and 1.33 atm occupies a volume of 50.3 L is 2.35 moles. It can found with the help of Ideal gas equation.

The ideal gas equation is formulated as : PV = nRT.

In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Given ;

We know ;

Formula used ;

n = PV / RT

n = 1.33 x 50.3 / 0.081 x 350k

  =  2.35 moles.

Hence, The number of moles of the gas at 77°C and 1.33 atm occupies a volume of 50.3 L is 2.35 moles

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NaClO₃ ⇒ NaCl + O₂ ⇒ unbalanced

1. O : left 3, right 2

give coefficient left 2, right 3

2NaClO₃ ⇒ NaCl + 3O₂

2. Na and Cl : left 2, right 1

give coefficient right 2

2NaClO₃ ⇒ 2NaCl + 3O₂ ⇒ balanced

Answer:

C.) Csp² - Nsp³

Explanation:

Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).

The hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.

Hybridization is defined as the concept of the mixing of the atomic orbitals for the formation of new hybrid orbitals which are suitable for the pairing of electrons in forming chemical bonds in valence bond theory. And the orbital formed by the hybridization are termed as hybrid orbitals.

Since the carbon atom form one single bond with hydrogen atom and one pi bond with nitrogen bond, so the conformation of carbon atom is Csp2. On the other hand, nitrogen also form one single bond and a pi bond, so it also contribute three hybrid orbital. Since it have one lone pair of nitrogen so they take one orbitals. Therefore, the conformation of nitrogen atom is Nsp3.

Thus, we concluded that the hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.

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Answer:

Substance

Explanation:

Any physical matter despite of living or non living things are composed by a set of molecules or atoms commonly known as substance

On specific living things are composed of biomolecules or cells where as non living things are composed of molecules and atoms

Answer:

Substances

Physical matters are divided into 3 states

As per randomness of particles the order is

Answer:

15 oxygens

Explanation:

Given the partially balanced reaction: [tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \text{5C} \text{O}_{2}}+\text{5H}_\text{2}\text{O}[/tex]

The subscripts (small number to the right of each element symbol) are the number of atoms of the element within each compound/molecule, and the coefficients (numbers in front of each compound) represent the number of that molecule involved in one full reaction (if the equation were balanced).

The product side of the reaction is on the right of the arrow.

To determine the total number of Oxygens on the product side, we need to identify how many Oxygens are in each molecule (the subscript on the Oxygen), and then multiply times the number of that molecule that would be involved (Coefficient of the compound containing Oxygen).  There are multiple compounds on the right side of the equation that contain Oxygen, so we'll need to add together the number of Oxygens each part contributes.

[tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}[/tex]

[tex]\text{\# reactant-side Oxygens}=\bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}\\=5 \text{ CO}_{\text{2}}\text{ molecules} *\frac{\text{2 Oxygens}}{\text{1 CO}_{\text{2}}\text{ molecule}}+5 \text{ H}_{\text{2}}\text{O molecules} *\frac{1\text{ Oxygen}}{\text{1 H}_{\text{2}}\text{O molecule}}\\=10\text{ Oxygens}+5\text{ Oxygens}\\=15\text{ Oxygens}[/tex]

(CH₂)n=42

(14)n=42

n=3

C₃H₆

The length measurements in increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events.

Measurement is a process of determining how large or small a physical quantity is as compared to a basic reference quantity of the same kind.

Hence, Among the given length measurements, The increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.

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Answer:

Whts ur question??

..?

Explanation:

Was this by mistake or smthin

Rubber gloves and other chemical resistant protective clothing are necessary when handling concentrated ammonium hydroxide.

The extent of injury produced by exposure to ammonia depends on the duration of the exposure, the concentration of the liquid or vapor and the depth of inhalation.

Hence, Rubber gloves and other chemical resistant protective clothing are necessary when handling concentrated ammonium hydroxide.

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Answer:

2HBr + Ba(OH)2 ____ BaBr2 + 2H2O

The numbers placed in front of formulas to balance equations

Answer: it is A i took the test i got it right

Explanation: i took the test

Answer: Double replacement reaction

Explanation:

The pressure has no effect on the equilibrium constant.

Equilibrium is a state when the forward reaction rate is equal to the backward reaction rate .

The equation given is

H₂ + I₂ ⇄ 2HI

The Equilibrium constant depends only upon temperature and nature of reaction ,

It is independent of  catalyst presence , initial concentration of reactants,and pressure.

The pressure has no effect on the equilibrium constant.

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Answer:

Conducting Experiments

The entropy of a mixture is 96.44J K-1 mol -1

The formula for calculating the entropy of a mixture-

Δ[tex]S_{mix} =[/tex][tex]-nR(X_{O2} ln_{XO2} +X_{N2} lnX_{N2})[/tex]

X=mole fraction

total no. of moles(t)=m + n

                             =2.4+9.2

                             =11.6 moles

now substituting the values-

entropy of mix=-11.6R(2.4/11.6 + 9.2/11.6)

                       =11.6R

( R=8.314 )        =11.6×8.314

                          =96.44J K-1 mol -1

hence, The entropy of a mixture is 96.44J K-1 mol -1

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M₁V₁=M₂V₂

65 x M₁ = 16.8 x 0.5

M₁ = 0.129

65 x M₁ = 18.2 x 0.5

M₁ = 0.14

65 x M₁ = 17.35 x 0.5

M₁ = 0.133

Average = 0.129 + 0.14 + 0.133 = 0.134 M

Answer:

In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.

Explanation:

To further explain this, there is 18 groups of the periodic table.  These groups include:

Group 1: The alkali metals have a 1+ charge for their entire group.

For example: Sodium would have a charge of 1+.

Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.

Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.

Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.

Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+

Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.

Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.

Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.

Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.  

Answer:

you know that they will be a displacement reaction that will form a barium salt:

Ba(NO3)2+ 2NaCl--> BaCl2 + 2NaNO3

So now that we have that formula and the molecular weight we can determine how much salt will be made. So here we convert the grams to moles

(42.3g Ba(NO3)2)*(1 mole/261.34g) = 0.16185 mol

In the molecular formula we know that 1 mole of Barium nitrate will create 1 mole of Barium chloride, so in this case (in a perfect world) you should get 0.16185 mole of barium chloride (208.23 g/mol) that we then have to convert to grams.

(0.16185 mol BaCl2) * ( 208.23 g/mol) = 33.7037 g of Barium Chloride (rounded to 3 significant digits = 33.7g)

Avogadro's law states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] atoms. This means that in the given sample, there are

[tex]\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}[/tex]

So, the atomic mass of sulfur dioxide is

[tex]32.06+2(15.9994=64.0588 \text{ g/mol}[/tex]

Therefore, the mass is:

[tex](64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}[/tex]

Work arriving at total valence electrons are 24

The valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond

For a main-group element, a valence electron can exist only in the outermost electron shell; for a transition metal, a valence electron can also be in an inner shell.

Lewis structures, also known as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that show the bonding between atoms of a molecule, as well as the lone pairs of electrons that may exist in the molecule.

Calculating the work arrival at total valence electrons

We know 1 bond contains

2 valence electrons

Here CCl4 contains 4 bonds that is 8 valence electrons

Therefore ,

Total valence electrons are 32

Now valence electrons remain after bond formation =

32 - 8

=24 valence electrons

A molecular model is a physical model of an atomistic system that represents molecules and their processes

Molecular image and lewis hand drawn structure is as shown below

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For a system PCl3(g) + Cl2(g) PCl5(g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C, the ratio of the partial pressure of PCl5 to the partial pressure of PCl3 is will increase

Generally, the equation for chemiecal reaction is mathematically given as

PC3 (g) + C₁₁₂ (g) = PC15 (g) 3

Assuming the addition of some Cl2 gas. The reaction will shift to the right at the invariant volume temperature, maintaining equilibrium. This results in a rise in P9Cl5(g) and a fall in PpCl3(g).

PpCl (g) /PpCl (g) will increase

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The ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increase for a system PCl₃ (g) + Cl₂ (g) --> PCl₅ (g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C when some Cl₂ (g) is added at constant volume and temperature.

Generally, the equation for chemical reaction is mathematically given as ;

PCl₃ (g) + Cl₂ (g) --> PCl₅ (g)

Assuming the addition of some Cl₂ gas,

The reaction will shift to the right at the constant volume and temperature, maintaining equilibrium.

This results in a rise in PCl₅ (g) and a fall in PCl₃(g).

Hence, the ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increases

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Answer:

According to me end point is the end of a reaction