The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :
LiOH + HNO₂ ----> LiNO₂ + H₂O
The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :
HX + BOH --> BX + H₂O
The reaction with the LiOH and the HNO₂ is :
LiOH + HNO₂ ----> LiNO₂ + H₂O
There is the combination of the H⁺ ions and OH⁻ ions that will form the water.
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1. Explain the difference in
Variation of molar conductivity
with dillusion for strong___
electrolyte and weak electrolyte
-
Explain molar Conductivity at
infinite dillusion...
Derive the expression for
dillusion law
For strong electrolytes, molar conductivity decreases as the solution is diluted because the concentration of ions decreases.
For weak electrolytes, molar conductivity increases as the solution is diluted because as the solution is diluted, the concentration of ions increases.
The expression for the dilution law is A = εcb
What is molar conductivity?The conductivity of a solution containing one mole of an electrolyte when placed between two electrodes spaced one centimeter apart is known as the molar conductivity of the electrolyte. The strength of the electrolyte affects how molar conductivity changes with dilution.
At infinite dilution, the molar conductivity of an electrolyte reaches its maximum value because the electrolyte's ions are so far apart that they no longer interact with one another.
The dilution law or Beer-Lambert law states that the absorbance of a solution is directly proportional to the concentration of the solution and the path length of the light through the solution.
A ∝ cb
Adding a proportionality constant gives:
A = εcb
where;
A is absorbanceε is a constant known as the molar absorptivityc is concentrationb is the path lengthLearn more about molar conductivity at: https://brainly.com/question/26097545
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A helium-filled balloon of the type used in long-distance flying contains 1.5 ✕ 107 L of helium. Let us say you fill the balloon with helium on the ground where the pressure is 837 mm Hg and the temperature is 18.4°C. When the balloon ascends to a height of 6 miles where the pressure is only 707. mm Hg and the temperature is -31°C, what volume is occupied by the helium gas? Assume the pressure inside the balloon matches the external pressure.
We can use the combined gas law to solve this problem:
(P1V1/T1) = (P2V2/T2)
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
We are given that the initial pressure is P1 = 837 mm Hg and the initial volume is V1 = 1.5 × 10^7 L. The initial temperature is T1 = 18.4°C, which we need to convert to Kelvin by adding 273.15:
T1 = 18.4°C + 273.15 = 291.55 K
We are also given that the final pressure is P2 = 707 mm Hg and the final temperature is T2 = -31°C, which we need to convert to Kelvin:
T2 = -31°C + 273.15 = 242.15 K
Now we can solve for the final volume, V2:
(P1V1/T1) = (P2V2/T2)
V2 = (P1V1T2) / (P2T1)
V2 = (837 mm Hg * 1.5 × 10^7 L * 242.15 K) / (707 mm Hg * 291.55 K)
V2 = 5.26 × 10^6 L
Therefore, the volume occupied by the helium gas at the higher altitude is 5.26 × 10^6 L.
Calculate the volume of hydrogen produced at s.t.p. When 25g of zinc are added to excess dilute hydrochloride acid at 31°c and 778mm Hg pressure. (H=1, Zn=65, Cl=35.5, molar volume of a gas at s.t.p = 22.4 dm3
To solve this problem, we need to use the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):
[tex]Zn + 2HCl - > ZnCl_2 + H_2[/tex]
According to the stoichiometry of this equation, one mole of Zn reacts with two moles of HCl to produce one mole of H2. Therefore, we need to determine the number of moles of Zn in 25 g, and then use the mole ratio to find the number of moles of H2 produced.
Finally, we can convert the number of moles of H2 to volume at STP using the molar volume of a gas.
First, we need to calculate the number of moles of Zn in 25 g:
The molar mass of Zn is 65.38 g/mol
The number of moles of Zn in 25 g is:
25 g / 65.38 g/mol = 0.383 mol Zn
Next, we use the mole ratio from the balanced equation to find the number of moles of H2 produced:
According to the balanced equation, one mole of Zn reacts with one-half mole of H2, so we produce 0.5 x 0.383 = 0.192 mol H2.
Finally, we can use the molar volume of a gas at STP to convert the number of moles of H2 to volume:
The molar volume of a gas at STP is 22.4 dm3/mol
Therefore, the volume of H2 produced is:
V = (0.192 mol) x (22.4 dm3/mol) = 4.30 dm3 or 4,300 ml
Therefore, the volume of hydrogen gas produced at STP is 4.30 dm3 or 4,300 ml when 25 g of zinc is added to excess dilute hydrochloric acid at 31°C and 778 mm Hg pressure.
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Chemistry Table balance A+B→C
Table 1 attached
The reaction A + B → C has the following rate expression is 197.62 [A][B] M/s
How to determine rate expression?Using the experimental data to determine the order of the reaction with respect to A and B, assume that the rate of the reaction is given by:
rate = [tex]k[A]^x[B]^y[/tex]
where k = rate constant and
x and y = orders of the reaction with respect to A and B, respectively.
Compare the rates of the reaction in trials 1 and 2 while keeping the concentration of A constant:
rate1/rate2 = [tex]\frac{k[A]^x[B]^y}{k[A]^x[B]^y} = \frac{[B]^y}{[B]^y} = 1[/tex]
Conclude that the reaction is first-order with respect to B.
Similarly, compare the rates of the reaction in trials 1 and 3 while keeping the concentration of B constant:
rate1/rate3 =[tex]\frac{k[A]^x[B]^y}{k[A]^x[B]^y} = \frac{[A]^x}{[A]^x} = 1[/tex]
Therefore, the reaction is first-order with respect to A.
The rate expression for the reaction A + B → C is:
rate = k[A][B]
Using any of the experimental trials to determine the value of the rate constant k, use trial 1:
rate1 =[tex]k[A]^1[B]^1[/tex]
k = [tex]\frac{rate1}{[A]^1[B]^1}[/tex] = (3.30 E-3)/(0.012 M x 0.014 M) = 197.62 M⁻² s⁻¹
Therefore, the rate expression for the reaction A + B → C is:
rate = 197.62 [A][B] M/s
In this case, the units of k are M⁻¹ s⁻¹ because the reaction is first-order with respect to both A and B.
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diffrences in water temperature in the ocean create movement because-
Diffrences in water temperature in the ocean create movement because bodies of water at different temperatures have different densities.
How can the differences be explained?Water that is colder is generally denser than water that is warmer, so when a body of water with colder, denser water is next to a body of water with warmer, less dense water, a density gradient is established. This gradient creates a difference in pressure between the two bodies of water, with the colder, denser water being at a higher pressure than the warmer, less dense water.
This difference in pressure creates a force that drives the movement of water from the denser, colder region to the less dense, warmer region. This movement of water is known as convection, and it can occur both vertically and horizontally in the ocean. Vertical convection occurs when differences in temperature cause water to rise or sink, while horizontal convection occurs when water moves laterally due to differences in temperature.
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missing options:
1. as water heats up, the atoms of water more faster.
2. warm water is pulled more by gravity than cold water.
3. warm and cold water mix and reach the same temperature.
4. bodies of water at different temperatures have different densities.
3. In a lab, students mixed HCI acid with a Mg strip. The Mg started to bubble and dissolved within a few seconds. The rate at which the reaction occurs is determined by the A. number of effective collisions B. large AH C. the stabilization of the reactants D. mass of the products after the reaction
Answer:It might exposed
Explanation: or a spayed H2O might change because different water change over time
Solutions of Pb(NO3)2 and NaCl are combined, resulting in concentration of 0.0050 M Pb(NO3)2 and 0.0025 M NaCl immediately upon mixing. Select the correct description of the final solution, given that the Ksp of PbCl2 is 1.70×10^-5.
A. All solutes remain soluble
B. NaNO3 precipitates
C. Pb(NO3)2 precipitates
D. PbCl2 precipitates
Solutions of [tex]Pb(NO_3)^2[/tex] and [tex]NaCl[/tex] are combined, resulting in concentration of 0.0050 M [tex]Pb(NO_3)^2[/tex] and 0.0025 M [tex]NaCl[/tex] immediately upon mixing. The correct description of the final solution, given that the Ksp of [tex]PbCl_2[/tex] is 1.70×10^-5 is All solutes remain soluble. The correct answer is option A
Upon mixing [tex]Pb(NO_3)^2[/tex] and [tex]NaCl[/tex] , the following reaction occurs:
[tex]Pb(NO_3)^2[/tex] + [tex]2NaCl[/tex] → [tex]PbCl_2[/tex] +[tex]2NaNO_3[/tex]
Using the given concentrations of the reactants, the reaction quotient Qc can be calculated as:
Qc =[tex][Pb^2^+][Cl^-]^2[/tex] = [tex](0.0050 M)(0.0025 M)^2[/tex]
Qc [tex]= 3.13[/tex] × [tex]10^{-3}[/tex]
Comparing Qc to the solubility product constant (Ksp) of [tex]PbCl_2[/tex] , we see that Qc < Ksp. This indicates that the system is not at equilibrium and more [tex]PbCl_2[/tex] can dissolve before the product reaches saturation.
Therefore, no precipitation of [tex]PbCl_2[/tex] will occur, and option A is the correct answer: all solutes remain soluble.
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Which of the following represents an exothermic reaction?
Question 5 options:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) + energy
2H2O(l) + energy → 2H2(g) + O2(g)
6CO2(g) + 6H2O(l) + energy → C6H12O6(aq) + 6O2(g)
Answer:
exothermic reaction is: Reactants → Products + Energy.
Explanation:
Note: ΔH represents the change in energy. If the energy produced in an exothermic reaction is released as heat, it results in a rise in temperature.
a student mixed 20 grams of salt into a beaker with 200 milliliters of warm water. then, the student set the cup of saltwater on a windowsill undisturbed for one week. what changes did the student observe? include what happened when salt was mixed with warm water and what most likely happened to the saltwater after one week.
Answer:
Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.
Explanation:
How much heat, in joules, would be required to raise the temperature of 450 g of
Aluminum (c Al = 0.21 cal/g o C) from 19.5 o C to 31.2 o C?
Answer:
[tex]\huge\boxed{\sf Q = 1105.65\ cal}[/tex]
Explanation:
Given data:Mass = m = 450 g
T₁ = 19.5 °C
T₂ = 31.2 °C
Change in Temperature = ΔT = 31.2 - 19.5 = 11.7 °C
c = 0.21 cal/g °C
Required:Heat = Q = ?
Formula:Q = mcΔT
Solution:Put the given data in the above formula.
Q = (450)(0.21)(11.7)
Q = 1105.65 cal
[tex]\rule[225]{225}{2}[/tex]
A 10 g piece of metal at 50°C absorbs 900 G of energy after which the temperature of the metal is 350°C what is the specific heat of the metal
A 10 g piece of metal at 50°C absorbs 900 G of energy after which the temperature of the metal is 350°C. 0.35J/g°C is the specific heat of the metal.
The amount of heat needed to raise a substance's temperature by one degree Celsius in one gramme, also known as specific heat. Typically, calories and joules per gramme per degree Celsius are used as the measurement units of specific heat.
For instance, water has a specific heat of 1 calorie per gramme per degree Celsius. The notion of specific heat was developed by the Scottish scientist Joseph Black in the 18th century as a result of his discovery that equal masses of different substances required varying quantities.
q = m×c×ΔT
900= 10×c×( 350-50)
c=0.35J/g°C
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Calculate the mass of Kr
in a 9.95 L
cylinder at 91.2 ∘C
and 4.50 bar
.
Propane, C3H8 (approximate molar mass = 44 g/mol) is used in gas barbeques and burns according to the thermochemical equation: C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) ΔH = –2046 kJ. If it takes 1.7 x 103 kJ to fully cook a pork roast on a gas barbeque, how many grams of propane will be required, assuming all the heat from the combustion reaction is absorbed by the pork?
The mass (in grams) of propane that will be required, assuming all the heat from the combustion reaction is absorbed by the pork is 36.56 grams
How do i determine the mass propane required?The mass of propane that will be required can be obtain as illustrated below:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g) ΔH = –2046 KJ
Molar mass of C₃H₈ = 44 g/molMass of C₃H₈ from the balanced equation = 1 × 44 = 44 gFrom the balanced equation above,
2046 KJ of heat energy required 44 g of propane, C₃H₈
Therefore,
1.7×10³ KJ of heat energy will require = (1.7×10³ KJ × 44 g) / 2046 KJ = 36.56 g of propane, C₃H₈
Thus, we can conclude that the mass of propane, C₃H₈ required is 36.56 grams
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The reactant concentration in a zero-order reaction was 6.00×10−2 M
after 175 s
and 3.50×10−2 M
after 315 s
. What is the rate constant for this reaction?
What volume will 5.00 mol of an ideal gas occupy at 25 C and 153 kPa of pressure?
79.8L is the volume for 5.00 mol of an ideal gas occupy at 25 C and 153 kPa of pressure.
A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.
P×V = n×R×T
153000×V = 5×0.082×298
V= 79.8L
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Why are leaves green
Answer:
Leaves are green due to the presence of an organelle chloroplast (in abundance) which contains the pigment chlorophyll
Explanation:
Now saying chlorophyll pigment is a green pigment might be slightly incorrect. The two famous types (Chlorophyll a, Chlorophyll b) only absorb red and blue light from the atmosphere and reflect green light hence giving the pigment a green appearance and lastly giving the leaves a green color too
Answer:
Chlorophyll
Explanation:
Plants are often seen as green to the human eye due to the presence of chlorophyll, which is the primary pigment used in photosynthesis. Chlorophyll absorbs light in the red and blue-violet parts of the spectrum, but reflects or transmits green light, resulting in the characteristic green color of leaves.
What is the molar mass of a compound if a gaseous sample has a density of 0.978 g/L at 30 °C and 615 torr? The temperature in Celsius is known to two significant figures.
If a gaseous sample has a density of 0.978 g/L at 30 °C and 615 torr, the molar mass of the compound is 24.8 g/mol.
To calculate the molar mass of the compound, we first need to calculate the number of moles present in the gaseous sample using the ideal gas law:
PV = nRT
Where P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.
Converting the given pressure of 615 torr to atm:
615 torr = 0.811 atm
Converting the given temperature of 30°C to Kelvin:
30°C + 273.15 = 303.15 K
Rounding off to two significant figures, we get:
P = 0.81 atm
T = 303 K
Now, rearranging the ideal gas law equation to solve for n:
n = PV/RT
Substituting the given values:
n = (0.978 g/L) x (1 L) / (0.081 atm x 0.0821 L atm/mol K x 303 K)
n = 0.0394 mol
Next, we can calculate the molar mass of the compound using the formula:
molar mass = mass / mole
molar mass = (0.978 g/L) x (1 L) / 0.0394 mol
molar mass = 24.8 g/mol
Therefore, 24.8 g/mol is the molar mass of the compound.
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What is the distance (km)?
What is the magnitude (M)?
The S-P difference (sec) is used to calculate the distance (km) between an earthquake epicenter and a seismic station, while the magnitude (M) is a measure of the energy released during the earthquake.
These parameters are important for understanding the severity and impact of an earthquake, as well as for predicting future seismic activity.
The S-P difference (sec) refers to the time difference between the arrival of the primary (P) waves and the secondary (S) waves at a seismic station. This time difference is used to calculate the distance (km) between the earthquake epicenter and the seismic station, using the equation: distance (km) = S-P difference (sec) x 8 km/sec. This calculation assumes that the waves travel at a constant speed through the Earth's interior.
The magnitude (M) of an earthquake is a measure of the energy released during the earthquake, and is usually determined using a seismometer. The magnitude scale is logarithmic, meaning that each increase of one unit represents a tenfold increase in seismic energy. For example, an earthquake with a magnitude of 5.0 is ten times more powerful than one with a magnitude of 4.0, and 100 times more powerful than one with a magnitude of 3.0.
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CHEMISTRY chemistry Table balance A+B→C Table2
Answer:
zn + Hcl cual es su rreaccion
7 Suppose you weighed a different sample, of 2.500-g, which consisted of a mixture of CuO and potassium chloride and dissolved it in 25.00 mL of 0.437 M H₂SO4 solution. Some acid remains after treatment of the sample. Determine: a) If 35.4-mL of 0.108 M NaOH were required to titrate the excess sulfuric acid, how (6) many moles of CuO were present in the original sample?
The initial sample had 0.010925 mol of Copper(II) oxide, or one mole.
What exactly is kinetic-molecular theory?The kinetic-molecular theory, which describes the states of matter, is based on the presumption that matter is composed of minuscule particles that are constantly in motion. This theory explains the observable properties and behaviours of solids, liquids, and gases. The container's walls and the quickly moving particles' collisions with one another are constant.
Copper(II) oxide + Sulfuric acid → Cupric sulfate + Water
One mole of Copper(II) oxide interacts with one mole of Sulfuric acid, as shown by the equation. The amount of Sulfuric acid that reacted with the Copper(II) oxide in the sample is therefore equal to the amount of Copper(II) oxide in the sample.
We must first determine how many moles of Sulfuric acid interacted with the sample:
moles Sulfuric acid = concentration × volume
moles Sulfuric acid = 0.437 mol/L × 0.025 L
moles Sulfuric acid = 0.010925 mol
Since the acid is in excess, the moles of Sulfuric acid remaining after treatment of the sample is:
moles Sulfuric acid remaining = moles Sulfuric acid added – moles Sulfuric acid reacted
moles Sulfuric acid remaining = 0.437 mol/L × 0.0354 L – 0.010925 mol
moles Sulfuric acid remaining = 0.007571 mol
To determine the number of moles of Copper(II) oxide in the original sample, we can use the following equation:
moles Copper(II) oxide = moles Sulfuric acid reacted = 0.010925 mol
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If 8.25
mol of C5H12
reacts with excess O2,
how many moles of CO2
will be produced by the following combustion reaction?
C5H12+8O2⟶6H2O+5CO2
The given reaction equation tells us that for every 1 mol of C₅H₁₂, 5 moles of CO₂ will be produced. Since 8.25 mol of C₅H₁₂ is given, 8.25 mol C₅H₁₂ x 5 moles CO₂/1 mol C₅H₁₂ = 41.25 moles CO₂ will be produced.
What is reaction?Reaction is the process of responding to an event or stimulus in a particular way. It can occur at the physical, cognitive, or emotional level. Physically, a reaction could be as simple as a reflex or as complex as a multi-step process. Cognitively, it could involve forming a judgment or understanding. Emotionally, it could involve feelings of fear, shock, anger, or joy. In the context of science, reactions are often chemical or physical processes that involve the conversion of one set of substances into another.
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What is volume of 12.0 g of carbon dioxide at stp?
Answer: 6.11 L
Explanation:
STP= 1atm, 273.15K
Molar mass of CO2=44.01g/mol so n= (12.0/44.01)
PV=nRT
V=(nRT)/P
V=((12.0/44.01)(0.0821)(273.15))/1
V=6.11L
Answer the following questions in complete sentences, and justify your responses.
After how many time intervals (shakes) did one-half of your atoms (candies) decay?
What is the half-life of your substance?
If the half-life model decayed perfectly, how many atoms would be remaining (not decayed) after 12 seconds?
If you increased the initial number of atoms (candies) to 300, would the overall shape of the graph be altered? Explain your answer.
Go back to your data table and for each three-second interval, divide the number of candies decayed by the number previously remaining and multiply by 100. Show your work.
The above percentage calculation will help you compare the decay modeled in this experiment to the half-life decay of a radioactive element. Did this activity perfectly model the concept of half-life? If not, was it close?
Compare how well this activity modeled the half-life of a radioactive element. Did the activity model half-life better over the first 12 seconds (four decays) or during the last 12 seconds of the experiment? If you see any difference in the effectiveness of this half-life model over time, what do you think is the reason for it?
To answer these questions, we need to know what substance you are referring to, as well as the data from the experiment.
1. After a certain number of time intervals (shakes), one-half of your atoms (candies) would decay. This number would depend on the specific substance and its half-life.
2. The half-life of a substance is the time it takes for half of its atoms to decay.
3. If the half-life model decayed perfectly, the number of remaining atoms after 12 seconds would depend on the initial number of atoms and the half-life of the substance.
4. If you increased the initial number of atoms (candies) to 300, the overall shape of the graph would not be altered. This is because the half-life decay is a percentage-based process, meaning it would still follow an exponential decay pattern.
5. To calculate the percentage of decay for each three-second interval, you would divide the number of candies decayed by the number previously remaining and multiply by 100. This would show the percentage of decay for each interval.
6. This activity may not perfectly model the concept of half-life, but it can provide a close approximation. Any discrepancies may be due to experimental errors or limitations.
7. To compare how well this activity modeled the half-life of a radioactive element, you would need to analyze the decay percentages over time. If there are differences in the effectiveness of the half-life model, it could be due to the limitations of the experimental setup, such as using candies as a representation of atoms.
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Can someone help me ?
The problem requires the calculation of the volume of carbon dioxide produced at STP when 587 mol of octane combusts; ,therefore, the volume of CO₂ produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
The ideal gas law is given by:
PV = nRT
P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.
587 mol octane × (16 mol CO₂/2 mol octane) = 4696 mol CO2
Next, one can use the ideal gas law to calculate the volume of CO₂ produced at 36.0 °C and 0.995 atm. Then one needs to convert the temperature to kelvin by adding 273.15:
T = 36.0 °C + 273.15 = 309.15 K
Substituting the values into the ideal gas law:
PV = nRT
V = nRT/P
V = (4696 mol)(0.0821 L·atm/mol·K)(309.15 K)/(0.995 atm)
V ≈ 124,700 L
Therefore, the volume of CO2 produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
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If heat is going INTO the system, that means that energy must have come OUT FROM the ____________
If heat is going into a system, it means that energy must have come out from the surroundings.
How is energy/heat transferred?Heat is a form of energy transfer from a hotter object to a cooler one, and the direction of heat flow is always from the hotter object to the cooler one.
Therefore, if heat is entering a system, it must be gaining energy from its surroundings, which are at a lower temperature and therefore have less thermal energy.
Conversely, if heat is leaving a system, it means that energy is being transferred from the system to its surroundings, which are at a higher temperature and therefore have more thermal energy.
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1. Which is an example of heat being transferred through conduction?
2. 6 C (s) + 3 H2 → C6H12 (l)
ΔH = -903
Therefore, this reaction (loses/gains) heat/energy.
Answer:
9. B
10. Loses
Explanation:
9. Conduction is The procedure by which thermal energy or electricity is directly transported through a substance without the material moving when there is a variance in temperature between adjacent parts. Only choice B shows this process.
10. In exothermic reactions, energy/heat is lost. Exothermic reactions are characterized by a negative delta H, such as the delta H for the reaction show.
How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat
The triacylglycerol depicted may be converted to a saturated fat by adding two hydrogen atoms (H2) to each carbon-carbon double bond. Six hydrogen atoms (H2) are required to convert the three carbon-carbon double bonds in triacylglycerol into saturated fat.
This is so that the triacylglycerol may be converted to a saturated fat by using hydrogen molecules (H2) to saturate the double bonds.
Triacylglycerol's physical characteristics, such as its melting point, will similarly be altered by the addition of hydrogen molecules (H2), making it more solid at normal temperature.
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A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 109.0 L and a pressure of 107.0 atm at 25.0 °C. After a while she notices that the valve has not been closed properly. The pressure had dropped to 97.0 atm. (The tank is still at 25.0 °C.) How many moles of gas has she lost?
The number of mole of the gas lost, given that the pressure had dropped to 97.0 atm is 44.5 moles
How do i determine the number of mole lost?First, we shall determine the initial mole of the gas. Details below:
Initial volume (V₁) = 109.0 LInitial temperature (T₁) = 25 °C = 25 + 273 = 298 KInitial pressure (P₁) = 107.0 atmGas constant (R) = 0.0821 atm.L/mol KInitial mole (n₁) =?P₁V₁ = n₁RT₁
107 × 109 = n₁ × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n₁ = (107 × 109) / (0.0821 × 298)
n₁ = 476.7 mole
Next, w shall determine the final mole of the gas. Details below
Final volume (V₂) = 109.0 LFinal temperature (T₂) = 25 °C = 25 + 273 = 298 KFinal pressure (P₂) = 97.0 atmGas constant (R) = 0.0821 atm.L/mol KFinal mole (n₂) =?P₂V₂ = n₂RT₂
97 × 109 = n₂ × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n₂ = (97 × 109) / (0.0821 × 298)
n₂ = 432.2 mole
Finally, we shall determine the mole of the gas that was lost. Details below:
Initial mole (n₁) = 476.7 molesFinal mole (n₂) = 432.2 molesMole lost =?Mole lost = n₁ - n₂
Mole lost = 476.7 - 432.2
Mole of gas lost = 44.5 moles
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Arrange the following ions in order of increasing ionic radius: selenide ion, rubidium ion, bromide ion, strontium ion.
Answer:
Br, Se, Sr, Rb
Explanation:
Atomic radius increases as you move to the left and down the periodic table. The increase in radius as you move left is due to decreasing effective nuclear charge (the pull an electron feels from the nucleus) since the number of protons decrease. The increase in radius as you move down is due to a higher number of principle energy levels (orbital in which the electron is located relative to the atom's nucleus), causing the electrons to be farther from the nucleus.
Five types begging the question
Five types of begging the question include: Circular reasoning, Loaded question, False analogy, Suppressed evidence and Appeal to authority.
Begging the question is a logical fallacy that occurs when someone assumes the truth of a premise in their argument, without providing evidence or proof. There are several types of begging the question:
1. Circular reasoning: This occurs when someone uses their conclusion as one of their premises, essentially assuming what they are trying to prove.
Example: "God exists because the Bible says so, and the Bible is the word of God."
2. Loaded question: This occurs when someone asks a question that assumes a particular answer or perspective.
Example: "Have you stopped beating your spouse yet?" This question assumes that the person being asked was previously beating their spouse.
3. False analogy: This occurs when someone uses an analogy that is not relevant or applicable to the argument at hand.
Example: "Banning guns is like banning cars because both can be used to kill people." This analogy is false because cars have a primary function of transportation, whereas guns have a primary function of killing.
4. Suppressed evidence: This occurs when someone ignores or dismisses evidence that contradicts their argument.
Example: "I don't believe in climate change because it's cold outside today." This argument suppresses evidence that shows long-term trends of warming temperatures.
5. Appeal to authority: This occurs when someone uses an authority figure or expert as evidence, without providing any other support for their argument.
Example: "Dr. Smith says that this diet is the best for losing weight, so it must be true." This argument appeals to Dr. Smith's authority without providing any evidence or research to support the claim.
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