The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.
How to calculate volume?The volume of a solution given the concentration can be calculated using the following expression;
CaVa = CbVb
Where;
Ca = initial concentrationVa = initial volumeCb = final concentrationVb = final volumeAccording to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.
0.75 × Va = 500 × 0.3
0.75Va = 150
Va = 150/0.75
Va = 200mL
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Why is leaf called the kitchen of the plant?
Plants rely on their leaves to produce food through a process called photosynthesis. This involves converting light energy into organic compounds, like sugars, using chloroplasts that contain the pigment chlorophyll. By combining carbon dioxide and water with light energy, plants create glucose, which serves as an energy source and building material. Along with stomata, which help regulate gas exchange with the environment, the leaf acts as the plant's primary kitchen for food production.
Chemistry balance QUESTION
reaction: AB₂C (g) → B₂ (g) + AC (g), find the value of K. At equilibrium, [AB₂C]=0.0168 M, [B₂]= 0.007 M, and [AC] = 0.0118 M
The value of the equilibrium constant, K, for the reaction is 0.0049
How do i determine the equilibrium constant?The following data were obtained from the quesion:
AB₂C (g) ⇌ B₂(g) + AC(g) Concentration of AB₂C, [AB₂C] = 0.0168 MConcentration of B₂, [B₂]= 0.007 MConcentration of AC, [AC] = 0.0118 MEquilibrium constant (K) =?The equilibrium constant for the reaction can be obtain as illustrated below:
Equilibrium constant = [B₂][AC] / [AB₂C]
Equilibrium constant = (0.007 × 0.0118) / 0.0168
Equilibrium constant = 0.0049
Thus, from the above calculation, the equilibrium constant, K for the reaction is 0.0049
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Help please! I'll give brainliest and 5 stars if you show work!
To solve this problem, we can use the formula:
q = m × c × ΔT
where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
First, let's calculate the mass of water:
m = 225.0 g
Next, let's calculate the heat absorbed by the water:
q_water = m × c × ΔT
q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)
q_water = 3749.8 J
Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:
q_calorimeter = - (q_water + q_metal)
q_calorimeter = - (3749.8 J + 4274 J)
q_calorimeter = - 8023.8 J
Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.
If 3.24 mol
of an ideal gas has a pressure of 2.19 atm
and a volume of 76.67 L,
what is the temperature of the sample in degrees Celsius?
The temperature of the sample in degrees Celsius is 358.14°C.
How to calculate temperature?The temperature of a substance can be calculated by using the following ideal gas law expression;
PV = nRT
Where;
P = pressureV = volume n = no of molesR = gas law constantT = temperatureAccording to this question, 3.24 mol of an ideal gas has a pressure of 2.19 atm and a volume of 76.67 L. The temperature can be calculated as follows;
2.19 × 76.67 = 3.24 × 0.0821 × T
167.9073 = 0.266004T
T = 167.9073/0.266004
T = 631.14K
T {°C} = 631.14 - 273 = 358.14°C
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When calcium metal is placed in water, hydrogen gas is produced. Determine the mass of H2 produced at 25 C and 0.967 atm when 525 mL of the gas is collected over water. Consider vapour pressure of water be 0.0313 atm.
The mass of hydrogen gas produced, given that 525 mL of the gas was collected over water is 0.04 grams
How do i determine the mass of hydrogen gas produced?First, we shall determine the mole of the dry hydrogen gas collected. Details below:
Vapour pressure = 0.0313 atmPressure of wet gas = 0.967 atmPressure of dry gas (P) = 0.967 - 0.0313 = 0.9357 atmTemperature (T) = 25 °C = 25 + 273 = 298 KVolume of gas (V) = 525 mL = 525 / 1000 = 0.525 LGas constant (R) = 0.0821 atm.L/mol KNumber of mole (n) =?PV = nRT
0.9357 × 0.525 = n × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n = (0.9357 × 0.525) / (0.0821 × 298)
n = 0.02 mole
Finally, we shall determine the mass of the hydrogen gas produced. Details below:
Molar mass of hydrogen gas, H₂ = 2 g/mol Mole of hydrogen gas, H₂ = 0.02 moleMass of hydrogen gas, H₂ = ?Mole = mass / molar mass
0.02 = Mass of H₂ / 2
Cross multiply
Mass of H₂ = 0.02 × 2
Mass of hydrogen gas, H₂ = 0.04 grams
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Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The Correct answer is option 3
Step by Syep Explanation:
4Fe+3O2---->rust
formula for rust----->Fe2O3
4Fe+3O2---->Fe2O3
Balancing the Chemical Equation
both the reactant and product side
we have that;
4Fe+3O2------->2FeO3
the equation is Chemically Balanced
therefore 4Fe+3O2------->2×rust
Answer:
2Fe₂O₃ (Option 3)Explanation:
Given that,
4Fe + 3O2 → rust.Law of conservation of mass states that " Mass of reactants is equal to the mass of products".
Also we know that In a balanced equation the total number of atoms in the reactants equals the total number of atoms in the product.
We are given with 4Fe + 3O₂ i.e the reactant.
First Let's calculate the number of atoms in the reactant.
No. of atoms in Fe = 4 No. of atoms in O = 3 × 2 = 6Now, Let's find the product .
Also, We can see 2Fe₂O₃ (Product)
No. of atoms in Fe = 2 × 2 = 4 No. of atoms in O = 2 × 3 = 6.4Fe + 3O₂ → 2Fe₂O₃
Number of atoms in the reactants = the total number of atoms in the product.
Therefore, 2Fe₂O₃ (Option 3) will the required answer .
NaOH is the limiting reactant, producing
2.0 mol Na3PO4. What mass of
Na3PO4 forms during the reaction?
Na3PO4: 164 g/mol
[?] g Na3PO4
Report your answer to two significant figures.
g Na PO
4
Enter
The mass of Na₃PO₄ formed during the reaction is 328 g.
The balanced chemical equation for the reaction is:
[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]
From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.
Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:
3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4
Solving for x, we get:
x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH
So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.
To find the mass of Na₃PO₄ produced, we can use its molar mass:
mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g
Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.
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A 1.5 M solution of HCl has 145 g of HCl dissolved, what is the volume of the solution?
The volume of the 1.5M solution of HCl solution that has 145g of mass is 2.65L.
How to calculate volume?The volume of a solution can be calculated by dividing the number of moles by its molar concentration as follows;
Volume = no of moles ÷ molarity
According to this question, a 1.5M solution of HCl has 145g of mass. The number of moles can be calculated as follows:
no of moles = 145g ÷ 36.5g/mol = 3.973 moles
volume of HCl solution = 3.973mol ÷ 1.5M
volume of HCl = 2.65L
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A rock is placed on a scale and gives a reading of 76.89 grams. The rock is then placed in a graduated cylinder with 63.12 mL of water, the water rises to a volume of 73.54mL What is the density of the rock? (you answer must have a total of 2 decimals)
Which best explains why individual chlorine atoms form covalent bonds with each other?
A. to increase their mass
B. to become more reactive
C. to maintain positive charges in their nuclei
D. to have eight electrons in their valence shells
The correct answer is D. to have eight electrons in their valence shells.
What is a covalent bond?A covalent bond is a chemical relationship that requires the sharing of electrons between atoms to generate electron pairs. These electron couples are known as bonding pairs or sharing pairs.
Covalent bonding is the steady balance of attractive and repulsive forces between atoms when they share electrons.
Covalent Bond Types
A single ionic bond.Covalent bonds with two protons.The triple covalent bond.Learn more about Covalent Bond here:
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If an aqueous solution is 5.321m, which of the following statements is incorrect?
A) Freezing point of solution will lower by 10 C
B) Boiling point of solution will increase by 2.72 C
C) Boiling point of solution will be 100 C
D) Osmotic pressure of solution will be higher than water
Boiling point of solution will be 100 C. The incorrect statement is C)
What is aqueous solution ?An aqueous solution is one in which water serves as the solvent. One or more substances are dissolved in water to create such a solution, and the water molecules surround and separate the individual solute particles to create a homogeneous mixture.
Therefore, A solvent's boiling point and freezing point change when a solute is dissolved in it, respectively. Boiling point elevation and freezing point depression are two terms used to describe this occurrence. The concentration of the solute determines how much of an impact it has.
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A solution that is neutral has a pH of:
0
14
10
1
7
Pleas help thanks!!!!!!!!!!!!!!!!!!!!
The number of molecules of BF₃ present in 2 grams of BF₃ is 1.776×10²² molecules (1st option)
How do i determine the number of molecules of BF₃?
We'll begin by calculating the number of mole of 2 grams of BF₃. Details below:
Mass of BF₃ = 2 grams Molar mass of BF₃ = 67.81 g/molMole of BF₃ =?Mole = mass / molar mass
Mole of BF₃ = 2 / 67.81
Mole of BF₃ = 0.02949 mole
Finally, we shall determine the number of molecules of BF₃. This is shown below:
Avogadro's hypothesis suggest that:
1 mole of BF₃ = 6.022×10²³ molecules
Therefore,
0.02949 mole of BF₃ = 0.02949 × 6.02×10²³
0.02949 mole of BF₃ = 1.776×10²² molecules
Thus, the number of molecules of BF₃ is 1.776×10²² molecules (1st option)
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A solution contains 3.5 mol NaCl and 4.2 mol MgCl₂. How many equivalents of chloride ion are present?
There are 15.4 equivalents of chloride ion present in the solution
To calculate the number of equivalents per mole of chloride ionWe need to multiply the total number of moles of chloride ion in the solution by the number of equivalents.
The molar mass of NaCl is 58.44 g/mol, so 3.5 mol of NaCl contains :
3.5 mol NaCl x 2 mol Cl⁻/1 mol NaCl = 7 mol Cl⁻
Similarly, the molar mass of MgCl₂ is 95.21 g/mol, so 4.2 mol of MgCl₂ contains:
4.2 mol MgCl₂ x 2 mol Cl⁻/1 mol MgCl₂ = 8.4 mol Cl⁻
Therefore, the total number of moles of chloride ion in the solution is:
7 mol Cl⁻ + 8.4 mol Cl⁻ = 15.4 mol Cl⁻
By dividing the total number of moles by the number of equivalents per mole, we can finally determine how many equivalents of the chloride ion there are. There is one equivalent of the chloride ion per mole since it has a valency of -1.
15.4 mol Cl⁻ x 1 eq/mol = 15.4 eq
So there are 15.4 equivalents of chloride ion present in the solution.
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A student conducted three trails to determine the concentration of an unknown concentration of HCI. In the first trail the calculated concentration was 0.104 M, the second was 0.113 M and the third trail was 0.108 M. What is the percent difference between the first two trials and based on the lab procedures procedures guidelines what would the average molarity be?
The percent difference between the first two trials is 8.3% and final outcome would be an average molarity of 0.108 M.
How to calculate percent difference and average molarity?To calculate the percent difference between the first two trials, use the formula:
% Difference = |(Value 1 - Value 2) / ((Value 1 + Value 2) / 2)| x 100%
% Difference = |(0.104 M - 0.113 M) / ((0.104 M + 0.113 M) / 2)| x 100%
% Difference = |-0.009 M / 0.1085 M| x 100%
% Difference = 8.3%
The percent difference between the first two trials is 8.3%.
To find the average molarity, add the three calculated concentrations together and divide by the number of trials:
Average Molarity = (0.104 M + 0.113 M + 0.108 M) / 3
Average Molarity = 0.108 M
Based on the lab procedures guidelines, the average molarity would be the most accurate representation of the unknown concentration of HCI. Therefore, the average molarity of 0.108 M would be the final result.
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