Need help here guys.....
three similar bars of length 200 cm , 300cm and 360 cm are cut into equal pieces. find
the largest possible
area of square which
can be made from any of the three pieces.(3mks)

If a time capsule has been buried 98m away from the cave at a bearing of 312. the time capsule is buried about 82.2 meters west of the cave.

To find how far west the time capsule is buried, we need to find the horizontal component of the displacement vector that points from the cave to the location of the time capsule. We can use trigonometry to do this:

cos(312°) = adjacent/hypotenuse

The hypotenuse is the distance between the cave and the time capsule, which is 98m. The adjacent side represents the horizontal distance between the two points, which is what we want to find. Rearranging the equation, we get:

adjacent = cos(312°) x hypotenuse

adjacent = cos(312°) x 98

adjacent ≈ 82.2

Therefore, the time capsule is buried about 82.2 meters west of the cave.

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Step-by-step explanation:

The coordinates of point B: (0,6)

Coordinates of point C: (3,8)

A kite has 4 sides, of which we have 2 equal pairs, thus the coordinates of point D must be (6,6)

Answer:

(6,6)

Step-by-step explanation:

The question is asking us to complete the half figure, and make it a kite.  We can see that the 2 lines AB and BC are half of the shape.  In the attachment, I drew a line of symmetry down the middle of the shape.  

I also created a point, Y, down the red line, AC, to represent the perpendicular bisector of the 2 diagonals.  We can see that line segment BY is the radius of the entire line BD.  

This radius is 3 units, so we now know that the diameter horizontally is 6 units.  We can draw this on the other side to create point D.  

This means that point D is at (6,6).

See attachment for more information, hope this helps!

The critical numbers are 4, -4.

To find the critical numbers of the function g(v) = v³ - 48v + 6, follow these steps:

1. Find the derivative of the function, g'(v).
2. Set g'(v) equal to 0 and solve for v.
3. List the critical numbers as a comma-separated list.

Step 1: Find the derivative of the function.
g(v) = v³ - 48v + 6
Using the power rule, the derivative is:
g'(v) = 3v² - 48

Step 2: Set g'(v) equal to 0 and solve for v.
3v² - 48 = 0
Divide both sides by 3:
v² - 16 = 0
Factor the equation:
(v - 4)(v + 4) = 0
Solve for v:
v = 4, -4

Step 3: List the critical numbers.
The critical numbers of the function g(v) = v³ - 48v + 6 are v = 4, -4.

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According to the 68-95-99.7 rule, approximately 68% of the distribution falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.

In this case, the mean is 7.06 minutes and the standard deviation is 0.75 minutes. Therefore, the range of times that covers the middle 95% of the distribution would be from the mean minus two standard deviations (7.06 - 2 x 0.75 = 5.56 minutes) to the mean plus two standard deviations (7.06 + 2 x 0.75 = 8.56 minutes).

In other words, 95% of the male college students' mile run times are expected to fall between 5.56 and 8.56 minutes. This means that most of the students' mile run times will be within this range, and only a small percentage will be outside of it.

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The palm tree is 21 feet tall.

To find the height of the palm tree, we can use the concept of similar triangles, where the ratio of corresponding sides is equal. In this case, the terms we need are Katie's height, her shadow length, the palm tree's shadow length, and the palm tree's height.

Step 1: Set up the proportion using the given information.
(Katie's Height / Katie's Shadow Length) = (Palm Tree Height / Palm Tree Shadow Length)

Step 2: Plug in the given values.
(6 ft / 2.5 ft) = (Palm Tree Height / 8.75 ft)

Step 3: Solve for Palm Tree Height.
(6 ft / 2.5 ft) * 8.75 ft = Palm Tree Height
2.4 * 8.75 ft = Palm Tree Height

Step 4: Calculate the height.
21 ft = Palm Tree Height

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a. The limit does not exist.
b. The limit is equal to 4.

a. To find the limit as x approaches 2, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 2 from the left
We have f(x) = x - 1 for x < 2. So, as x approaches 2 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 2 from the right
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 2 from the right, f(x) approaches 6.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 2 does not exist.
b. To find the limit as x approaches 6, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 6 from the left
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 6 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 6 from the right
We have f(x) = x + 4 for x > 6. So, as x approaches 6 from the right, f(x) approaches 10.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 6 does not exist.
Therefore, the correct choices are:
a. The limit is not -oo or co and does not exist.
b. lim = 4.

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The best estimate of the charge Zachary will later find on his credit card statement is $20

The formula to be used is -

Amount in USD = Amount of MYR/Value of one MYR

As, 3.04 MYR is 1 USD performing money conversion of 58 MYR

So, 58 MYR will be = 58/3.04

Divide the values in Right Hand Side of the equation to find the value of MYR in USD

Value in USD = $19.07

Hence, the credit card statement will reflect usage of $20 (since it is the closes correct option and we have been asked the best estimate).

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The value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)

Circle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, secants, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.

GH² = IH × JI {secant tangent segments}

JI = 12 - IH, we shall represent IH with x so that;

8² = x(12 - x)

64 = 12x - x²

x² - 12x + 64 = 0 {rearrange to get a quadratic equation}

with the quadratic formula;

x = [12 + √(-112)]/2 or x = = [12 - √(-112)]/2

√(-112) = 4i√7 {where i = √(-1)}

so;

x = (6 + 2i√7) or x = (6 - 2i√7)

Therefore, the value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)

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Answer: Yes those are correct good job

Step-by-step explanation:

The shows that Luther can expect the speed to be 51 miles/hour when he throws 80 pitches and 64 miles/hour when he throws 54 pitches.

The average speed of Luther's pitches when he throws 80 pitches will be:

y = -0.511x + 91.636

= -0.511(80) + 91.636

= 50.756

= 51

Also, the number of pitches that Luther can throw when the speed is 64 miles per hour will be:

y = -0.511x + 91.638

64 = -0.511x + 91.638

0.511x = 91.638 - 64

0.511x = 27.636

x = 54

Therefore, the number of pitches will be 54.

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Answer:

Because the absolute value of the correlation coefficient, 0.9672, is very close to 1, Luther can be very confident in the predictions.

Step-by-step explanation: Edmentum Answer

Thus, approximately 33.33% of the data values are between 25 and 45.

A box-and-whisker plot, also known as a box plot, is a graphical representation of a set of data that shows the distribution of the data along a number line. The plot is composed of a box that represents the middle 50% of the data, along with two "whiskers" that represent the lowest and highest values in the data set. The box is drawn between the first and third quartiles of the data, with a line inside the box representing the median value. The distance between the first and third quartiles is known as the interquartile range (IQR), which can be used to identify outliers in the data. Box-and-whisker plots are useful for comparing the distribution of data between different groups or data sets.

Here,

To find the percentage of the data values that are between 25 and 45 on the given box-and-whisker plot, we need to find the area of the box that is between the lower quartile (Q1) and the median (Q2). From the plot, we can see that the lower quartile (Q1) is at 30, and the median (Q2) is at 40. The interquartile range (IQR), which is the distance between Q1 and Q3, is 20.

Therefore, the box extends from 30 to 40, which is a distance of 10. The total length of the plot is 30 (from 25 to 55), so the percentage of data values between 25 and 45 is:

10/30 * 100% = 33.33%

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Complete question:

The box-and-whisker plot below represents some data set. What percentage of the data values are between 25 and 45?

The amount made by Caroline is $593.75 and 200 + 0.25x when she made $1574 and $x in sales respectively.

The total amount will be given by the formula using percentage -

Total amount = Base salary + 25% × her total sales

Keep the value in equation when she made $1575

Total amount = 200 + 25% × 1575

Total amount = 200 + 393.75

Total amount = $593.75

Keep the value in equation when she made $x

Total amount = 200 + 25% × x

Total amount = 200 + 0.25x

Hence, the earned amount is $593.75 and 200 + 0.25x.

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The complete question is -

Caroline works in a department store selling clothing. She makes a guaranteed salary of $200 per week, but is paid a commision on top of her base salary equal to 25% ofher total sales for the week. How much would Caroline make in a week in which she made $1575 in sales? How much would Caroline make in a week if she made x dollars in sales?

Answer:

Step-by-step explanation:

The center of mass of the metal plate with density rho(x,y) = αx+ βy g/cm2 must lie on the line x + y = 7/6.

To find the center of mass of the metal plate, we need to calculate the coordinates of its centroid (X, Y). The coordinates of the centroid are given by:

X = (1/M) ∬(R) x ρ(x,y) dA, Y = (1/M) ∬(R) y ρ(x,y) dA

where M is the total mass of the plate, R is the region of integration (0 ≤ x ≤ 1, 0 ≤ y ≤ 1), and dA is the differential area element.

We can calculate the total mass M of the plate as follows:

M = ∬(R) ρ(x,y) dA = α/2 + β/2 = (α + β)/2

Using the given density function, we can calculate the integrals for X and Y:

X = (1/M) ∬(R) x ρ(x,y) dA = (2/αβ) ∬(R) x(αx+βy) dA = (2/3)(α+β)

Y = (1/M) ∬(R) y ρ(x,y) dA = (2/αβ) ∬(R) y(αx+βy) dA = (2/3)(α+β)

Thus, the coordinates of the centroid are (X, Y) = ((2/3)(α+β), (2/3)(α+β)).

Now, if we substitute X + Y = (4/3)(α+β) into the equation x + y = 7/6, we get:

x + y = 7/6

2x + 2y = 7/3

2(x+y) = 4/3(α+β)

x+y = (2/3)(α+β)

which shows that the centroid lies on the line x + y = 7/6. Therefore, the center of mass must also lie on this line.

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Answer:To find the value of x, bring the all the variable to the left side and bring all of the remaining values to the right side. You then simplify the values to find the answer.

Step-by-step explanation:

Answer:

im not sure bud because i don't know  what is the full question?

Step-by-step explanation:

Answer:

7.6 cm

Step-by-step explanation:

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

[tex]a^{2}[/tex] + [tex]6.5^{2}[/tex] = [tex]10^{2}[/tex]

[tex]a^{2}[/tex] + 42.25 = 100 Subtract 42.25 from both sides

[tex]a^{2}[/tex] = 57.57

[tex]\sqrt{\a^{a} }[/tex] = [tex]\sqrt{57.57}[/tex]

a ≈ 7.6

Helping in the name of Jesus.

Answer:

7.6 cm

Step-by-step explanation:

a^2+ b^2=c^2

a^2+6.5^2=10^2

a^2+42.25=100 subtract 42.25 from both sides

a^2=57.57

a=√57.57

a=7.6 cm

57 students most likely got heads between 45 and 60 times.

To determine the number of students who got heads between 45 and 60 times, we'll use the normal distribution properties. First, we need to calculate the z-scores for 45 and 60:

Z = (X - μ) / σ

For 45 heads:
Z1 = (45 - 50) / 5 = -1

For 60 heads:
Z2 = (60 - 50) / 5 = 2

Next, we need to find the probability that a student falls between these z-scores. We can do this by looking up the z-scores in a standard normal distribution table or using a calculator. The probabilities corresponding to these z-scores are:

P(Z1) = 0.1587
P(Z2) = 0.9772

Now, subtract P(Z1) from P(Z2) to get the probability of a student's result falling between 45 and 60 heads:

P(45 ≤ X ≤ 60) = P(Z2) - P(Z1) = 0.9772 - 0.1587 = 0.8185

Finally, multiply this probability by the total number of students (70) and round to the nearest whole number:

Number of students = 0.8185 * 70 ≈ 57

So, approximately 57 students most likely got heads between 45 and 60 times.

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The average x-coordinate of the points in the prism is 3.

A prism is a polyhedron that has two parallel and congruent polygonal bases that are linked by parallelogram faces that are lateral. The height of the prism is the perpendicular distance between the bases.

The formula for calculating the average x-coordinate of the points in the prism D = {(x,y,z):0 ≤ x ≤ 6,0 ≤ y ≤ 18-3x, 0 ≤ z ≤ 4} is$$\frac{\text{sum of all x-coordinates}}{\text{number of vertices}}$$

The vertices of a prism are the points where two adjacent edges meet. There are eight vertices in a rectangular prism, and the x-coordinate of each vertex is either 0 or 6. The x-coordinates of the vertices are $$0,0,0,0,6,6,6,6.

$$The sum of all the x-coordinates is 24. Thus, the average x-coordinate of the points in the prism is$$\frac{24}{8}=\boxed{3}.

$$Hence, the average x-coordinate of the points in the prism is 3.

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The congruent triangles is solved and the triangles are congruent by AAS postulate

Given data ,

Let the two triangles be represented as ΔRQT and ΔTQS

And , the side TQ is the common side of both the triangles

Now , the measure of ∠TQR ≅ measure of ∠TQS ( given )

And , the measure of ∠TRQ ≅ measure of ∠TSQ ( given )

So , Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)

Hence , the triangles are congruent by ASA postulate

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The estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.

Let V = (1/3)πr²h be the volume of the cone, where r and h are the base radius and height of the cone, respectively.

Let dr and dh be the possible errors in the measurements of r and h, respectively.

Then, the actual dimensions of the cone are (r+dr) cm and (h+dh) cm, respectively.

The differential of V is given by:

dV = (∂V/∂r)dr + (∂V/∂h)dh

We have:

∂V/∂r = (2/3)πrh and ∂V/∂h = (1/3)πr²

Substituting the given values, we get:

∂V/∂r = (2/3)π(10 cm)(25 cm) = 500π/3

∂V/∂h = (1/3)π(10 cm)² = 100π/3

Substituting into the differential equation, we get:

dV = (500π/3)dr + (100π/3)dh

Using the given maximum error of 0.1 cm for both r and h, we have:

|dr| ≤ 0.1 cm and |dh| ≤ 0.1 cm

Therefore, the maximum possible error in V is given by:

|dV| = |(500π/3)(0.1 cm) + (100π/3)(0.1 cm)|

|dV| = 50π/3 + 10π/3

|dV| = 60π/3

|dV| = 20π cm³

Therefore, the estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.

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Answer:

D(6,4).

Step-by-step explanation:

The shape ABCD is a square.

By definition, the diagonals are equal.

The diagonal from A to C is 6 units long. Therefore, you should get your point D by drawing across from B to the right by 6.

D(6,4).

There were 490 walkers at the 10k fund-raiser.

The ratio of runners to walkers is 5:7, that means that the every five runners, there are 7 walkers so therefore we will use ratio formula.

If there have been 350 runners, we can use this ratio to discover what number of walkers there were:

5/7 = 350/x

Where x is the number of walkers.

To solve for x, we will cross-multiply:

5x = 7 * 350

5x = 2450

x = 490

Consequently, there were 490 walkers at the 10k fund-raiser.

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The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.

The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:

Let the probability that a student completed the homework be P(B).

Also, let the probability that a student passed the test be P(A)

P(A or B) = P(A) + P(B) - P(A * B)

From the data table:

The number of students who passed the test = 18

The number of students who completed the homework = 17

The number of students who both passed the test and completed the homework = 15.

Total number of students = 27

P(A) = 18/27

P(B) = 17/27

P(A*B) = 15/27

Therefore,

P(A or B) = 18/27 + 17/27 - 15/27

P(A or B) = 20/27

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The compound interest generated on the investment is roughly $813.67, which is the solution to the question based on compound interest.

The initial sum of money invested or borrowed, upon which interest is based, is referred to as the principle. The principal is then periodically increased by the interest, often monthly or annually, to create a new principal sum that will accrue interest in the ensuing period.

Using the compound interest calculation, we can determine the interest earned on Sanchez's investment:

[tex]A = P(1 + \frac{r}{n} )^{(n*t)}[/tex]

where A is the overall sum, P denotes the principal (the initial investment), r denotes the yearly interest rate in decimal form, n denotes the frequency of compounding interest annually, and t denotes the number of years.

In this case, P = $3,000, r = 0.06 (6%), n = 365 (compounded daily),

and t = 4.

Plugging in the values, we get:

[tex]A = 3000(1 + \frac{0.06}{365} )^{(365*4)}[/tex]

A= $3813.67

The difference between the final amount and the principal is the interest earned.

Interest = A - P

Interest = $3813.67 - $3000

Interest = $813.67

As a result, the investment's interest yield is roughly $813.67.

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Answer:

the answer is 14,986 centimetres

The final value is f'(-1) = 16,777,2160.

We can use the chain rule and the power rule of differentiation to find f'(-1).

Recall that the chain rule states that if f(x) = g(h(x)), then f'(x) = g'(h(x)) h'(x). Applying this rule to f(x) = (h(x))^10, we get:

f'(x) = 10(h(x))^9 h'(x)

Now, we can substitute x = -1 into the above equation, since we are asked to find f'(-1). Thus, we have:

f'(-1) = 10(h(-1))^9 h'(-1)

We are given that h(-1) = 3 and h'(-1) = 6, so we can substitute these values to get:

f'(-1) = 10(3)^9 (6)

Simplifying, we get:

f'(-1) = 16,777,2160

Therefore, f'(-1) = 16,777,2160

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To find the volume of the cone, we first need to find its radius. Since the pyramid is contained within the cone such that the vertices of the base of the pyramid are touching the edge of the cone, the diagonal of the square base of the pyramid is equal to the diameter of the base of the cone. The diagonal of the square base of the pyramid is:

d = √(10^2 + 10^2) = √200 = 10√2 cm

Therefore, the diameter of the base of the cone is 10√2 cm, and the radius is 5√2 cm.

The volume of the cone can be calculated using the formula:

V = (1/3)πr^2h

where r is the radius of the base of the cone and h is the height of the cone.

Substituting the given values, we get:

V = (1/3)π(5√2)^2(20)

V = (1/3)π(50)(20)

V = (1/3)(1000π)

V = 1000/3 * π

Using 3.14 as the decimal approximation for π, we get:

V ≈ 1046.35 cubic centimeters

Therefore, the volume of the cone is approximately 1046.35 cubic centimeters. The answer is A.

a) Area (Ф(R)) = 5184 (b) Area (Ф(R)) = 25920

Let J be the Jacobian of Ф. We have J = det(DФ) = det([3 9; 9 9]) = -72.

(a) For R = [0,9] × [0,6], we have

Ф(R) = {(3u+9v,9u+9v) | 0 ≤ u ≤ 9, 0 ≤ v ≤ 6}.

The area of Ф(R) is given by the double integral over R of the Jacobian:

Area (Ф(R)) = ∬R |J| dudv

= ∫0^9 ∫0^6 72 dudv

= 5184.

Therefore, the area of Ф(R) is 5184.

(b) For R = [2,20] × [1,17], we have Ф(R) = {(3u+9v,9u+9v) | 2 ≤ u ≤ 20, 1 ≤ v ≤ 17}. The area of Ф(R) is given by the double integral over R of the Jacobian:

Area (Ф(R)) = ∬R |J| dudv = ∫2^20 ∫1^17 72 dudv = 25920.

Therefore, the area of Ф(R) is 25920.

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Answer:

$7.35

Step-by-step explanation: