1. Consider the point exactly halfway between the two wires. Can you adjust the current so that, with current passing through each of the wires, the net field is zero here? 2. Note the distance between the field lines from one of the wires. Are they equally space? Explain. 3. With currents of different magnitudes passing through the two wires, how do the forces on the two wires compare? What is the reason for this?

Answer:

13.3

Explanation

work= force/area

2000/150

Answer:

following are the solution to this question:

Explanation:

When I stand at such a scale in an elevated that's already rising upwards, its scale would appear to also be 0 because of free fall and would often reveal that weight whenever the lift is stable.  

In this, the free fall is also known as the object, that is influenced exclusively by gravity, and an object operating only through the influence of gravity is said to be in a free-fall state.

Answer:

No you didn't win the stuffed poodle

Explanation:

From the question we are told that

    The distance of the ramp to the hole is  d =  3 m \

     The angle of inclination is  [tex]\theta  =  10^o[/tex]

       The coefficient of static friction is [tex]\mu_s = 0.1[/tex]

     The coefficient of kinetic  friction is [tex]\mu_k = 0.08[/tex]

      The mass of the puck is  m  =  1 kg

     The velocity of the first slide  is  [tex]v_1  =  2.0 m/s[/tex]

Generally the kinetic energy at the bottom of the ramp  is equal the energy loss due to friction and this can be mathematically represented as

    [tex]\frac{1}{2} m *  v^  2 =  \mu_k * [m *  g] *  cos (theta )  *  d[/tex]

=>     [tex]\frac{1}{2}  *  v^  2 = 0.08 * 9.8 *  cos (10 )  *  3[/tex]

=>     [tex] v=  2.17 \  m/s [/tex]

Comparing the relative velocity obtained and the velocity of your first throw we can see that you didn't win the stuffed animal  

Answer:

gjmoon = 19.6 m/s2

Explanation:

       [tex]F_{gE} = m* \frac{G*M_{E} }{R_{E} ^{2} } = m*g_{E}[/tex]

      [tex]F_{gjmoon} = m* \frac{G*M_{Jmoon} }{R_{Jmoon} ^{2} } = m*g_{jmoon} (1)[/tex]

       [tex]M_{Jmoon} = \frac{M_{E} }{2} (2)[/tex]  

      [tex]R_{Jmoon} = \frac{R_{E} }{2} (3)[/tex]

       [tex]F_{gjmoon} = m* \frac{G*M_{E} }{2*\frac{R_{E} ^{2}}{4} } = m*g_{jmoon} (1) = m* 2* \frac{G*M_{E} }{R_{E} ^{2}} = 2* m*g_{E}[/tex]

      ⇒  [tex]g_{jmoon} = 2* g_{E}[/tex]

       gjmoon = 19.6 m/s2 (in magnitude).

Answer:

v = 0.349 m/s

Explanation:

If you borrow your mom's car to drive 128 m to the store, but you go cruising  instead and drive a total distance of 1256 m in 3600s.

We need to find your speed during the  trip. It is equal to the total distance divided by time taken.

He has done cruising  instead and drive a total distance of 1256 m.

So,

[tex]v=\dfrac{d}{t}\\\\v=\dfrac{1256\ m}{3600\ s}\\\\v=0.349\ m/s[/tex]

So, the speed of the person during the trip is 0.349 m/s.

Answer:

The weight W, or gravitational force, is then just the mass of an object times the gravitational acceleration. Since the gravitational constant (g) depends on the square of the distance from the center of the earth, the weight of an object decreases with altitude.

Explanation:

please mark as brainlist

Answer:

The value  is  [tex]B =  0.0452 \  T [/tex]

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

Generally the magnetic field is mathematically represented as

         [tex]B = \mu_o  * \frac{N }{L}  *  I[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  

     [tex]\mu_o  =  4\pi * 10^{-7} N/A^2[/tex]

So

     [tex]B =  4\pi * 10^{-7}  *   \frac{1000}{0.50} *  18.0[/tex]

=>   [tex]B =  0.0452 \  T [/tex]

Answer:

stop being an annoying child and appreciate everything your mother does for you because she cares for you

Explanation:

its the right thing to do

Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can

Answer:

45.89m/s²

Explanation:

Given

Distance S = 305m

Time t = 3.64s

To get the acceleration during this run, we will apply the equation of motion:

S = ut+1/2at²

Substitute the given parameters into the formula and calculate the value of a

305 = 0+1/2 a(3.64)²

304 = 1/2(13.2496)a

304 = 6.6248a

a = 304/6.6248

a = 45.89m/s²

Hence the average acceleration during this run is 45.89m/s²

Answer:

1.152 miles

Explanation:

Given: central angle = 1 minute = [tex](\frac{1}{60}) ^{o}[/tex]

           radius of the earth = 3960 miles

The length of an arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

where: [tex]\alpha[/tex] is the central angle, and r is the radius.

Thus,

Distance along the arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

Distance along the arc = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 2 x [tex]\frac{22}{7}[/tex] x 3960

                                      = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 24891.4286

                                      = 1.1524

The required distance along an arc is 1.152 miles.

Answer:

The observed wavelength is  [tex] \lambda = 700nm[/tex] (color -  Red)

Explanation:

From the question we are told that

   The wavelength of the emitter is  [tex]\lambda_ e  = 500 nm  =  500 *10^{-9} \  m[/tex]

  The redshift is  R  =  0.4  

     Generally red shift is mathematically represented as

    [tex]R =  \frac{ \lambda -  \lambda_e }{\lambda_e}[/tex]

=>  [tex]0.4  =  \frac{ \lambda -   500 *10^{-9} }{500 *10^{-9} }[/tex]

=>  [tex] \lambda - 500*10^{-9} = 200*10^{-9}  [/tex]

=>   [tex] \lambda = 700 *10^{-9}[/tex]

=>   [tex] \lambda = 700nm[/tex]

Answer:

Radiocarbon dating

Explanation:

Answer:

Its speed remains the same but its velocity keeps chaging (in direction)

Explanation:

Answer:

Experimenter bias

Explanation:

If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of Experimenter bias.

Definitions of Experimenter bias

1) Research bias, also called experimenter bias, is a process where the scientists performing the research influence the results, in order to portray a certain outcome.

2) Observer bias (also called experimenter bias or research bias) is the tendency to see what we expect to see, or what we want to see. When a researcher studies a certain group, they usually come to an experiment with prior knowledge and subjective feelings about the group being studied.

Answer:

I'm in 10th grade

Explanation:

Answer:

A. g

Explanation:

Answer:

[tex]10.845\ \text{J}[/tex]

Explanation:

m = Mass of box = 0.6 kg

[tex]\theta[/tex] = Angle of incline = [tex]37^{\circ}[/tex]

[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.4

l = Distance the box travels = 2 m

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The potential energy in the spring is given by

[tex]U=mgl\sin\theta+mg\mu_k\cos\theta l\\\Rightarrow U=mgl(\sin\theta+\mu_k\cos\theta)\\\Rightarrow U=0.6\times 9.81\times 2\times(\sin37^{\circ}+0.4\times\cos37^{\circ})\\\Rightarrow U=10.845\ \text{J}[/tex]

The minimum elastic potential energy required is [tex]10.845\ \text{J}[/tex].

Answer:

also choose D and E i belive those are also correct

Answer:

Distance 5 km, Displacement 3 km east

Explanation:

The distance covered by Anthony is 5 km, while his displacement is 3 km.

The distance is defined as the total length of space covered during motion between the starting point and end point, not necessarily a straight line. Whereas displacement is defined as the minimum distance between two points in space, that is a straight line.

Suppose, if you start from one point and walk for 100 meters then come back at the same point that you started your walk, you would have traveled 2 times 100 meters that is 200 meters. But your displacement will be zero because your starting point and the end point are the same.

The given question clarifies the difference between distance and displacement:

Since Anthony walks 4 km east and then walks 1 km west, the distance covered by him is:

distance = 4 + 1 = 5 km

but as he walks west, he comes closer to the starting point, and his displacement is the distance between the starting point and the end point.

displacement = 4 - 1 = 3 km

Referto the figure below for more information.

Learn more about distance and displacement:

https://brainly.com/question/24522401?referrer=searchResults

Answer:

Acidity

Explanation:

A pH indicator measures how acidic or basic a substance is.

Hope this helped :)

Answer:

Gravitational Potential Energy

B Gravitational potential energy

Answer:

You mean in periods.

They have the same number of elctron shells.

But if they are in the same group then they have the sane number oifValence electrons.

Explanation:

Answer:

2.The centripetal force required to keep the pennies in place increases with the distance from the center. Eventually, as the turntable spins faster, the friction force between the turntable and the penny near the edge is not enough to supply the required centripetal force.

Explanation:

centripetal force = m ω² R

here m is mass , ω is angular velocity and R is distance of penny from centre

So this force depends upon R

penny on the outer edge will require  greater centripetal force to move in circular path .

The centripetal force will be provided by frictional force of table which is same for both the coin . Hence the penny on the outer edge will slip off first the moment , frictional force reach its maximum value for it . But it will be sufficient to keep in balance the penny nearer to the centre .

Answer:

94.4

Explanation:

it is

Answer:

94.4 i took the test and got it right :)

hope that helps

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

Answer:

option (i) is correct

Explanation:

as there is no air resistance, no force is acting on the object horizontally, but gravitational acceleration will obviously act, regardless of the air resistance... option (i) is correct

Answer:

Parietal Lobe

Explanation:

Answer:

C

gravity and inertia

Explanation:

Answer:

c :)

Explanation:

Answer:

The correct solution will be "271.95 N".

Explanation:

The given values are:

velocity  

v = 3.5 m/s

mass

m = 9.0 kg

r = 0.6 m

According to the question:

⇒ [tex]F_{branch}=F_{gravity}+F_{centrifugal}[/tex]

⇒             [tex]=mg+\frac{mv^2}{r}[/tex]

On substituting the values, we get

⇒             [tex]=9\times 9.8+\frac{9\times (3.5)^2}{0.6}[/tex]

⇒             [tex]=88.2+\frac{110.35}{0.6}[/tex]

⇒             [tex]=271.95 \ N[/tex]